Category: Algebra

Question Number 199033 by essaad last updated on 27/Oct/23 Commented by essaad last updated on 27/Oct/23 $${mr}\:\:{W}\:{could}\:{you}\:{please}\:{help}\:{us}\: \\ $$ Commented by mr W last updated…

Question Number 198968 by necx122 last updated on 26/Oct/23 $${Find}\:{the}\:{polynomial}\:{with}\:{roots}\:{that} \\ $$$${exceed}\:{the}\:{roots}\:{of}\: \\ $$$${f}\left({x}\right)=\mathrm{3}{x}^{\mathrm{3}} −\mathrm{14}{x}^{\mathrm{2}} +{x}+\mathrm{62}=\mathrm{0}\:{by}\:\mathrm{3}.\:{Hence} \\ $$$${determine}\:{the}\:{value}\:{of}\:\frac{\mathrm{1}}{{a}+\mathrm{3}}+\frac{\mathrm{1}}{{b}+\mathrm{3}}+\frac{\mathrm{1}}{{c}+\mathrm{3}}, \\ $$$${where}\:{a},{b}\:{and}\:{c}\:{are}\:{roots}. \\ $$ Answered by Rasheed.Sindhi…

Question Number 199015 by Tawa11 last updated on 26/Oct/23 Answered by Rasheed.Sindhi last updated on 26/Oct/23 $$\sqrt{{a}−{x}}\:+\sqrt{{b}−{x}}\:+\sqrt{{c}−{x}}\:=\mathrm{0} \\ $$$$\sqrt{{a}−{x}}\:=\mathrm{0}\:\wedge\:\sqrt{{b}−{x}}\:=\mathrm{0}\:\wedge\:\sqrt{{c}−{x}}\:=\mathrm{0} \\ $$$${x}={a}={b}={c} \\ $$$$\left({a}+{b}+{c}+\mathrm{3}{x}\right)\left({a}+{b}+{c}−{x}\right)=\mathrm{4}\left({bc}+{ca}+{ab}\right) \\ $$$$\left({x}+{x}+{x}+\mathrm{3}{x}\right)\left({x}+{x}+{x}−{x}\right)=\mathrm{4}\left({x}.{x}+{x}.{x}+{x}.{x}\right)…

Question Number 198902 by necx122 last updated on 25/Oct/23 $${Given}\:{that}\:{k}^{\mathrm{2}} −\mathrm{3}{k}+\mathrm{5}=\mathrm{0},\:{determine} \\ $$$${the}\:{value}\:{of}\:{k}^{\mathrm{4}} −\mathrm{6}{k}^{\mathrm{3}} +\mathrm{9}{k}^{\mathrm{2}} −\mathrm{7} \\ $$ Answered by witcher3 last updated on 25/Oct/23…

Question Number 198932 by necx122 last updated on 25/Oct/23 $${Find}\:{the}\:{value}\:{of}\:{m}\:{given}\:{that}\:{the} \\ $$$${roots}\:{of}\:{x}^{\mathrm{4}} −\mathrm{15}{x}^{\mathrm{3}} +\mathrm{70}{x}^{\mathrm{2}} −\mathrm{120}{x}+{m}=\mathrm{0} \\ $$$${form}\:{a}\:{geometric}\:{progression}. \\ $$ Answered by AST last updated on…