Question Number 202721 by Rasheed.Sindhi last updated on 01/Jan/24 $$\:\:\:\begin{array}{|c|}{\underset{\mathcal{HAPPY}\:\mathcal{NEW}\:\mathcal{YEAR}!} {\mathrm{2}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} +\centerdot\centerdot\centerdot\centerdot\centerdot+\mathrm{22}^{\mathrm{2}} =\mathrm{2024}}}\\\hline\end{array} \\ $$$$\begin{array}{|c|}{\:\:\:\mathrm{May}\:\mathrm{2024}\:\mathrm{be}\:\begin{cases}{\mathrm{war}-\mathrm{free}!}\\{\&}\\{{peaceful}!}\end{cases}\:\:\:}\\\hline\end{array} \\ $$$$ \\ $$ Terms of Service Privacy…
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Question Number 202684 by ajfour last updated on 31/Dec/23 Answered by mr W last updated on 02/Jan/24 $$\mathrm{cos}\:\alpha=\frac{{s}^{\mathrm{2}} +{q}^{\mathrm{2}} −\left(\frac{{s}}{\mathrm{2}}\right)^{\mathrm{2}} }{\mathrm{2}{sq}}=\frac{\mathrm{3}{s}^{\mathrm{2}} +\mathrm{4}{q}^{\mathrm{2}} }{\mathrm{8}{sq}} \\ $$$$\mathrm{cos}\:\beta=\frac{{p}}{\mathrm{2}{s}}=\frac{{s}−{q}}{\mathrm{2}{s}}=\mathrm{sin}\:\alpha…
Question Number 202653 by liuxinnan last updated on 31/Dec/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 202648 by liuxinnan last updated on 31/Dec/23 $${how}\:{to}\:{use}\:{the}\:{fewest}\:“\mathrm{2}''\:{to}\:{make}\:\mathrm{2024} \\ $$$${you}\:{only}\:{can}\:{use}\:“\mathrm{2}''\:{and}\:−\:+\:×\:/\:\left(\:\right)\:!\:\:\hat {\:}\:… \\ $$$${as}\:{the}\:{following} \\ $$$$\:\:\:\:\:\:\mathrm{2}×\mathrm{2}×\mathrm{2}\left(\left(\mathrm{2}×\mathrm{2}\right)!−\mathrm{2}/\mathrm{2}\right)\left(\mathrm{2}×\left(\mathrm{2}+\mathrm{2}/\mathrm{2}\right)!−\mathrm{2}/\mathrm{2}\right)=\mathrm{2024} \\ $$$${totally}\:{use}\:{thirteen}\:“\:\mathrm{2}'' \\ $$ Commented by Frix last…
Question Number 202650 by liuxinnan last updated on 31/Dec/23 Answered by liuxinnan last updated on 01/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 202651 by hardmath last updated on 31/Dec/23 Commented by Frix last updated on 31/Dec/23 $${y}=\frac{\mathrm{3cos}\:{x}\:+\mathrm{sin}\:{x}}{\mathrm{10}}+{c}_{\mathrm{1}} \mathrm{e}^{\mathrm{2}{x}} +{c}_{\mathrm{2}} \mathrm{e}^{{x}} \\ $$ Answered by Mathspace…
Question Number 202677 by BaliramKumar last updated on 31/Dec/23 $$ \\ $$$$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\mathrm{2023}^{\mathrm{2024}} \:\&\:{x},\:{y}\:\in\:\boldsymbol{\mathrm{N}} \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{set}\left\{{x},\:{y}\right\} \\ $$ Answered by AST last updated on…
Question Number 202679 by Mingma last updated on 31/Dec/23 Answered by esmaeil last updated on 31/Dec/23 $$\curvearrowright\rightarrow<_{{hex}} =\mathrm{120}\rightarrow \\ $$$${tan}\mathrm{30}=\frac{{h}}{\frac{{a}}{\mathrm{2}}}\rightarrow{h}=\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}} \\ $$$$\mathrm{2}\left(\frac{{a}}{\mathrm{2}}×\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}}×\frac{\mathrm{1}}{\mathrm{2}}\right)=\mathrm{43}=\left({S}_{{blue}} +{S}_{{pink}} \right)\rightarrow \\…
Question Number 202672 by BaliramKumar last updated on 31/Dec/23 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{divisors}\:\mathrm{of}\:\mathrm{24}\:\mathrm{is}\:\mathrm{60}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{divisors}\:\mathrm{of}\:\mathrm{24}×\mathrm{79}. \\ $$ Answered by a.lgnaoui last updated on 31/Dec/23 $$\mathrm{60} \\ $$ Commented…