Question Number 1809 by alib last updated on 04/Oct/15 $$\mathrm{tan}\:{a}+\mathrm{cot}\:{a}+\mathrm{tan}\:\mathrm{3}{a}+\mathrm{cot}\:\mathrm{3}{a}=\frac{\mathrm{8cos}\:^{\mathrm{2}} \mathrm{2}{a}}{\mathrm{sin}\:\mathrm{6}{a}} \\ $$$$ \\ $$ Commented by alib last updated on 04/Oct/15 $$\boldsymbol{{prove}} \\ $$…
Question Number 67345 by Aditya789 last updated on 26/Aug/19 $$\mathrm{3}{sinx}+\mathrm{5}{cosx}=\mathrm{5}\:{then}\:{prove}\:{that}\: \\ $$$$\mathrm{5}{sinx}−\mathrm{3}{cox}=\:+\mathrm{3} \\ $$ Answered by $@ty@m123 last updated on 26/Aug/19 $$\frac{\mathrm{3}}{\mathrm{5}}\mathrm{sin}\:{x}+\mathrm{cos}\:{x}=\mathrm{1} \\ $$$$\frac{\mathrm{1}−\mathrm{cos}\:{x}}{\mathrm{sin}\:{x}}=\frac{\mathrm{3}}{\mathrm{5}} \\…
Question Number 1808 by alib last updated on 04/Oct/15 $$\boldsymbol{\mathcal{P}}{rove}\:\:\mathrm{sin}\:\left({a}\right)+\mathrm{sin}\:\left({a}+\frac{\mathrm{14}\pi}{\mathrm{3}}\right)+\mathrm{sin}\:\left({a}−\frac{\mathrm{8}\pi}{\mathrm{3}}\right)=\mathrm{0}/ \\ $$$$ \\ $$ Answered by 112358 last updated on 05/Oct/15 $${Using}\:{the}\:{compound}\:{angle}\:{formula} \\ $$$${sin}\left({x}\pm{y}\right)={sinxcosy}\pm{cosxsiny}\:{we}\:{get} \\…
Question Number 132877 by mnjuly1970 last updated on 17/Feb/21 $$\:\:\:\:\:\:\:\:\:\:\:\:\:….\:{nice}\:\:{calculus}… \\ $$$$\:\:\:{prove}\:{that}\:: \\ $$$$\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\infty} \frac{{sin}\left({x}\right).{log}^{\mathrm{2}} \left({x}\right)}{{x}} \\ $$$$\:\:\:\:\:\:\:=\frac{\pi}{\mathrm{24}}\left(\mathrm{12}\gamma^{\:\mathrm{2}} +\pi^{\mathrm{2}} \right)\:….. \\ $$ Answered by…
Question Number 67342 by mathmax by abdo last updated on 26/Aug/19 $${find}\:{the}\:{value}\:{of}\:\int_{−\infty} ^{\infty} \:\:\:\frac{{sin}\left(\mathrm{2}{x}^{\mathrm{2}} \right)}{\left({x}^{\mathrm{2}} −{x}\:+\mathrm{3}\right)^{\mathrm{3}} }{dx} \\ $$ Commented by mathmax by abdo last…
Question Number 132876 by mnjuly1970 last updated on 17/Feb/21 Commented by Dwaipayan Shikari last updated on 17/Feb/21 $$\phi'\left(\frac{\mathrm{1}}{\mathrm{2}}\right)\:\:\:\phi\left({x}\right){is}\:{defined}\:{in}\:{Q}\mathrm{132877} \\ $$ Terms of Service Privacy Policy…
Question Number 1805 by ình Plus 001 last updated on 03/Oct/15 $${WTF} \\ $$ Answered by 123456 last updated on 03/Oct/15 $$\mathrm{Dolphins} \\ $$$$ \\…
Question Number 132878 by aurpeyz last updated on 17/Feb/21 $${is}\:{the}\:{surface}\:{of}\:{a}\:{mirror}\:{refractive} \\ $$$${or}\:{reflective}? \\ $$ Commented by Dwaipayan Shikari last updated on 17/Feb/21 $${Generally}\:{reflective}\:..\:{but}\:{sometimes}\:{refractive}.. \\ $$…
Question Number 1804 by 123456 last updated on 03/Oct/15 $$\left(\mathrm{1}−{u}\right)\frac{\partial{u}}{\partial{t}}={u}\frac{\partial{v}}{\partial{t}} \\ $$$$\left(\mathrm{1}−{v}\right)\frac{\partial{v}}{\partial{t}}={v}\frac{\partial{u}}{\partial{t}} \\ $$$$\frac{\partial}{\partial{t}}\left({uv}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 132873 by aurpeyz last updated on 17/Feb/21 $${is}\:{linear}\:{magnification}\:{positive}\:{or}\: \\ $$$${negative}\:{for}\:{a}\:{convex}\:{mirror}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com