Question Number 223459 by mr W last updated on 26/Jul/25 $${solve}\:{for}\:{x}\in{R} \\ $$$$\sqrt{\mathrm{25}−\mathrm{10}{x}−{x}^{\mathrm{2}} }+\sqrt{\mathrm{15}−{x}^{\mathrm{2}} }=\mathrm{2}\sqrt{\mathrm{5}} \\ $$ Answered by fantastic last updated on 26/Jul/25 $$\sqrt{\mathrm{25}−\mathrm{10}{x}−{x}^{\mathrm{2}}…
Question Number 223449 by ajfour last updated on 25/Jul/25 Answered by ajfour last updated on 26/Jul/25 $$\:\:\:\sqrt{\mathrm{1}−\theta^{\mathrm{2}} }=\frac{\mathrm{sin}\:\left(\phi−\theta\right)}{\mathrm{sin}\:\phi} \\ $$$${Wow}!\:\:\:\:\:\:{arc}\:{CD}=\:{line}\:{AB} \\ $$$$ \\ $$$$\bullet\:{Find}\:{CT}/{AO}={t}/{R}\:\:{in}\:{terms}\:{of}\:\theta. \\…
Question Number 223429 by klipto last updated on 25/Jul/25 $$…. \\ $$ Commented by klipto last updated on 25/Jul/25 Answered by Rasheed.Sindhi last updated on…
Question Number 223424 by behi834171 last updated on 25/Jul/25 Commented by fantastic last updated on 25/Jul/25 $${GIGANTIC}\:{when}\:{using}\:{normal}\:{method} \\ $$ Commented by Ghisom last updated on…
Question Number 223405 by behi834171 last updated on 24/Jul/25 Answered by fantastic last updated on 24/Jul/25 $$\sqrt[{\mathrm{3}}]{{x}+\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\left(\sqrt[{\mathrm{3}}]{{x}+\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}}\right)^{\mathrm{3}} =\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\therefore{x}+\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$$${let}\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}={u} \\…
Question Number 223401 by wewji12 last updated on 24/Jul/25 Commented by MathematicalUser2357 last updated on 24/Jul/25 대학전쟁에서 나온 문제라면 개추 Answered by wewji12 last updated on 24/Jul/25 $$\underset{{n}\rightarrow\infty}…
Question Number 223403 by Rojarani last updated on 24/Jul/25 Commented by mr W last updated on 24/Jul/25 $${should}\:{be}\:\:…=+\:\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{37}}−\mathrm{10}} \\ $$ Answered by mr W last…
Question Number 223412 by nECxx2 last updated on 24/Jul/25 $${Good}\:{day}\:{great}\:{problem}\:{solvers}. \\ $$$${Please}\:{I}\:{need}\:{links}\:{to}\:{resources}\:{helpful} \\ $$$${for}\:{preparations}\:{for}\:{Olympiad}\:{mathematics} \\ $$$${especially}\:{books}\:{and}\:{video}\:{recommendations}. \\ $$$${I}'{ll}\:{be}\:{grateful}\:{to}\:{get}\:{our}\:{responses}. \\ $$ Commented by fantastic last updated…
Question Number 223414 by BaliramKumar last updated on 24/Jul/25 $${is}\:{it}\:{possible}\:{to}\:{prove}\:{that}\:{mn}\left({m}+{n}\right)\left({m}−{n}\right)\: \\ $$$${divisible}\:{by}\:\mathrm{6}\:{always}\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by mehdee7396 last updated on 24/Jul/25 $${let}\:\:\:{d}={mn}\left({m}+{n}\right)\left({m}−{n}\right) \\ $$$${case}\mathrm{1} \\…
Question Number 223410 by STUDENT12345 last updated on 24/Jul/25 Terms of Service Privacy Policy Contact: info@tinkutara.com