Question Number 193414 by mokys last updated on 13/Jun/23 Answered by AST last updated on 13/Jun/23 $${Z}\:{and}\:{Z}_{\mathrm{2}} \:{in}\:{the}\:{closed}\:{unit}\:{disk}\Rightarrow\mid{Z}\mid,\mid{Z}_{\mathrm{2}} \mid\leqslant\mathrm{1} \\ $$$$\mid{Z}_{\mathrm{1}} −{Z}_{\mathrm{2}} \mid\geqslant\mathrm{1}\Rightarrow\left({Z}_{\mathrm{1}} −{Z}_{\mathrm{2}} \right)\left(\overset{−}…
Question Number 193409 by cortano12 last updated on 13/Jun/23 $$\:\:\:\Subset \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 193408 by cortano12 last updated on 13/Jun/23 $$\:\underline{\underbrace{ }} \\ $$ Answered by MM42 last updated on 13/Jun/23 $${lim}_{{n}\rightarrow\infty} \:\frac{\mathrm{1}}{{n}}×\left(\frac{\mathrm{1}−\left({e}^{\frac{{a}}{{n}}} \right)^{{n}} ×\frac{\mathrm{1}}{{e}^{\frac{{a}}{{n}}} }}{\mathrm{1}−{e}^{\frac{{a}}{{n}}}…
Question Number 193411 by cortano12 last updated on 13/Jun/23 $$\:\:\:\:\: \\ $$$$ \\ $$ Commented by BaliramKumar last updated on 13/Jun/23 $$\mathrm{put}\:\:\:{x}\:=\:{cos}\mathrm{2}\theta \\ $$ Answered…
Question Number 193410 by cortano12 last updated on 13/Jun/23 $$\:\:\begin{cases}{\mathrm{x}=\sqrt{\mathrm{3}−\sqrt{\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}}}}\\{\mathrm{y}=\sqrt{\mathrm{3}+\sqrt{\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}}}}\end{cases}\: \\ $$$$\:\:\:\:\underbrace{\boldsymbol{{x}}} \\ $$ Answered by aba last updated on 13/Jun/23 $$\mathrm{xy}=\sqrt{\mathrm{9}−\left(\mathrm{5}+\mathrm{2}\sqrt{\mathrm{3}}\right)}=\sqrt{\mathrm{4}−\mathrm{2}\sqrt{\mathrm{3}}}=\sqrt{\mathrm{3}}−\mathrm{1}\:\wedge\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\mathrm{6} \\…
Question Number 193405 by sciencestudentW last updated on 13/Jun/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62086 by Cypher1207 last updated on 15/Jun/19 $$\mathrm{The}\:\mathrm{coefficient}\:\mathrm{of}\:{x}^{{m}} \:\mathrm{in} \\ $$$$\left(\mathrm{1}+{x}\right)^{{p}} +\left(\mathrm{1}+{x}\right)^{{p}+\mathrm{1}} +…+\left(\mathrm{1}+{x}\right)^{{n}} ,\:{p}\leqslant\:{m}\leqslant\:{n} \\ $$$$\mathrm{is}\: \\ $$ Answered by mr W last…
Question Number 61948 by subhankar10 last updated on 12/Jun/19 $$\mathrm{The}\:\mathrm{vectors}\:\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}},\:\boldsymbol{\mathrm{c}}\:\mathrm{are}\:\mathrm{equal}\:\mathrm{in}\:\mathrm{length} \\ $$$$\mathrm{and}\:\mathrm{taken}\:\mathrm{pairwise},\:\mathrm{they}\:\mathrm{make}\:\mathrm{equal} \\ $$$$\mathrm{angles}.\:\mathrm{If}\:\:\boldsymbol{\mathrm{a}}=\boldsymbol{\mathrm{i}}+\boldsymbol{\mathrm{j}},\:\:\boldsymbol{\mathrm{b}}=\boldsymbol{\mathrm{j}}+\boldsymbol{\mathrm{k}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{c}}\:\mathrm{makes} \\ $$$$\mathrm{an}\:\mathrm{obtuse}\:\mathrm{angle}\:\mathrm{with}\:{X}−\mathrm{axis},\:\mathrm{then}\:\boldsymbol{\mathrm{c}}= \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 61614 by Tajaddin last updated on 05/Jun/19 $$\underset{−\mathrm{1}} {\overset{\mathrm{1}} {\int}}\:\frac{{d}}{{dx}}\:\left(\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{1}}{{x}}\right){dx}\:= \\ $$ Commented by maxmathsup by imad last updated on 05/Jun/19 $${we}\:{have}\:\frac{{d}}{{dx}}\left({arctan}\left(\frac{\mathrm{1}}{{x}}\right)\right)\:=\frac{−\mathrm{1}}{{x}^{\mathrm{2}}…
Question Number 60461 by ashutosh last updated on 21/May/19 $$\mathrm{Two}\:\mathrm{cogged}\:\mathrm{wheels},\:\mathrm{of}\:\mathrm{which}\:\mathrm{one}\:\mathrm{has} \\ $$$$\mathrm{16}\:\mathrm{cogs}\:\mathrm{and}\:\mathrm{other}\:\mathrm{has}\:\mathrm{27},\:\mathrm{work}\:\mathrm{into}\: \\ $$$$\mathrm{each}\:\mathrm{other}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{latter}\:\mathrm{turns}\:\mathrm{80}\:\mathrm{times}\:\mathrm{in}\: \\ $$$$\mathrm{three}\:\mathrm{quarters}\:\mathrm{of}\:\mathrm{a}\:\mathrm{minute},\:\mathrm{how}\:\mathrm{often} \\ $$$$\mathrm{does}\:\mathrm{the}\:\mathrm{other}\:\mathrm{turn}\:\mathrm{in}\:\mathrm{8}\:\mathrm{seconds}? \\ $$ Answered by MJS last updated…