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Author: Tinku Tara

0-pi-4-cos-3-2x-cos-x-dx-

Question Number 137345 by liberty last updated on 01/Apr/21 $$\ell\:=\:\int_{\mathrm{0}} ^{\:\pi/\mathrm{4}} \sqrt{\mathrm{cos}\:^{\mathrm{3}} \left(\mathrm{2}{x}\right)}\:\mathrm{cos}\:{x}\:{dx}\:=?\: \\ $$ Answered by MJS_new last updated on 01/Apr/21 $$\int\mathrm{cos}^{\mathrm{3}/\mathrm{2}} \:\mathrm{2}{x}\:\mathrm{cos}\:{x}\:{dx}= \\…

1-1-pi-2-1-pi-1-2-1-pi-2-2-1-1-1-pi-1-2-1-pi-2-2-1-1-pi-Prove-or-disprove-

Question Number 137347 by Dwaipayan Shikari last updated on 01/Apr/21 $$\frac{\mathrm{1}}{\mathrm{1}+\frac{\pi^{\mathrm{2}} }{\mathrm{1}+\frac{\left(\pi+\mathrm{1}\right)^{\mathrm{2}} }{\mathrm{1}+\frac{\left(\pi+\mathrm{2}\right)^{\mathrm{2}} }{\mathrm{1}+…}}}}+\frac{\mathrm{1}}{\mathrm{1}+\frac{\left(\pi+\mathrm{1}\right)^{\mathrm{2}} }{\mathrm{1}+\frac{\left(\pi+\mathrm{2}\right)^{\mathrm{2}} }{\mathrm{1}+…}}}=\frac{\mathrm{1}}{\pi}\:\: \\ $$$$\boldsymbol{\mathrm{Prove}}\:\boldsymbol{\mathrm{or}}\:\boldsymbol{\mathrm{disprove}} \\ $$ Answered by MJS_new last updated…

Question-71809

Question Number 71809 by TawaTawa last updated on 20/Oct/19 Answered by tw000001 last updated on 21/Oct/19 $$\mathrm{I}\:\mathrm{have}\:\mathrm{showed}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{on}\:\mathrm{No}.\mathrm{71776}. \\ $$ Terms of Service Privacy Policy Contact:…

Question-71806

Question Number 71806 by ahmadshahhimat775@gmail.com last updated on 20/Oct/19 Answered by MJS last updated on 20/Oct/19 $$\left(−\mathrm{2}\right)^{\sqrt{\mathrm{2}}} =\left(\mathrm{2e}^{\mathrm{i}\pi} \right)^{\sqrt{\mathrm{2}}} =\mathrm{2}^{\sqrt{\mathrm{2}}} \mathrm{e}^{\mathrm{i}\pi\sqrt{\mathrm{2}}} = \\ $$$$=\mathrm{2}^{\sqrt{\mathrm{2}}} \mathrm{cos}\:\pi\sqrt{\mathrm{2}}\:+\mathrm{2}^{\sqrt{\mathrm{2}}}…