Question Number 188648 by Shrinava last updated on 04/Mar/23 Answered by SEKRET last updated on 04/Mar/23 $${Q}\mathrm{188572} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 188647 by Rupesh123 last updated on 04/Mar/23 Commented by mr W last updated on 05/Mar/23 $$\mathrm{4}. \\ $$$$\underset{{max}} {\mathrm{3}}^{\:\:\:\frac{\mathrm{1}}{\mathrm{3}}} >\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{4}^{\frac{\mathrm{1}}{\mathrm{4}}} >\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{5}}} >\mathrm{6}^{\frac{\mathrm{1}}{\mathrm{6}}}…
Question Number 188646 by Rupesh123 last updated on 04/Mar/23 Answered by Frix last updated on 04/Mar/23 $$\mathrm{Due}\:\mathrm{to}\:\mathrm{symmetry}\:\mathrm{the}\:\mathrm{minimum}\:\mathrm{of} \\ $$$$\left(\sqrt{{ab}}−\frac{\mathrm{1}}{\mathrm{2}}\right)\left(\sqrt{{ac}}−\frac{\mathrm{1}}{\mathrm{2}}\right)\left(\sqrt{{bc}}−\frac{\mathrm{1}}{\mathrm{2}}\right)\:\mathrm{is}\:\mathrm{at} \\ $$$${c}={b}={a} \\ $$$$\Rightarrow \\ $$$$\mathrm{3}\sqrt{{a}}=\mathrm{2}{a}\sqrt{{a}}\:\Rightarrow\:{a}=\frac{\mathrm{3}}{\mathrm{2}}…
Question Number 123108 by benjo_mathlover last updated on 23/Nov/20 Commented by benjo_mathlover last updated on 23/Nov/20 $$\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}+\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}\sqrt{\mathrm{3}}+\mathrm{3}\sqrt{\mathrm{2}}}+\frac{\mathrm{1}}{\mathrm{4}\sqrt{\mathrm{5}}+\mathrm{5}\sqrt{\mathrm{4}}}+ \\ $$$$…\:+\:\frac{\mathrm{1}}{\mathrm{4012008}\sqrt{\mathrm{4012009}}+\mathrm{4012009}\sqrt{\mathrm{4012008}}}\:? \\ $$ Commented by liberty last…
Question Number 188619 by Rupesh123 last updated on 03/Mar/23 Commented by Rupesh123 last updated on 03/Mar/23 Prove the inequality Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 123062 by pete last updated on 22/Nov/20 $$\mathrm{Erica}'\mathrm{s}\:\mathrm{age}\:\mathrm{is}\:\mathrm{8}\:\mathrm{years}\:\mathrm{and}\:\mathrm{her}\:\mathrm{mother}\:\mathrm{is}\:\mathrm{42}. \\ $$$$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{years}\:\mathrm{time}\:\mathrm{will}\:\mathrm{the}\:\mathrm{mother}\:\mathrm{be} \\ $$$$\mathrm{3}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old}\:\mathrm{as}\:\mathrm{her}\:\mathrm{daughter}? \\ $$ Answered by JDamian last updated on 22/Nov/20 $$\mathrm{42}+{y}=\mathrm{3}\left(\mathrm{8}+{y}\right) \\…
Question Number 57521 by rahul 19 last updated on 06/Apr/19 Commented by rahul 19 last updated on 06/Apr/19 $${Ans}−\left({a}\right)\mathrm{11}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 123053 by Snail last updated on 22/Nov/20 $${Find}\:{all}\:{P}\left({x}\right)\:{with}\:{real}\:{coefficients}\:{such}\:{that}\: \\ $$$${P}\left({x}^{\mathrm{2}} +{x}+\mathrm{1}\right)\:{divides}\:{P}\left({x}^{\mathrm{3}} −\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 188587 by Rupesh123 last updated on 03/Mar/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 57513 by pete last updated on 06/Apr/19 $$\mathrm{There}\:\mathrm{are}\:\mathrm{128}\:\mathrm{players}\:\mathrm{in}\:\mathrm{the}\:\mathrm{first}\:\mathrm{round} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{knockout}\:\mathrm{competition}.\:\mathrm{Half}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{players}\:\mathrm{were}\:\mathrm{knocked}\:\mathrm{out}\:\mathrm{in}\:\mathrm{each}\:\mathrm{round}. \\ $$$$\mathrm{How}\:\mathrm{many}\:\mathrm{players}\:\mathrm{took}\:\mathrm{part}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{fourth}\:\mathrm{round}?\:\mathrm{How}\:\mathrm{many}\:\mathrm{rounds}\:\mathrm{were}\:\mathrm{there} \\ $$$$\mathrm{in}\:\mathrm{this}\:\mathrm{competion}? \\ $$ Commented by mr…