Question Number 222644 by MrGaster last updated on 03/Jul/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 222646 by Tawa11 last updated on 03/Jul/25 Answered by som(math1967) last updated on 03/Jul/25 $$\:{AB}={BC}−{d},\:{AC}={BC}+{d} \\ $$$$\:\:{AC}^{\mathrm{2}} ={AB}^{\mathrm{2}} +{BC}^{\mathrm{2}} \\ $$$$\left({BC}+{d}\right)^{\mathrm{2}} =\left({BC}−{d}\right)^{\mathrm{2}} +{BC}^{\mathrm{2}}…
Question Number 222659 by Mingma last updated on 03/Jul/25 Answered by mr W last updated on 04/Jul/25 Commented by mr W last updated on 04/Jul/25…
Question Number 222636 by Mingma last updated on 02/Jul/25 Answered by mr W last updated on 04/Jul/25 $${d}=\sqrt{{a}^{\mathrm{2}} −\left({a}−{x}\right)^{\mathrm{2}} }+{x}+\sqrt{{b}^{\mathrm{2}} −\left({b}−{x}\right)^{\mathrm{2}} } \\ $$$$\:\:=\sqrt{\mathrm{2}{ax}−{x}^{\mathrm{2}} }+{x}+\sqrt{\mathrm{2}{bx}−{x}^{\mathrm{2}}…
Question Number 222622 by Mingma last updated on 02/Jul/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 222635 by Mingma last updated on 02/Jul/25 Answered by Raphael254 last updated on 28/Jul/25 $${n}\:+\:{S}\left({n}\right)\:+\:{S}\left({S}\left({n}\right)\right)\:=\:\mathrm{2007} \\ $$$$ \\ $$$${n}\:=\:\mathrm{1983} \\ $$$$ \\ $$$$\mathrm{1983}\:+\:\left(\mathrm{1}+\mathrm{9}+\mathrm{8}+\mathrm{3}\right)\:+\:{S}\left(\mathrm{1}+\mathrm{9}+\mathrm{8}+\mathrm{3}\right)\:=…
Question Number 222624 by Lekhraj last updated on 02/Jul/25 Answered by mr W last updated on 02/Jul/25 Commented by mr W last updated on 02/Jul/25…
Question Number 222607 by MrGaster last updated on 01/Jul/25 $$\mathrm{Prove}:\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\mathrm{3}} }{\mathrm{5}−{x}^{\mathrm{3}} }\centerdot\frac{\mathrm{1}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}−{x}^{\mathrm{3}} }}{dx}=\frac{\sqrt[{\mathrm{3}}]{\mathrm{10}}−\mathrm{2}}{\mathrm{3}\sqrt{\mathrm{3}}}\pi \\ $$ Answered by MrGaster last updated on 01/Jul/25 $${t}={x}^{\mathrm{3}}…
Question Number 222616 by ajfour last updated on 01/Jul/25 Answered by ajfour last updated on 01/Jul/25 Commented by MathematicalUser2357 last updated on 02/Jul/25 $$\mathrm{I}\:\mathrm{had}\:\mathrm{grapher}\:\mathrm{free} \\…
Question Number 222601 by MathematicalUser2357 last updated on 01/Jul/25 $$\mathrm{L}\:\mathrm{60} \\ $$$$ \\ $$$$\mathrm{1}.\:\: \\ $$ Commented by MathematicalUser2357 last updated on 01/Jul/25 $$\mathrm{The}\:“\mathrm{L}''\:\mathrm{is}\:\mathrm{the}\:\mathrm{Grade}\:\mathrm{letter} \\…