Question Number 194713 by Mingma last updated on 14/Jul/23 Commented by Frix last updated on 15/Jul/23 $$\frac{{A}}{{B}}=\mathrm{2} \\ $$ Commented by Mingma last updated on…
Question Number 194715 by masterpk last updated on 14/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194710 by York12 last updated on 14/Jul/23 $${let}\:{p}\:{be}\:{a}\:{prime}\:{number} \\ $$$$\&\:{let}\:{a}_{\mathrm{1}} \:,{a}_{\mathrm{2}} ,{a}_{\mathrm{3}} ,…,{a}_{{p}\:} {be}\:{integers} \\ $$$${show}\:{that}\:,\:{there}\:{exists}\:{an}\:{integer}\:{k}\:{such}\:{that}\:{the}\:{numbers} \\ $$$${a}_{\mathrm{1}} +{k},\:{a}_{\mathrm{2}} +{k},{a}_{\mathrm{3}} +{k},….,{a}_{{p}} +{k} \\…
Question Number 194732 by MathsFan last updated on 14/Jul/23 Commented by York12 last updated on 15/Jul/23 $${do}\:{not}\:{participate}\:{IYMC} \\ $$$${it}\:{is}\:{fake} \\ $$ Answered by mahdipoor last…
Question Number 194735 by sonukgindia last updated on 14/Jul/23 Answered by TheHoneyCat last updated on 14/Jul/23 $$\mathrm{If}\:{x}\:\mathrm{is}\:\mathrm{a}\:\mathrm{constant},\:\left({i}.{e}.\:{x}\left(\mathrm{2}\right)={x}×\mathrm{2}\:\right) \\ $$$$\mathrm{then}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{is}: \\ $$$${x}\left(\mathrm{2}\right)=\frac{\mathrm{4}\sqrt{\mathrm{7}}−\mathrm{2}\sqrt{\mathrm{5}}}{\:\sqrt{\mathrm{7}}+\sqrt{\mathrm{5}}} \\ $$$$ \\ $$$$\mathrm{But}\:\mathrm{I}'\mathrm{m}\:\mathrm{guessing}\:{x}\:\mathrm{is}\:\mathrm{here}\:\mathrm{a}\:\mathrm{function}……
Question Number 194685 by cortano12 last updated on 13/Jul/23 Answered by qaz last updated on 14/Jul/23 $$\left(\mathrm{1}+{x}\right)^{\frac{\mathrm{1}}{{x}}} ={e}^{\frac{\mathrm{1}}{{x}}{ln}\left(\mathrm{1}+{x}\right)} ={e}^{\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\mathrm{1}}{\mathrm{3}}{x}^{\mathrm{2}} +…} \\ $$$$={e}\left(\mathrm{1}+\left(−\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\mathrm{1}}{\mathrm{3}}{x}^{\mathrm{2}} +…\right)+\frac{\mathrm{1}}{\mathrm{2}}\left(−\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\mathrm{1}}{\mathrm{3}}{x}^{\mathrm{2}} +…\right)^{\mathrm{2}} +…\right.…
Question Number 194700 by MathsFan last updated on 13/Jul/23 Commented by MathsFan last updated on 13/Jul/23 $${help}\:{please} \\ $$ Commented by Tinku Tara last updated…
Question Number 194697 by cortano12 last updated on 13/Jul/23 $$\:\:\:\:\underbrace{\:} \\ $$ Answered by MM42 last updated on 13/Jul/23 $$\frac{{tanx}−{tan}\mathrm{3}{x}}{{tanx}}=\mathrm{3}\Rightarrow\frac{{tan}\mathrm{3}{x}}{{tanx}}=−\mathrm{2} \\ $$$$\frac{{cotx}}{{cotx}+{cot}\mathrm{3}{x}}=\frac{{tan}\mathrm{3}{x}}{{tanx}+{tan}\mathrm{3}{x}} \\ $$$$=\frac{−\mathrm{2}}{\mathrm{1}−\mathrm{2}}=\mathrm{2}\:\checkmark \\…
Question Number 194709 by MM42 last updated on 13/Jul/23 $${Show}\:{that}\:\:{in}\:{fibonacci}\:{sequence} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{f}_{\mathrm{3}{n}} ={f}_{{n}} ^{\mathrm{3}} +{f}_{{n}+\mathrm{1}} ^{\mathrm{3}} −{f}_{{n}−\mathrm{1}} ^{\mathrm{3}} \\ $$$$ \\ $$ Answered by TheHoneyCat…
Question Number 194693 by MM42 last updated on 13/Jul/23 $${if}\:\:\:{f}_{{n}} ={f}_{{n}−\mathrm{1}} +{f}_{{n}−\mathrm{2}} \:\:;\:\:{f}_{\mathrm{1}} ={f}_{\mathrm{2}} =\mathrm{1} \\ $$$${then}\:\:\:{prove}\:{that}\:\:\:\mathrm{5}\mid{f}_{\mathrm{5}{n}} \:\: \\ $$ Answered by Frix last updated…