Question Number 68019 by mathmax by abdo last updated on 03/Sep/19 $${let}\:{F}\left({x}\right)\:=\int_{{x}} ^{{x}^{\mathrm{2}} +\mathrm{1}} {e}^{−\mathrm{2}{t}} {sin}\left({xt}\right){dt} \\ $$$${determine}\:{F}\:^{'} \left({x}\right)\:{and}\:{calculate}\:{lim}_{{x}\rightarrow\mathrm{0}} \:{F}\left({x}\right). \\ $$$$ \\ $$ Commented…
Question Number 2481 by Syaka last updated on 21/Nov/15 $$\frac{\mathrm{2014}}{\mathrm{2013}}\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\frac{\mathrm{2012}}{\mathrm{2011}}\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\:\frac{\mathrm{2012}}{\mathrm{2011}}\:\ast\:\frac{\mathrm{2010}}{\mathrm{2009}}\:+\:\centerdot\centerdot\centerdot\centerdot\:+\:\frac{\mathrm{2014}}{\mathrm{2013}}\:\ast\:\frac{\mathrm{2012}}{\mathrm{2011}}\:\ast\:\frac{\mathrm{2010}}{\mathrm{2009}}\:\ast\:\frac{\mathrm{2008}}{\mathrm{2007}\:}\ast\centerdot\centerdot\centerdot\ast\frac{\mathrm{4}}{\mathrm{3}}\ast\frac{\mathrm{2}}{\mathrm{1}}\:−\:\mathrm{1}\:=\:\:\:\:? \\ $$ Answered by Filup last updated on 21/Nov/15 $$\mathrm{if}\:\mathrm{by}\:''\ast''\:\mathrm{you}\:\mathrm{mean}\:''×'' \\ $$$${in}\:{form}\:\left({k}=\mathrm{2014}\right): \\ $$$$ \\…
Question Number 2478 by Syaka last updated on 21/Nov/15 $${limit}\:{x}\:\rightarrow\:\infty \\ $$$$\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{{x}}\right)^{{x}\:+\:\mathrm{2}} \:=\:? \\ $$ Commented by John_Haha last updated on 21/Nov/15 $${e} \\ $$…
Question Number 133545 by leena12345 last updated on 22/Feb/21 Commented by leena12345 last updated on 23/Feb/21 $${help} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 133541 by bemath last updated on 22/Feb/21 $$\underset{\mathrm{0}} {\overset{\mathrm{3}} {\int}}\sqrt{\mathrm{9}−\mathrm{x}^{\mathrm{2}} }\:\mathrm{dx}\:=? \\ $$$$\left(\mathrm{a}\right)\mathrm{13}.\mathrm{5}\:\:\:\:\:\:\left(\mathrm{b}\right)\mathrm{21}\:\:\:\:\:\:\left(\mathrm{c}\right)\mathrm{22}.\mathrm{5} \\ $$$$\left(\mathrm{d}\right)\mathrm{1}.\mathrm{8}\:\:\:\:\:\:\:\:\:\left(\mathrm{e}\right)\:\mathrm{30} \\ $$ Commented by MJS_new last updated on…
Question Number 133540 by bemath last updated on 22/Feb/21 $$\int\:\left(\mathrm{cosec}\:\mathrm{x}\right)^{\mathrm{11456}} \:\left(\mathrm{cot}\:\mathrm{x}\right)^{\mathrm{11456}} \:\mathrm{dx}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 133542 by help last updated on 22/Feb/21 Commented by help last updated on 22/Feb/21 $${x}^{\mathrm{3}{n}+\mathrm{2}} +{x}+\mathrm{1}\:\:{is}\:{divisible}\:{by}\:{x}^{\mathrm{2}} +{x}+\mathrm{1} \\ $$$${correct}\:{question} \\ $$ Terms of…
Question Number 133537 by mathmax by abdo last updated on 22/Feb/21 $$\mathrm{calculate}\:\int_{\mathrm{1}} ^{\infty} \:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} +\mathrm{x}+\mathrm{1}\right)^{\mathrm{9}} } \\ $$ Answered by Ñï= last updated on 23/Feb/21…
Question Number 133536 by mathmax by abdo last updated on 22/Feb/21 $$\mathrm{find}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{u}_{\mathrm{n}} \mathrm{with}\:\mathrm{verify}\:\mathrm{u}_{\mathrm{n}} +\mathrm{u}_{\mathrm{n}+\mathrm{1}} =\frac{\left(−\mathrm{1}\right)^{\mathrm{n}} }{\:\sqrt{\mathrm{n}}}\:\:\forall\mathrm{n}\geqslant\mathrm{1} \\ $$$$\mathrm{determine}\:\mathrm{a}\:\mathrm{equivalent}\:\mathrm{of}\:\:\mathrm{u}_{\mathrm{n}} \\ $$$$\mathrm{is}\:\mathrm{u}_{\mathrm{n}} \mathrm{convergent}? \\ $$ Terms of…
Question Number 2466 by prakash jain last updated on 20/Nov/15 $$\sqrt{−\frac{\mathrm{1}}{\mathrm{5}}\:}−\frac{\mathrm{1}}{\:\sqrt{−\mathrm{5}}}=? \\ $$ Answered by Yozzi last updated on 20/Nov/15 $$\sqrt{\frac{\mathrm{1}}{−\mathrm{5}}}−\frac{\mathrm{1}}{\:\sqrt{−\mathrm{5}}}={i}\sqrt{\frac{\mathrm{1}}{\mathrm{5}}}−\frac{\mathrm{1}}{{i}\sqrt{\mathrm{5}}} \\ $$$$={i}\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}}+\frac{{i}}{\:\sqrt{\mathrm{5}}}=\mathrm{2}\frac{{i}}{\:\sqrt{\mathrm{5}}} \\ $$$$\frac{\mathrm{1}}{\:\sqrt{−\mathrm{5}}}=\frac{\sqrt{\mathrm{1}}}{\:\sqrt{−\mathrm{5}}}=\sqrt{\frac{\mathrm{1}}{−\mathrm{5}}}\Rightarrow\sqrt{\frac{\mathrm{1}}{−\mathrm{5}}}−\frac{\mathrm{1}}{\:\sqrt{−\mathrm{5}}}\overset{?}…