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Question Number 132827 by victoras last updated on 16/Feb/21 Commented by mr W last updated on 16/Feb/21 $${impossible}! \\ $$ Commented by Dwaipayan Shikari last…
Question Number 132826 by mohammad17 last updated on 16/Feb/21 $${prove}\:{Log}\left({z}_{\mathrm{1}} {z}_{\mathrm{2}} \right)={Log}\left({z}_{\mathrm{1}} \right)+{Log}\left({z}_{\mathrm{2}} \right) \\ $$$${if}\:−\pi<{Argz}_{\mathrm{1}} +{Argz}_{\mathrm{2}} <\pi \\ $$$${hwo}\:{can}\:{solve}\:{this} \\ $$ Commented by guyyy…
Question Number 1752 by Rasheed Ahmad last updated on 14/Sep/15 $${Prove}\:{that}: \\ $$$$\left(−{x}\right)\left(−{y}\right)={xy} \\ $$ Commented by 123456 last updated on 15/Sep/15 $${ax}+{bx}=\left({a}+{b}\right){x} \\ $$$$−{x}=−\mathrm{1}×{x}…
Question Number 1750 by Lissy=ž=ždd
Question Number 1748 by Rasheed Ahmad last updated on 14/Sep/15 $${Why}\:\:\:{a}^{\mathrm{0}} =\mathrm{1}\:{and}\:\:{a}^{−\mathrm{3}} =\frac{\mathrm{1}}{{a}^{\mathrm{3}} } \\ $$ Answered by 123456 last updated on 14/Sep/15 $$\frac{{a}^{{x}} }{{a}^{{y}}…
Question Number 67281 by Tony Lin last updated on 25/Aug/19 Commented by mr W last updated on 25/Aug/19 $${I}\:{get}\:\mathrm{3}{C}_{\mathrm{2}} ^{\mathrm{5}} +\mathrm{3}{C}_{\mathrm{2}} ^{\mathrm{5}} +\mathrm{12}=\mathrm{72} \\ $$…
Question Number 1744 by Rasheed Ahmad last updated on 13/Sep/15 $${If}\:\boldsymbol{\mathrm{A}}\:{and}\:\boldsymbol{\mathrm{B}}\:{are}\:{two}\:{sets}\:{and}\:\mathbb{U}\:{is} \\ $$$${a}\:{universal}\:{set}\:{prove}\:{that} \\ $$$$\boldsymbol{\mathrm{A}}\:\subseteq\:\boldsymbol{\mathrm{B}}\:\:\Rightarrow\:\boldsymbol{\mathrm{B}}=\boldsymbol{\mathrm{A}}\:\cup\:\left(\boldsymbol{\mathrm{A}}'\:\cap\:\boldsymbol{\mathrm{B}}\right) \\ $$ Answered by Rasheed Ahmad last updated on 19/Sep/15…
Question Number 1743 by 123456 last updated on 12/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}=? \\ $$ Commented by Rasheed Ahmad last updated on 13/Sep/15 $${u}'\left({v}−{v}'\right)+{uv}'=\mathrm{0} \\ $$$${u}'{v}+{uv}'−{u}'{v}'=\mathrm{0}…
Question Number 1740 by tabrez8590@gmail last updated on 11/Sep/15 $${how}\:\:\mathrm{0}!=\mathrm{1} \\ $$ Commented by 123456 last updated on 11/Sep/15 $$\mathrm{1}!=\mathrm{1}\centerdot\mathrm{0}! \\ $$$$\mathrm{so}\:\mathrm{for}\:\mathrm{it}\:\mathrm{work}\:\mathrm{to}\:\mathrm{1}\:\mathrm{them}\:\mathrm{0}!=\mathrm{1} \\ $$ Answered…