Question Number 62092 by Cypher1207 last updated on 15/Jun/19 $$\mathrm{MATH}\:\mathrm{MEME}: \\ $$$$\mathrm{3}+\mathrm{x}\:=\:\mathrm{1}+\mathrm{8} \\ $$$$\left.:\right) \\ $$$$\frac{\mathrm{3}+\mathrm{x}}{+}\:=\:\frac{\mathrm{1}+\mathrm{8}}{+} \\ $$$${cancel}\:{the}\:{plus}\:{sign} \\ $$$$\mathrm{3}{x}\:=\:\mathrm{18} \\ $$$$\frac{\mathrm{3}{x}}{\mathrm{3}}\:=\:\frac{\mathrm{18}}{\mathrm{3}} \\ $$$$\boldsymbol{{x}}\:=\:\mathrm{6} \\…
Question Number 127607 by bramlexs22 last updated on 31/Dec/20 Answered by liberty last updated on 31/Dec/20 $$\:\mathrm{A}\:\Rightarrow\mathrm{24}\:\mathrm{days}\: \\ $$$$\:\mathrm{B}\:\Rightarrow\:\mathrm{15}\:\mathrm{days} \\ $$$$\:\mathrm{C}\Rightarrow\:\mathrm{12}\:\mathrm{days} \\ $$$$\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{started}\:\mathrm{worked}\:\mathrm{3}\:\mathrm{days}\:\Rightarrow\:\mathrm{3}×\left(\frac{\mathrm{1}}{\mathrm{15}}+\frac{\mathrm{1}}{\mathrm{12}}\right)\:\mathrm{work} \\ $$$$\:\Rightarrow\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{4}}\:=\:\frac{\mathrm{9}}{\mathrm{20}}\:\mathrm{works}\:…
Question Number 62057 by hhghg last updated on 14/Jun/19 $$\mathrm{2}^{−\mathrm{2}} \\ $$ Commented by gunawan last updated on 15/Jun/19 $$\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{4}} \\ $$ Commented by…
Question Number 62055 by hhghg last updated on 14/Jun/19 $$\$\mathrm{8}+\$\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 62053 by hhghg last updated on 14/Jun/19 $$\mathrm{m5}=\mathrm{25} \\ $$ Commented by meme last updated on 15/Jun/19 $${m}=\mathrm{5} \\ $$$$ \\ $$ Terms…
Question Number 62054 by hhghg last updated on 14/Jun/19 $$\mathrm{484}×\mathrm{27} \\ $$ Commented by Tony Lin last updated on 15/Jun/19 $$=\mathrm{11}^{\mathrm{2}} ×\mathrm{6}^{\mathrm{2}} ×\mathrm{3} \\ $$$$=\left(\mathrm{108}×\mathrm{11}\right)×\mathrm{11}…
Question Number 62051 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{7}^{\mathrm{5}} }{\mathrm{7}^{\mathrm{3}} } \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\mathrm{7}^{\mathrm{5}−\mathrm{3}} \:=\mathrm{7}^{\mathrm{2}}…
Question Number 62052 by hhghg last updated on 14/Jun/19 $$\mathrm{3}\frac{\mathrm{1}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\mathrm{3}}{\mathrm{4}}−\frac{\mathrm{3}}{\mathrm{4}}=\mathrm{0} \\ $$ Terms…
Question Number 62050 by hhghg last updated on 14/Jun/19 $$\left[\mathrm{3}×\mathrm{5}+\mathrm{3}\right]+\left[\mathrm{3}+\left(\mathrm{3}×\mathrm{2}\right)\right] \\ $$ Commented by meme last updated on 15/Jun/19 $$=\mathrm{18}+\mathrm{9} \\ $$$$=\mathrm{27} \\ $$ Terms…
Question Number 62049 by hhghg last updated on 14/Jun/19 $$\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{5}} \\ $$ Commented by maxmathsup by imad last updated on 15/Jun/19 $$=\frac{\left(\mathrm{1}×\mathrm{5}\right)+\left(\mathrm{4}×\mathrm{1}\right)}{\mathrm{4}×\mathrm{5}}\:=\frac{\mathrm{5}+\mathrm{4}}{\mathrm{20}}\:=\frac{\mathrm{9}}{\mathrm{20}} \\ $$ Terms…