Question Number 5479 by keagan j last updated on 15/May/16 $${cos}\mathrm{180}.{tan}\left(−{x}\right) \\ $$ Answered by Rasheed Soomro last updated on 15/May/16 $${cos}\:\mathrm{180}=−\mathrm{1},{tan}\left(−{x}\right)=−{tan}\left({x}\right)\:\left[{tan}\:\:{is}\:{odd}\:{function}\right] \\ $$$$\therefore\:{cos}\mathrm{180}.{tan}\left(−{x}\right)=\left(−\mathrm{1}\right)\left(−{tan}\:{x}\right) \\…
Question Number 136551 by Tinku Tara last updated on 23/Mar/21 $$\mathrm{Google}\:\mathrm{released}\:\mathrm{an}\:\mathrm{update}\:\mathrm{to}\:\mathrm{android} \\ $$$$\mathrm{webview}\:\mathrm{which}\:\mathrm{is}\:\mathrm{causing}\:\mathrm{multiple} \\ $$$$\mathrm{android}\:\mathrm{app}\:\mathrm{to}\:\mathrm{crash}.\:\mathrm{Please} \\ $$$$\mathrm{search}\:\mathrm{internet}\:\mathrm{for}\:\mathrm{workaround} \\ $$$$\mathrm{for}\:\mathrm{your}\:\mathrm{device}. \\ $$$$\boldsymbol{\mathrm{This}}\:\boldsymbol{\mathrm{problem}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{not}}\:\boldsymbol{\mathrm{caused}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{Tinkutara}} \\ $$$$\boldsymbol{\mathrm{Equation}}\:\boldsymbol{\mathrm{Editor}}. \\ $$$$\mathrm{Please}\:\mathrm{also}\:\mathrm{note}\:\mathrm{no}\:\mathrm{android}\:\mathrm{app}…
Question Number 5476 by love math last updated on 15/May/16 $$\int\frac{\mathrm{2}^{{x}} \mathrm{3}^{{x}} }{\mathrm{9}^{{x}} −\mathrm{4}^{{x}} }{dx} \\ $$$$ \\ $$$$\int\frac{{dx}}{\left(\mathrm{1}+{x}\right)\sqrt{{x}}} \\ $$ Answered by Yozzii last…
Question Number 136541 by mr W last updated on 23/Mar/21 $${to}\:{Tinku}\:\:{Tara}\:{sir}: \\ $$$${since}\:{update}\:{to}\:{version}\:\mathrm{2}.\mathrm{262}\:{i}'{m} \\ $$$${encountering}\:{a}\:{big}\:{problem}: \\ $$$${after}\:{some}\:{time}\:{of}\:{use}\:{the}\:{app}\: \\ $$$${crashes},\:{then}\:{i}\:{can}'{t}\:{start}\:{the}\:{app} \\ $$$${any}\:{more},\:{that}\:{means}\:{after}\:{displaying} \\ $$$${the}\:{welcome}\:{screen}\:{the}\:{app}\:{crashes}. \\ $$$${besides}\:{some}\:{other}\:{apps},\:{e}.{g}.\:{google},…
Question Number 136537 by Jamshidbek last updated on 23/Mar/21 Answered by Olaf last updated on 23/Mar/21 $${a}+\frac{\mathrm{1}}{{a}}\:=\:−\mathrm{1} \\ $$$${a}^{\mathrm{2}} +{a}+\mathrm{1}\:=\:\mathrm{0} \\ $$$${a}\:=\:\frac{−\mathrm{1}\pm{i}\sqrt{\mathrm{3}}}{\mathrm{2}}\:=\:{e}^{{i}\frac{\mathrm{2}\pi}{\mathrm{3}}} \mathrm{or}\:{e}^{{i}\frac{\mathrm{4}\pi}{\mathrm{3}}} \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+\mathrm{4}+\mathrm{5}+\mathrm{6}+\mathrm{7}+\mathrm{8}+\mathrm{9}+\mathrm{1}+\mathrm{0}+\mathrm{1}+\mathrm{1}…
Question Number 5467 by 3 last updated on 15/May/16 $$\boxtimes\mathrm{7}{n} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 5466 by 3 last updated on 15/May/16 $$\sqrt{\mathrm{8}} \\ $$ Answered by FilupSmith last updated on 15/May/16 $$\sqrt{\mathrm{8}}=\sqrt{\mathrm{4}×\mathrm{2}} \\ $$$$=\sqrt{\mathrm{4}}\sqrt{\mathrm{2}} \\ $$$$\therefore\sqrt{\mathrm{8}}=\mathrm{2}\sqrt{\mathrm{2}} \\…
Question Number 71000 by Maclaurin Stickker last updated on 10/Oct/19 $${Where}\:{f}\left({x}\right)=\frac{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{x}−\mathrm{1}}\:{defined}\:{in}\: \\ $$$$\mathbb{R}−\left\{\frac{\mathrm{1}}{\mathrm{2}}\right\},\:{determine}\:\underset{{x}\rightarrow\frac{\mathrm{1}}{\mathrm{2}}} {\mathrm{lim}}{f}\left({x}\right). \\ $$ Commented by mathmax by abdo last updated on…
Question Number 5465 by 3 last updated on 15/May/16 $${i} \\ $$ Answered by FilupSmith last updated on 15/May/16 $${i}=\sqrt{−\mathrm{1}} \\ $$ Terms of Service…