Question Number 63602 by pavithra last updated on 06/Jul/19 $$\mathrm{32}{x}^{\mathrm{3}} −\mathrm{48}{x}^{\mathrm{2}} −\mathrm{22}{x}−\mathrm{3}=\mathrm{0} \\ $$ Answered by MJS last updated on 06/Jul/19 $${x}^{\mathrm{3}} −\frac{\mathrm{3}}{\mathrm{2}}{x}^{\mathrm{2}} −\frac{\mathrm{11}}{\mathrm{16}}{x}−\frac{\mathrm{3}}{\mathrm{32}}=\mathrm{0} \\…
Question Number 63574 by Tawa1 last updated on 05/Jul/19 $$\mathrm{prove}\:\mathrm{that}\:\:\:\underset{\mathrm{k}\:=\:\mathrm{1}} {\overset{\infty} {\sum}}\:\:\frac{\mathrm{1}}{\mathrm{k}\left(\mathrm{2k}\:+\:\mathrm{1}\right)}\:\:=\:\:\mathrm{2}\:−\:\mathrm{2ln}\left(\mathrm{2}\right) \\ $$ Commented by mathmax by abdo last updated on 05/Jul/19 $${the}\:{H}_{{n}} \:{method}\:\:{let}\:{S}_{{n}}…
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Question Number 63522 by Tawa1 last updated on 05/Jul/19 Commented by Tawa1 last updated on 05/Jul/19 Find the real parameter “m” such that cross cutting of mx + 2y - 1 = 0 and 2x + my + 3 = 0 give slopes equation belongs x - y - 3 = 0 Commented by MJS last updated on 05/Jul/19 $$\left(\mathrm{1}\right)\:{mx}+\mathrm{2}{y}−\mathrm{1}=\mathrm{0}…
Question Number 63485 by ANTARES VY last updated on 04/Jul/19 $$\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}−\mathrm{3}\right)+\boldsymbol{\mathrm{f}}\left(\boldsymbol{\mathrm{x}}\right)=\mathrm{2}\boldsymbol{\mathrm{x}}−\mathrm{3} \\ $$$$\boldsymbol{\mathrm{F}}\left(\mathrm{2}\right)=\mathrm{0}. \\ $$$$\boldsymbol{\mathrm{F}}\left(−\mathrm{2}\right)=? \\ $$ Answered by MJS last updated on 04/Jul/19 $${f}\left({x}\right)={ax}+{b}…
Question Number 63474 by aliesam last updated on 04/Jul/19 $${let}\:{P}\left({x}\right)={x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{2}}{x}+{b} \\ $$$$ \\ $$$${and}\:{Q}\left({x}\right)={x}^{\mathrm{2}} +{cx}+{d} \\ $$$$ \\ $$$${be}\:{to}\:{polynomials}\:{with}\:{real}\:{coefficient}\:{such}\:{that} \\ $$$$ \\ $$$${P}\left({x}\right)\:{Q}\left({x}\right)={Q}\left({P}\left({x}\right)\right) \\…
Question Number 63449 by minh2001 last updated on 04/Jul/19 $${Do}\:{you}\:{remember}\:{that} \\ $$$$\pi\approx\mathrm{3}.\mathrm{1415926535897932}\ddots \\ $$$$\mathrm{38462643383279502884}\ddots \\ $$$$\mathrm{197}… \\ $$ Commented by minh2001 last updated on 04/Jul/19…
Question Number 128942 by bramlexs22 last updated on 11/Jan/21 $$\:\mathrm{Given}\::\:\mathrm{3}{xf}\left(\frac{\mathrm{1}}{{x}}\right)+{f}\left({x}\right)=\mathrm{2}{x}+\mathrm{2}\: \\ $$$${and}\:{f}\left(\mathrm{3}\right),\:\mathrm{f}\left(\mathrm{9}\right)\:,\:\mathrm{f}\left(\mathrm{a}\right)\:\mathrm{three}\:\mathrm{first} \\ $$$$\mathrm{term}\:\mathrm{in}\:\mathrm{AP}\:\mathrm{respectively}.\:\mathrm{Find} \\ $$$$\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{a}\:?\: \\ $$ Answered by liberty last updated on 11/Jan/21…
Question Number 128932 by Koyoooo last updated on 11/Jan/21 Commented by mr W last updated on 11/Jan/21 $${question}\:{is}\:{wrong}! \\ $$$$−\mathrm{3}\leqslant\mathrm{2}{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +\mathrm{2}{a}−\mathrm{4}{b}\leqslant\mathrm{44} \\ $$ Commented…