Question Number 25075 by Mr easy last updated on 03/Dec/17 $$\mathrm{Let}\:{z}_{\mathrm{1}} \mathrm{and}\:{z}_{\mathrm{2}} \:\mathrm{be}\:\mathrm{two}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation} \\ $$$${z}^{\mathrm{2}} +{az}+{b}=\mathrm{0},\:{z}\:\mathrm{being}\:\mathrm{complex}.\:\mathrm{Further} \\ $$$$\mathrm{assume}\:\mathrm{that}\:\mathrm{the}\:\mathrm{origin},\:{z}_{\mathrm{1}} \:\mathrm{and}\:{z}_{\mathrm{2}} \:\mathrm{form} \\ $$$$\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle}.\:\mathrm{Then}, \\ $$ Answered…
Question Number 90535 by 1223 last updated on 24/Apr/20 $$\mathrm{In}\:\mathrm{a}\:\mathrm{triangle}\:{ABC},\:{a}\left({b}\:\mathrm{cos}\:{C}−{c}\:\mathrm{cos}\:{B}\right)= \\ $$ Answered by $@ty@m123 last updated on 24/Apr/20 $${a}\left({b}×\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} −{c}^{\mathrm{2}} }{\mathrm{2}{ab}}−{c}×\frac{{c}^{\mathrm{2}} +{a}^{\mathrm{2}} −{b}^{\mathrm{2}}…
Question Number 24998 by anuj saini last updated on 30/Nov/17 $$\mathrm{A}\:\mathrm{fair}\:\mathrm{coin}\:\mathrm{is}\:\mathrm{tossed}\:\mathrm{100}\:\mathrm{times}.\:\mathrm{The} \\ $$$$\mathrm{probability}\:\mathrm{of}\:\mathrm{getting}\:\mathrm{tails}\:\mathrm{an}\:\mathrm{odd} \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{times}\:\mathrm{is} \\ $$ Commented by Penguin last updated on 01/Dec/17 $${attempt}?…
Question Number 24974 by kawsar ahmed last updated on 30/Nov/17 $$\mathrm{If}\:\:\frac{{x}^{\mathrm{23}} }{{x}^{{m}} }\:=\:{x}^{\mathrm{15}} \:\mathrm{and}\:\left({x}^{\mathrm{4}} \right)^{{n}} ={x}^{\mathrm{20}} ,\:\mathrm{then}\:{mn}= \\ $$ Answered by nnnavendu last updated on…
Question Number 155914 by jlewis last updated on 05/Oct/21 $${D}\mathrm{raw}\:\mathrm{the}\:\mathrm{Newman}\:\mathrm{projection}\:\mathrm{formula} \\ $$$$\mathrm{for}\:\mathrm{the}\:\mathrm{chair}\:\mathrm{conformation}\:\:\mathrm{of}\:\mathrm{cyclohexanol} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 24800 by ghazalashaheen last updated on 26/Nov/17 $$\mathrm{A}\:\mathrm{closed}\:\mathrm{box}\:\mathrm{measures}\:\mathrm{externally}\: \\ $$$$\mathrm{9dm}\:\mathrm{long},\:\mathrm{6dm}\:\mathrm{broad},\:\mathrm{4}\frac{\mathrm{1}}{\mathrm{2}}\mathrm{dm}\:\mathrm{high},\:\mathrm{and} \\ $$$$\mathrm{is}\:\mathrm{made}\:\mathrm{of}\:\mathrm{wood}\:\mathrm{2}\frac{\mathrm{1}}{\mathrm{2}}\mathrm{cm}\:\mathrm{thick}.\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{cost}\:\mathrm{of}\:\mathrm{lining}\:\mathrm{it}\:\mathrm{on}\:\mathrm{the}\:\mathrm{inside}\:\mathrm{with}\:\mathrm{metal} \\ $$$$\mathrm{at}\:\mathrm{6}\:\mathrm{paise}\:\mathrm{per}\:\mathrm{sq}.\mathrm{m}. \\ $$ Answered by mrW1 last updated…
Question Number 90223 by zainal tanjung last updated on 22/Apr/20 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{in}\:\mathrm{which}\:\mathrm{12}\:\mathrm{books} \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{put}\:\mathrm{in}\:\mathrm{3}\:\mathrm{shelves},\:\mathrm{4}\:\mathrm{on}\:\mathrm{each},\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 90220 by zainal tanjung last updated on 22/Apr/20 $$\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{in}\:\mathrm{which}\:\mathrm{8}\:\mathrm{distinct} \\ $$$$\mathrm{toys}\:\mathrm{can}\:\mathrm{be}\:\mathrm{distributed}\:\mathrm{among}\:\mathrm{5}\: \\ $$$$\mathrm{children}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 90221 by zainal tanjung last updated on 22/Apr/20 $$\mathrm{There}\:\mathrm{are}\:\mathrm{3}\:\mathrm{copies}\:\mathrm{each}\:\mathrm{of}\:\mathrm{4}\:\mathrm{different} \\ $$$$\mathrm{books}.\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{ways}\:\mathrm{in}\:\mathrm{which} \\ $$$$\mathrm{in}\:\mathrm{which}\:\mathrm{they}\:\mathrm{can}\:\mathrm{be}\:\mathrm{arranged}\:\mathrm{in}\:\mathrm{a}\: \\ $$$$\mathrm{shelf}\:\mathrm{is} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 24459 by mustafasediqi last updated on 18/Nov/17 $$\mathrm{If}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{a}\:\mathrm{rectangle}\:\mathrm{are}\:\mathrm{increased} \\ $$$$\mathrm{each}\:\mathrm{by}\:\mathrm{10\%},\:\mathrm{find}\:\mathrm{the}\:\%\:\mathrm{increase}\:\mathrm{in}\:\mathrm{its} \\ $$$$\mathrm{diagonal}. \\ $$ Answered by ajfour last updated on 18/Nov/17 $${d}^{\:\mathrm{2}} \:=\:{l}^{\mathrm{2}}…