Question Number 60500 by prof Abdo imad last updated on 21/May/19 $${let}\:{A}\:=\begin{pmatrix}{\mathrm{1}\:\:\:\:\:\:\:\mathrm{1}}\\{−\mathrm{2}\:\:\:\mathrm{3}}\end{pmatrix} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{A}^{−\mathrm{1}} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:{A}^{{n}} \\ $$$$\left.\mathrm{3}\right)\:{determine}\:{e}^{{A}} \:\:\:{and}\:{e}^{−\mathrm{2}{A}} \:. \\ $$ Commented by maxmathsup…
Question Number 60501 by prof Abdo imad last updated on 21/May/19 $${let}\:{A}\:=\begin{pmatrix}{\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\mathrm{1}}\\{\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{1}}\end{pmatrix} \\ $$$$\left.\mathrm{1}\right){calculate}\:{A}^{{n}} \\ $$$$\left.\mathrm{2}\right)\:{determine}\:{e}^{{A}} \:\:\:{and}\:{e}^{−{A}} \:. \\ $$$$ \\ $$ Commented by maxmathsup…
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Question Number 126030 by Fareed last updated on 16/Dec/20 $$\mathrm{2}^{\mathrm{x}} =\mathrm{4x} \\ $$$$\mathrm{solve}\:\mathrm{it}\:\mathrm{please} \\ $$ Answered by Dwaipayan Shikari last updated on 16/Dec/20 $$\mathrm{2}^{{x}} =\mathrm{4}{x}…
Question Number 191553 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{a}^{\mathrm{2}} \:+\:{a}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:{a}^{\mathrm{5}} \:+\:{a}^{\mathrm{4}} \:+\:\mathrm{1}. \\ $$ Commented by Tinku Tara last updated on 25/Apr/23 $${a}=\omega,\:\omega^{\mathrm{2}} ,\:\mathrm{where}\:\omega\:\mathrm{is}\:\mathrm{cube}\:\mathrm{root}\:\mathrm{of}\:\mathrm{unity}.…
Question Number 191555 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{Solve} \\ $$$$\sqrt{{x}}\:+\:{y}\:=\:\mathrm{11} \\ $$$${x}\:+\:\sqrt{{y}}\:=\:\mathrm{7} \\ $$ Commented by Frix last updated on 26/Apr/23 $$\mathrm{Use}\:\mathrm{your}\:\mathrm{common}\:\mathrm{sense} \\…
Question Number 191552 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:\mathrm{3}{x}\:+\:\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\left({x}^{\mathrm{2}} \:+\:{x}\:+\:\frac{\mathrm{1}}{{x}}\:+\:\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\right)^{\mathrm{2}} \\ $$ Answered by mr W last updated on 25/Apr/23…
Question Number 60475 by Tawa1 last updated on 21/May/19 Answered by tanmay last updated on 21/May/19 $$\frac{{dp}}{{dx}}=\frac{{f}\left({x}\right)\frac{{dg}\left({x}\right)}{{dx}}−\left[{g}\left({x}\right)−\mathrm{1}\right]\frac{{df}\left({x}\right)}{{dx}}}{\left\{{f}\left({x}\right)\right\}^{\mathrm{2}} } \\ $$$${p}'\left(\mathrm{2}\right)=\frac{{f}\left(\mathrm{2}\right){g}'\left(\mathrm{2}\right)−\left[{g}\left(\mathrm{2}\right)−\mathrm{1}\right]{f}'\left(\mathrm{2}\right)}{{f}^{\mathrm{2}} \left(\mathrm{2}\right)} \\ $$$$=\frac{\left(−\mathrm{1}\right)\left(−{sin}\mathrm{2}\right)−\left[{cos}\mathrm{2}−\mathrm{1}\right]\mathrm{5}}{\left(−\mathrm{1}\right)^{\mathrm{2}} } \\…
Question Number 191546 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{If}\:{m}\:+\:\mathrm{1}\:=\:\sqrt{{n}}\:+\:\mathrm{3}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{{m}^{\mathrm{3}} \:−\:\mathrm{6}{m}^{\mathrm{2}} \:+\:\mathrm{12}{m}\:−\mathrm{8}}{\:\sqrt{{n}}}\:−\:{n}\right) \\ $$ Answered by som(math1967) last updated on 25/Apr/23 $$\frac{\mathrm{1}}{\mathrm{2}}×\left\{\frac{\left({m}−\mathrm{2}\right)^{\mathrm{3}} }{\:\sqrt{{n}}}\:−{n}\right\}…
Question Number 191536 by MATHEMATICSAM last updated on 25/Apr/23 $$\mathrm{Factorize} \\ $$$$\frac{\mathrm{2}}{\mathrm{2}{x}\:−\:\mathrm{1}}\:−\mathrm{5}\:+\:\frac{\mathrm{3}}{\mathrm{3}{x}\:−\:\mathrm{1}} \\ $$ Answered by som(math1967) last updated on 25/Apr/23 $$\frac{\mathrm{2}}{\mathrm{2}{x}−\mathrm{1}}−\mathrm{3}+\frac{\mathrm{3}}{\mathrm{3}{x}−\mathrm{1}}−\mathrm{2} \\ $$$$=\frac{\mathrm{2}−\mathrm{6}{x}+\mathrm{3}}{\mathrm{2}{x}−\mathrm{1}}\:+\frac{\mathrm{3}−\mathrm{6}{x}+\mathrm{2}}{\mathrm{3}{x}−\mathrm{1}} \\…