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Category: Algebra

Find-1-2-5-1-4-5-3-5-1-4-2-

Question Number 213374 by hardmath last updated on 03/Nov/24 $$\mathrm{Find}:\:\:\:\frac{\mathrm{1}\:−\:\mathrm{2}\:\sqrt[{\mathrm{4}}]{\mathrm{5}}\:+\:\sqrt{\mathrm{5}}}{\left(\sqrt{\mathrm{3}}\:−\:\sqrt[{\mathrm{4}}]{\mathrm{5}}\right)^{\mathrm{2}} }\:=\:? \\ $$ Commented by Frix last updated on 03/Nov/24 $$\frac{\mathrm{29}−\mathrm{15}\sqrt{\mathrm{3}}}{\mathrm{2}}−\frac{\mathrm{8}−\mathrm{5}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{3}}{\mathrm{4}}} +\frac{\mathrm{13}−\mathrm{7}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{2}}} −\frac{\mathrm{18}−\mathrm{11}\sqrt{\mathrm{3}}}{\mathrm{2}}\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{4}}} \\ $$…

2-x-3-x-1-0-x-1-x-2-

Question Number 213264 by efronzo1 last updated on 02/Nov/24 $$\:\:\:\:\:\:\sqrt{\mathrm{2}}\:\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\: \\ $$$$\:\:\:\:\:\:\mathrm{x}_{\mathrm{1}} \:,\:\mathrm{x}_{\mathrm{2}} \:\:\underline{\underbrace{\square}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com

1-2-x-1-x-3-1-3-x-3-1-6-x-

Question Number 213099 by MathematicalUser2357 last updated on 30/Oct/24 $$\frac{\mathrm{1}}{\mathrm{2}}\left({x}−\mathrm{1}\right)−\left({x}−\mathrm{3}\right)=\frac{\mathrm{1}}{\mathrm{3}}\left({x}+\mathrm{3}\right)+\frac{\mathrm{1}}{\mathrm{6}} \\ $$$${x}=… \\ $$ Answered by MrGaster last updated on 30/Oct/24 $$\frac{\mathrm{1}}{\mathrm{2}}{x}−\frac{\mathrm{1}}{\mathrm{2}}−{x}+\mathrm{3}=\frac{\mathrm{1}}{\mathrm{3}}{x}+\mathrm{1}+\frac{\mathrm{1}}{\mathrm{6}} \\ $$$$−\frac{\mathrm{1}}{\mathrm{2}}{x}+\frac{\mathrm{5}}{\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{3}}{x}+\frac{\mathrm{7}}{\mathrm{6}} \\…

n-15-find-4n-2-4n-120-n-4-2n-3-n-2-

Question Number 213047 by hardmath last updated on 29/Oct/24 $$\boldsymbol{\mathrm{n}}\:=\:\mathrm{15} \\ $$$$\mathrm{find}:\:\:\:\:\:\frac{\mathrm{4n}^{\mathrm{2}} \:\:+\:\:\mathrm{4n}\:\:+\:\:\mathrm{120}}{\:\sqrt{\mathrm{n}^{\mathrm{4}} \:\:+\:\:\mathrm{2n}^{\mathrm{3}} \:\:+\:\:\mathrm{n}^{\mathrm{2}} }}\:\:=\:\:? \\ $$ Answered by mehdee7396 last updated on 29/Oct/24…

Question-212991

Question Number 212991 by efronzo1 last updated on 28/Oct/24 $$\:\:\:\:\:\underbrace{\downharpoonleft\underline{}\:} \\ $$ Answered by Frix last updated on 28/Oct/24 $${H}\left({n}\right)=\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\:{k}!\left({k}^{\mathrm{2}} +{k}+\mathrm{1}\right) \\ $$$$\frac{{H}\left({n}\right)+\mathrm{1}}{\left({n}+\mathrm{1}\right)!}={n}+\mathrm{1}\:\:\:\:\:\left[\mathrm{test}\:\mathrm{it}\:\mathrm{for}\:{n}=\mathrm{1},\:\mathrm{2},\:\mathrm{3},…\right]…

52-6-43-3-2-52-6-43-3-2-18-

Question Number 213002 by efronzo1 last updated on 28/Oct/24 $$\:\:\frac{\left(\mathrm{52}+\mathrm{6}\sqrt{\mathrm{43}}\:\right)^{\mathrm{3}/\mathrm{2}} −\left(\mathrm{52}−\mathrm{6}\sqrt{\mathrm{43}}\right)^{\mathrm{3}/\mathrm{2}} }{\mathrm{18}}=? \\ $$ Answered by Rasheed.Sindhi last updated on 28/Oct/24 $$\:\:\frac{\left(\mathrm{52}+\mathrm{6}\sqrt{\mathrm{43}}\:\right)^{\mathrm{3}/\mathrm{2}} −\left(\mathrm{52}−\mathrm{6}\sqrt{\mathrm{43}}\right)^{\mathrm{3}/\mathrm{2}} }{\mathrm{18}}=? \\…