Menu Close

Author: Tinku Tara

Question-5189

Question Number 5189 by sanusihammed last updated on 28/Apr/16 Commented by FilupSmith last updated on 28/Apr/16 $${Q}\mathrm{1} \\ $$$${V}={IR} \\ $$$${I}=\frac{{V}}{{R}}\:\Rightarrow\:{I}=\frac{\mathrm{12}}{\mathrm{16}+\mathrm{8}} \\ $$$${I}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$…

log-x-2-10-3x-lt-2-

Question Number 136256 by EDWIN88 last updated on 20/Mar/21 $$\mathrm{log}\:_{\left(\mathrm{x}−\mathrm{2}\right)} \left(\mathrm{10}−\mathrm{3x}\right)\:<\:\mathrm{2} \\ $$ Answered by liberty last updated on 20/Mar/21 $$\left(\mathrm{1}\right)\:\mathrm{10}−\mathrm{3}{x}\:>\:\mathrm{0}\:;\:\mathrm{3}{x}−\mathrm{10}<\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:{x}\:<\:\frac{\mathrm{10}}{\mathrm{3}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{log}\:_{\left({x}−\mathrm{2}\right)}…

Given-2f-x-f-1-x-6x-3-x-then-1-2-f-x-dx-

Question Number 136259 by liberty last updated on 20/Mar/21 $${Given}\:\mathrm{2}{f}\left({x}\right)+{f}\left(\frac{\mathrm{1}}{{x}}\right)=\mathrm{6}{x}+\frac{\mathrm{3}}{{x}} \\ $$$${then}\:\int_{\mathrm{1}} ^{\:\mathrm{2}} {f}\left({x}\right){dx}=? \\ $$ Answered by EDWIN88 last updated on 20/Mar/21 $$\mathrm{Replacing}\:\mathrm{x}\:\mathrm{by}\:\frac{\mathrm{1}}{\mathrm{x}}\:\mathrm{gives} \\…

lim-x-2a-x-2a-x-2a-x-2-4a-2-where-a-gt-0-

Question Number 136258 by EDWIN88 last updated on 20/Mar/21 $$\underset{{x}\rightarrow\mathrm{2a}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{x}−\mathrm{2a}}\:+\:\sqrt{\mathrm{x}}\:−\sqrt{\mathrm{2a}}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{4a}^{\mathrm{2}} }}\:=?\:\mathrm{where}\:\mathrm{a}>\mathrm{0} \\ $$ Answered by liberty last updated on 20/Mar/21 $$\:{L}'{H}\ddot {{o}pital}\: \\…

sin-101x-sin-99-x-dx-

Question Number 70719 by oyemi kemewari last updated on 07/Oct/19 $$\int\mathrm{sin}\:\left(\mathrm{101x}\right)\mathrm{sin}\:^{\mathrm{99}} \mathrm{x}\:\mathrm{dx} \\ $$ Answered by mind is power last updated on 07/Oct/19 $${sin}\left(\mathrm{101}{x}\right)={sin}\left(\mathrm{100}{x}\right){cos}\left({x}\right)+{sin}\left({x}\right){cos}\left(\mathrm{100}{x}\right) \\…