Question Number 222521 by hu last updated on 29/Jun/25 $$−\mathrm{3}{ix}+\frac{\pi}{\mathrm{2}}+\frac{{ix}−\sqrt{\mathrm{5}\pi}}{\mathrm{6}}=\mathrm{0} \\ $$$${x}=?\: \\ $$ Commented by Rasheed.Sindhi last updated on 29/Jun/25 $$\sqrt{\mathrm{5}\pi}\:{or}\:\sqrt{\mathrm{5}}\:\pi\:? \\ $$ Answered…
Question Number 222523 by hu last updated on 29/Jun/25 $${x}+{V}−{J}\left({x}\right)\frac{{ustx}}{{zac}^{\mathrm{2}} {x}}={x}−\frac{{ustx}_{\mathrm{0}} }{\:\sqrt{{x}}\psi+\zeta\left(\frac{−\mathrm{1}+{v\%}}{\pi+\mathrm{2}}+\mathscr{L}_{{l}\left({x}\rightarrow\mathrm{0}\right)} ^{\:\:{v\%}} {X}_{\mathrm{2}{x}^{\mathrm{2}} } ^{\:\mathrm{1}} \right)} \\ $$ Answered by wewji12 last updated on…
Question Number 222511 by hu last updated on 28/Jun/25 $${Is}\:{the}\:{statement}\:{correct}? \\ $$$${in}\:{const}.“\:{x}+{a}−{bx}^{{n}} =\left\{\mathrm{0}\right\}\:'' \\ $$$${x}=\begin{cases}{−{a}\pm\frac{\mathrm{2}{b}}{{n}+\mathrm{1}}\:,\:{n}>\mathrm{0}}\\{{N}_{{b}} ^{\:{a}} \:\int_{{b}} ^{\:{a}} {G}\left({n}−\mathrm{1}\right),\:{n}\leqslant\mathrm{0}}\end{cases} \\ $$ Terms of Service Privacy…
Question Number 222501 by hu last updated on 28/Jun/25 $${This}\:{is}\:{VERY}\:{HARD} \\ $$$$\begin{cases}{\begin{cases}{{x}+{y}=\mathrm{0}}\\{{l}\left({y}\right)=\mathrm{1}}\end{cases}}\\{\begin{cases}{{x}\in\mathbb{N}}\\{−{y}=\begin{cases}{{v\%},\:\:{for}\:{x}\circlearrowleft\gamma\left(\mathrm{1}\right)}\\{−{v\%},\:\:{for}\:{x}\looparrowright\theta\left(\oint_{−{x}} ^{\:\mathrm{0}} \frac{{c}}{\mathrm{7}}\right)}\end{cases}}\end{cases}}\end{cases} \\ $$$${x}=?,\:{y}=? \\ $$ Answered by wewji12 last updated on 28/Jun/25…
Question Number 222404 by ajfour last updated on 25/Jun/25 Answered by ajfour last updated on 26/Jun/25 $${x}+{y}+{z}=\boldsymbol{{s}} \\ $$$${xy}+{yz}+{zx}=\boldsymbol{{k}} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\boldsymbol{{h}} \\…
Question Number 222353 by Nicholas666 last updated on 23/Jun/25 $$ \\ $$$$\:\:\:\:\:\mathrm{solve};\:\:\frac{\mathrm{11}}{\mathrm{29}}\:=\:?\:,\:\mathrm{no}\:\mathrm{fraction}\:\mathrm{and}\:\mathrm{no}\:\mathrm{decimal}\:\:\:\:\: \\ $$$$ \\ $$ Commented by mr W last updated on 23/Jun/25 $${what}\:{is}\:{to}\:{solve}?\:{can}\:{you}\:{make}\:{clear}…
Question Number 222299 by fantastic last updated on 22/Jun/25 $${For}\:{what}\:{value}\:{of}\:\:{k}\:\:{the}\:{roots}\:{of}\:{the}\:{equation} \\ $$$$\frac{{x}^{\mathrm{2}} −\mathrm{2}{x}}{\mathrm{4}{x}−\mathrm{1}}=\frac{{k}−\mathrm{1}}{{k}+\mathrm{1}} \\ $$$${will}\:{have}\:{same}\:{value}\:{but}\:\:{with}\:{opposite}\:{symbol}\left({like}\:{x}={a}\:{and}\:−{a}\right) \\ $$$${i}\:{mean}\:{the}\:{two}\:{valuea}\:{of}\:{x}\:{will}\:{be}\:{this}\:{type} \\ $$$${x}=\mathrm{2}\:{and}\:−\mathrm{2}\left({both}\:\mathrm{2}\:{but}\:{opposite}\:{symbols}\right) \\ $$ Answered by mr W…
Question Number 222323 by MrGaster last updated on 22/Jun/25 $${a}+\mathrm{3}^{{b}} ={b},\mathrm{3}^{{b}} \centerdot{a}^{{b}+\mathrm{1}} \:\mathrm{max}=? \\ $$ Answered by Frix last updated on 22/Jun/25 $${a}={b}−\mathrm{3}^{{b}} \\ $$$${f}\left({b}\right)=\mathrm{3}^{{b}}…
Question Number 222309 by fantastic last updated on 22/Jun/25 $$\begin{array}{|c|}{\mathrm{4}^{{x}} +\mathrm{6}^{{x}} =\mathrm{9}^{{x}} }\\\hline\end{array} \\ $$ Answered by Rasheed.Sindhi last updated on 22/Jun/25 $$\frac{\mathrm{4}^{{x}} }{\mathrm{6}^{{x}} }+\mathrm{1}=\frac{\mathrm{9}^{{x}}…
Question Number 222339 by Tawa11 last updated on 22/Jun/25 $$\mathrm{Solve}:\:\:\:\:\:\:\sqrt[{\mathrm{x}}]{\mathrm{36}}\:\:\:+\:\:\:\sqrt[{\mathrm{x}}]{\mathrm{24}}\:\:\:\:=\:\:\:\sqrt[{\mathrm{x}}]{\mathrm{16}} \\ $$ Answered by fantastic last updated on 22/Jun/25 $$\left(\mathrm{36}\right)^{\frac{\mathrm{1}}{{x}}} +\left(\mathrm{24}\right)^{\frac{\mathrm{1}}{{x}}} =\left(\mathrm{16}\right)^{\frac{\mathrm{1}}{{x}}} \\ $$$${or}\:\left(\frac{\mathrm{36}}{\mathrm{16}}\right)^{\frac{\mathrm{1}}{{x}}} +\left(\frac{\mathrm{24}}{\mathrm{16}}\right)^{\frac{\mathrm{1}}{{x}}}…