Question Number 196246 by mathlove last updated on 20/Aug/23 Commented by mathlove last updated on 20/Aug/23 $${faind}\:{the}\:{value}\:{of} \\ $$$$\left({fog}^{−\mathrm{1}} {of}\right)_{\mathrm{4}} =? \\ $$ Answered by…
Question Number 196211 by pete last updated on 20/Aug/23 $$\mathrm{Show}\:\mathrm{that}\:\mathrm{cos}\left(\frac{\pi}{\mathrm{3}}+\mathrm{i}\right)=\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{e}+\frac{\mathrm{1}}{\mathrm{e}}\right)\:−\frac{\sqrt{\mathrm{3}}}{\mathrm{4}}\left(\mathrm{e}−\frac{\mathrm{1}}{\mathrm{e}}\right)\mathrm{i} \\ $$ Answered by Frix last updated on 20/Aug/23 $$\mathrm{cos}\:{x}\:=\frac{\mathrm{e}^{\mathrm{2i}{x}} +\mathrm{1}}{\mathrm{2e}^{\mathrm{i}{x}} } \\ $$$$\mathrm{cos}\:\left({a}+{b}\mathrm{i}\right)\:=\mathrm{cos}\:{a}\:\mathrm{cosh}\:{b}\:−\mathrm{i}\:\mathrm{sin}\:{a}\:\mathrm{sinh}\:{b} \\…
Question Number 196242 by pete last updated on 20/Aug/23 $$\mathrm{Simplify}\:\left(\frac{\mathrm{1}+\mathrm{cos2}\theta\:+\mathrm{isin2}\theta}{\mathrm{1}+\mathrm{cos2}\theta\:−\mathrm{isin2}\theta}\right)^{\mathrm{30}} \\ $$ Answered by MM42 last updated on 20/Aug/23 $$\left(\frac{\mathrm{2}{cos}^{\mathrm{2}} \theta+\mathrm{2}{isin}\theta{cos}\theta}{\mathrm{2}{cos}^{\mathrm{2}} \theta−\mathrm{2}{isin}\theta{cos}\theta}\right)^{\mathrm{30}} =\left(\frac{{cos}\theta+{isin}\theta}{{cos}\theta−{isin}\theta}\right)^{\mathrm{30}} \\ $$$$={cos}\left(\mathrm{60}\theta\right)+{isin}\left(\mathrm{60}\theta\right)\:\checkmark…
Question Number 196225 by mr W last updated on 20/Aug/23 Commented by mr W last updated on 20/Aug/23 $${find}\:{the}\:{area}\:{of}\:{red}\:{part}\:{in}\:{the} \\ $$$${parallelogram}. \\ $$ Answered by…
Question Number 196185 by cortano12 last updated on 19/Aug/23 $$\:\:\:\underbrace{\:} \\ $$ Commented by AST last updated on 19/Aug/23 $${When}\:{x}={y}={z}\:\wedge\:{a}={b}={c};\frac{{ab}+{bc}+{ca}}{{bc}}=\mathrm{3} \\ $$$${When}\:{x}=−\mathrm{1},{y}=\mathrm{1},{z}=\mathrm{1};\:\frac{{ab}+{bc}+{ca}}{{bc}}=\frac{{a}\left({b}+{c}\right)}{{bc}}+\mathrm{1} \\ $$$${can}\:{get}\:{multiple}\:{values}\:{since}\:{a},{b},{c}\:{can}\:{vary}. \\…
Question Number 196155 by sonukgindia last updated on 19/Aug/23 Commented by mr W last updated on 19/Aug/23 Answered by mr W last updated on 19/Aug/23…
Question Number 196154 by sonukgindia last updated on 19/Aug/23 Answered by mr W last updated on 19/Aug/23 $${x}^{\mathrm{2}} =−\mathrm{2}\left({x}+\mathrm{2}\right) \\ $$$${x}^{\mathrm{4}} =\mathrm{4}\left({x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{4}\right)=\mathrm{4}\left(\mathrm{2}{x}\right)=\mathrm{8}{x} \\ $$$${x}^{\mathrm{6}}…
Question Number 196181 by sonukgindia last updated on 19/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196183 by cortano12 last updated on 19/Aug/23 Answered by dimentri last updated on 19/Aug/23 $$\:\:\underbrace{\Subset} \\ $$ Answered by mr W last updated…
Question Number 196209 by mnjuly1970 last updated on 19/Aug/23 $$ \\ $$$$\:\:\:\:\:\:\Omega=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:\left({x}−\mathrm{1}\right)^{\:\mathrm{2}} }{\mathrm{ln}^{\mathrm{2}} \left({x}\right)}\:{dx}=\:? \\ $$$$\:\:\:\:\:−−−− \\ $$ Answered by Mathspace last updated…