Question Number 191077 by Shrinava last updated on 17/Apr/23 $$\overset{\rightarrow} {\mathrm{a}}\:\centerdot\:\overset{\rightarrow} {\mathrm{b}}\:=\:\mathrm{4} \\ $$$$\overset{\rightarrow} {\mathrm{b}}\:\centerdot\:\overset{\rightarrow} {\mathrm{c}}\:=\:\mathrm{5} \\ $$$$\overset{\rightarrow} {\mathrm{7a}}\:=\:\overset{\rightarrow} {\mathrm{4b}}\:+\:\overset{\rightarrow} {\mathrm{2c}}\:\: \\ $$$$\mathrm{Find}:\:\:\:\mid\overset{\rightarrow} {\mathrm{c}}\:\mid\:=\:? \\…
Question Number 125539 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${The}\:{blue}\:{cubic}\:{curve}\:{is} \\ $$$$\:\:{y}={x}^{\mathrm{3}} −\mathrm{21}{x}−\mathrm{20} \\ $$$${Find}\:{p}. \\ $$ Answered…
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Question Number 59977 by mjay last updated on 16/May/19 $$\mathrm{4}×\left(\mathrm{5}+\mathrm{5}\right) \\ $$ Answered by meme last updated on 16/May/19 $$=\mathrm{40} \\ $$ Terms of Service…
Question Number 125504 by Study last updated on 11/Dec/20 $${n}!=\mathrm{2}^{\mathrm{10}} \centerdot\mathrm{10}!\left(\mathrm{1}\centerdot\mathrm{3}\centerdot\mathrm{5}\centerdot\mathrm{7}\centerdot\centerdot\centerdot\mathrm{19}\right)\:\:\:\:\:\:\:\:{n}=??? \\ $$$${help}\:{me} \\ $$ Answered by Dwaipayan Shikari last updated on 11/Dec/20 $$\mathrm{1}.\mathrm{3}.\mathrm{5}…{k}=\frac{\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}…\mathrm{2}{n}}{\mathrm{2}^{{k}} .{k}!}=\frac{\left(\mathrm{2}{k}\right)!}{\mathrm{2}^{{k}}…
Question Number 191024 by Rupesh123 last updated on 16/Apr/23 Answered by BaliramKumar last updated on 16/Apr/23 $$\mathrm{3600}\:=\:\mathrm{36}×\mathrm{100}\:=\:\mathrm{2}^{\mathrm{2}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{2}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{2}} \: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}^{\mathrm{4}} ×\mathrm{3}^{\mathrm{2}} ×\mathrm{5}^{\mathrm{2}}…
Question Number 191022 by Rupesh123 last updated on 16/Apr/23 Commented by Frix last updated on 16/Apr/23 $$\mathrm{1}? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 191027 by Rupesh123 last updated on 16/Apr/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 191019 by Albert12 last updated on 16/Apr/23 $$\mathrm{1}−\frac{\mathrm{1}−\frac{\mathrm{1}−\frac{\iddots}{\mathrm{5}}}{\mathrm{5}}}{\mathrm{5}}\:\:=? \\ $$ Answered by 073 last updated on 16/Apr/23 $$\mathrm{1}−\frac{\mathrm{x}}{\mathrm{5}}=\mathrm{x} \\ $$$$\mathrm{1}=\mathrm{x}+\frac{\mathrm{x}}{\mathrm{5}}=\frac{\mathrm{6x}}{\mathrm{5}} \\ $$$$\mathrm{6x}=\mathrm{5} \\…
Question Number 125464 by Mathgreat last updated on 11/Dec/20 Commented by Mathgreat last updated on 11/Dec/20 $$….. \\ $$ Terms of Service Privacy Policy Contact:…