Question Number 223192 by Nicholas666 last updated on 17/Jul/25 $$ \\ $$$$\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{Evaluate}}\:;\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\mathrm{1}−{q}^{\mathrm{24}{n}} \right)\:\mathrm{d}{q} \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 223193 by Tawa11 last updated on 17/Jul/25 $$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\:\:\:\:\:\:\:\int_{\:\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \:\mathrm{tan}^{−\:\mathrm{1}} \left(\mathrm{r}\:\mathrm{sin}\:\theta\right)\:\mathrm{d}\theta\:\:\:=\:\:\:\mathrm{2}\boldsymbol{\chi}_{\mathrm{2}} \left(\frac{\sqrt{\mathrm{1}\:\:+\:\:\mathrm{r}^{\mathrm{2}} }\:\:−\:\:\mathrm{1}}{\mathrm{r}}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 223210 by fantastic last updated on 17/Jul/25 $${I}\:{have}\:{a}\:{theory}.\:{this}\:{may}\:{not}\:{be}\:{true}\:{and} \\ $$$${I}\:{cannot}\:{prove}\:{it}\:.\:{I}\:{think} \\ $$$${If}\:{you}\:{want}\:{to}\:{draw} \\ $$$$\:{a}\:{closed}\:{shape}\:{in}\:{x}^{{th}} \:{dimention} \\ $$$${the}\:{minimum}\:{number}\:{of} \\ $$$$\:{vertex}\:{you}\:{will}\:{need}\:{is}\:{x}+\mathrm{1} \\ $$$$ \\ $$$$\:{like}\:{if}\:{you}\:{want}\:{to}\:{draw}\:{a}\:{closed}\:{shape}…
Question Number 223204 by Nadirhashim last updated on 17/Jul/25 $$\:\:\:\underset{\frac{\pi}{\mathrm{6}}} {\overset{\frac{\pi}{\mathrm{3}}} {\int}}\frac{\boldsymbol{{dx}}}{\mathrm{1}+\sqrt{\boldsymbol{{tanx}}}}\:=…? \\ $$ Answered by som(math1967) last updated on 17/Jul/25 $$\:\:\:{I}=\int_{\frac{\pi}{\mathrm{6}}\:} ^{\frac{\pi}{\mathrm{3}}} \frac{{dx}}{\mathrm{1}+\sqrt{{tan}\left(\frac{\pi}{\mathrm{3}}+\frac{\pi}{\mathrm{6}}−{x}\right)}} \\…
Question Number 223191 by Nicholas666 last updated on 17/Jul/25 $$ \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{Evaluate}}\:;\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\:\left(\mathrm{1}−{q}^{\mathrm{4}{n}} \right)^{\mathrm{6}} \:{dq} \\ $$$$ \\ $$ Terms of Service…
Question Number 223203 by ajfour last updated on 17/Jul/25 $${Find}\:{x}\:{and}\:{y} \\ $$$$\:\:\:\:{ix}+{y}={ix}^{\mathrm{3}} −{y}^{\mathrm{3}} \\ $$$$\:\:\:{and}\: \\ $$$$\:\:\:\:{xy}\left({y}−{ix}\right)={c} \\ $$ Answered by mr W last updated…
Question Number 223161 by Rojarani last updated on 16/Jul/25 $${Solve}\:{for}\:{x}\:{if} \\ $$$$\:\sqrt{{x}+\mathrm{1}}+\sqrt{{x}−\mathrm{1}}=\mathrm{1} \\ $$ Commented by fantastic last updated on 16/Jul/25 $${Why}\:{am}\:{i}\:{getting}\:\frac{\mathrm{5}}{\mathrm{4}}?? \\ $$ Commented…
Question Number 223179 by hardmath last updated on 16/Jul/25 $$\mathrm{If}:\:\:\:\mathrm{xy}\:=\:\boldsymbol{\mathrm{e}}^{\frac{\boldsymbol{\pi}}{\mathrm{4}}} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{tg}\:\left(\mathrm{ln}\:\left(\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{y}}\right)\right)\:\centerdot\:\mathrm{tg}\:\left(\mathrm{ln}\:\left(\frac{\mathrm{y}^{\mathrm{3}} }{\mathrm{x}}\right)\right)\:=\:? \\ $$ Commented by hardmath last updated on 16/Jul/25 $$\mathrm{no}\:\mathrm{dear}\:\mathrm{professor},\:\mathrm{answer}: \\…
Question Number 223189 by behi834171 last updated on 16/Jul/25 $$\left(\boldsymbol{{x}}−\mathrm{1}\right)\left(\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{2}\right)\left(\boldsymbol{{x}}^{\mathrm{3}} −\mathrm{3}\right)\left(\boldsymbol{{x}}^{\mathrm{4}} −\mathrm{4}\right)=\mathrm{36} \\ $$$$\boldsymbol{{x}}=? \\ $$ Commented by Ghisom last updated on 17/Jul/25 $$\mathrm{you}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate}…
Question Number 223157 by cemoosky last updated on 16/Jul/25 Answered by som(math1967) last updated on 16/Jul/25 $$\angle{QPN}+\angle{NML}=\mathrm{55}° \\ $$$$\therefore\angle{NPQ}=\mathrm{55}−\mathrm{40}=\mathrm{15}° \\ $$$$\angle{RQP}=\angle{NPQ}=\mathrm{15}° \\ $$ Answered by…