Question Number 59929 by hhghg last updated on 16/May/19 $$\mathrm{Use}\:\mathrm{long}\:\mathrm{division}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{7485}/\mathrm{5} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 125465 by shaker last updated on 11/Dec/20 Answered by john_santu last updated on 11/Dec/20 $$\:{f}\:'\left(\frac{\mathrm{1}}{\mathrm{2}}\right) \\ $$ Commented by mathmax by abdo last…
Question Number 125442 by deepraj123 last updated on 11/Dec/20 $${find}\:\mathrm{2}^{\mathrm{2}^{\mathrm{2}^{\mathrm{2}} } } \\ $$ Answered by JDamian last updated on 11/Dec/20 $$\mathrm{65536} \\ $$ Terms…
Question Number 125428 by ajfour last updated on 11/Dec/20 Commented by ajfour last updated on 11/Dec/20 $${Find}\:{equation}\:{of}\:{circle}\:{passing} \\ $$$${through}\:\left(\mathrm{1},\mathrm{1}\right)\:{and}\:{P}\:\left({p},{p}^{\mathrm{2}} \right)\:{with} \\ $$$${radius}\:{t}<\mathrm{1}/\mathrm{2}\:.\: \\ $$ Terms…
Question Number 190947 by Shrinava last updated on 15/Apr/23 Answered by mr W last updated on 15/Apr/23 $$\frac{{BD}}{{AB}}=\frac{\mathrm{sin}\:\beta}{\mathrm{sin}\:\mathrm{30}}\:\:\:…\left({i}\right) \\ $$$$\frac{{AB}}{{AC}}=\frac{\mathrm{sin}\:\left(\beta+\mathrm{45}\right)}{\mathrm{sin}\:\mathrm{45}}\:\:\:…\left({ii}\right) \\ $$$$\left({i}\right)×\left({ii}\right): \\ $$$$\mathrm{1}=\frac{\mathrm{sin}\:\beta\:\mathrm{sin}\:\left(\beta+\mathrm{45}\right)}{\mathrm{sin}\:\mathrm{30}\:\mathrm{sin}\:\mathrm{45}} \\…
Question Number 190942 by mathlove last updated on 14/Apr/23 $$\left({x}+{y}\right)\left({x}^{\mathrm{2}} −{xy}+{y}^{\mathrm{2}} \right)=\mathrm{2} \\ $$$$\frac{{x}^{\mathrm{3}} {y}^{\mathrm{3}} }{{x}^{\mathrm{9}} +{y}^{\mathrm{9}} −\mathrm{8}}=? \\ $$ Answered by Frix last updated…
Question Number 190936 by Spillover last updated on 14/Apr/23 $$\mathrm{Determine}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:\mathrm{such}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\mathrm{e}^{\mathrm{sinh}\:^{−\mathrm{1}} \mathrm{x}} =\mathrm{1}+\mathrm{e}^{\mathrm{cosh}\:^{−\mathrm{1}} \mathrm{x}} \\ $$ Answered by mr W last updated on 14/Apr/23…
Question Number 190938 by Shrinava last updated on 14/Apr/23 Answered by Frix last updated on 15/Apr/23 $$\mathrm{tan}\:\mathrm{3}{x}\:−\mathrm{tan}\:{x}\:\mathrm{tan}\:\mathrm{11}{x}\:\mathrm{tan}\:\mathrm{13}{x}\:=\mathrm{0} \\ $$$$\mathrm{We}\:\mathrm{can}\:\mathrm{transform}\:\mathrm{this}\:\mathrm{to} \\ $$$$\mathrm{sin}\:\mathrm{28}{x}\:−\mathrm{sin}\:\mathrm{20}{x}\:+\mathrm{sin}\:\mathrm{4}{x}\:=\mathrm{0} \\ $$$${y}=\mathrm{4}{x} \\ $$$$\mathrm{sin}\:\mathrm{7}{y}\:−\mathrm{sin}\:\mathrm{5}{y}\:+\mathrm{sin}\:{y}\:=\mathrm{0}…
Question Number 190935 by Spillover last updated on 14/Apr/23 $$\mathrm{G}{iven}\:{that}\:\:\:\:\:\:\:\:\mathrm{sinh}\:^{−\mathrm{1}} {y}=\mathrm{sech}\:^{−\mathrm{1}} {y}\:\:\:\: \\ $$$${show}\:{that}\:\:\:\:\:\:\:\:\:{y}^{\mathrm{2}} =\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\:\:\: \\ $$$$ \\ $$ Answered by mehdee42 last updated on…
Question Number 190916 by Abdullahrussell last updated on 14/Apr/23 Commented by Rasheed.Sindhi last updated on 14/Apr/23 $$\mathrm{6}{A}+\mathrm{12}{B}+\mathrm{24}{C}=\mathrm{100} \\ $$$$\mathrm{6}\:\mid\:\left(\mathrm{6}{A}+\mathrm{12}{B}+\mathrm{24}{C}\right)\:\wedge\:\mathrm{6}\:\nmid\:\mathrm{100} \\ $$$$\Rightarrow\nexists\:{integer}\:{solution}! \\ $$ Terms of…