Question Number 55888 by behi83417@gmail.com last updated on 05/Mar/19 $$\:\:\:\boldsymbol{\mathrm{a}}=\mathrm{1}+\boldsymbol{\mathrm{b}}+\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{b}}=\mathrm{1}+\boldsymbol{\mathrm{c}}+\boldsymbol{\mathrm{c}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{c}}=\boldsymbol{\mathrm{ab}}+\boldsymbol{\mathrm{a}}^{\mathrm{2}} +\boldsymbol{\mathrm{b}}^{\mathrm{2}} \\ $$$$\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\boldsymbol{\mathrm{a}},\:\:\boldsymbol{\mathrm{b}},\:\:\boldsymbol{\mathrm{c}}. \\ $$ Answered by MJS last updated on…
Question Number 121423 by Jamshidbek2311 last updated on 08/Nov/20 $${x}^{\mathrm{4}} −\mathrm{2}\sqrt{\mathrm{2}}{x}^{\mathrm{2}} −{x}+\mathrm{2}−\sqrt{\mathrm{2}}=\mathrm{0}\:\:\:{x}=? \\ $$ Answered by 2004 last updated on 08/Nov/20 $$\sqrt{\mathrm{2}}=\mathrm{t} \\ $$$$\mathrm{t}^{\mathrm{2}} −\mathrm{t}\left(\mathrm{2x}^{\mathrm{2}}…
Question Number 55887 by behi83417@gmail.com last updated on 05/Mar/19 $$\:\:\:{a}^{\mathrm{2}} +\mathrm{1}={b}^{\mathrm{2}} \\ $$$$\:\:\:{b}^{\mathrm{2}} +{c}^{\mathrm{2}} ={b}^{\mathrm{4}} \\ $$$$\:\:\:{ab}={c} \\ $$$$\:\:\:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\::\:\:\:\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}},\:\boldsymbol{\mathrm{c}}. \\ $$ Answered by MJS last…
Question Number 186941 by mathlove last updated on 12/Feb/23 $$\frac{{sinx}}{{x}^{{b}} }=\frac{\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{2}{n}+\mathrm{1}\right)!}{x}^{\mathrm{2}{n}+\mathrm{1}} }{{x}^{{b}} } \\ $$$${prove}\:{that} \\ $$ Commented by mr W last…
Question Number 186929 by cortano12 last updated on 12/Feb/23 $$\:\:{If}\:\begin{cases}{{B}+{R}+{P}=−\mathrm{1}}\\{{B}^{\mathrm{2}} +{R}^{\mathrm{2}} +{P}^{\mathrm{2}} =\mathrm{17}}\\{{B}^{\mathrm{3}} +{R}^{\mathrm{3}} +{P}^{\mathrm{3}} =\mathrm{11}}\end{cases} \\ $$$$\:{then}\:{B}^{\mathrm{5}} +{R}^{\mathrm{5}} +{P}^{\mathrm{5}} \:=? \\ $$ Answered by…
Question Number 55857 by Joel578 last updated on 05/Mar/19 $$\mathrm{Let}\:{A}\:\mathrm{and}\:{B}\:\mathrm{are}\:\mathrm{matrices}\:\mathrm{in}\:\mathbb{R}^{\mathrm{2017}×\mathrm{2017}} \:\mathrm{such}\:\mathrm{that}\: \\ $$$${A}^{−\mathrm{1}} \:=\:\left({A}\:+\:{B}\right)^{−\mathrm{1}} \:−\:{B}^{−\mathrm{1}} \\ $$$$\mathrm{and}\: \\ $$$$\mathrm{det}\left({A}^{−\mathrm{1}} \right)\:=\:\mathrm{2017} \\ $$$$\mathrm{Find}\:\:\mathrm{det}\left({B}\right) \\ $$ Terms…
Question Number 121359 by liberty last updated on 07/Nov/20 $$\mathrm{Find}\:\mathrm{all}\:\mathrm{n}\in\mathbb{N}\:\mathrm{such}\:\mathrm{that}\:\left(\mathrm{n}+\mathrm{3}\right)^{\mathrm{n}} \:=\:\underset{\mathrm{k}=\mathrm{3}} {\overset{\mathrm{n}+\mathrm{2}} {\sum}}\:\mathrm{k}^{\mathrm{n}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 55805 by bshahid010@gmail.com last updated on 04/Mar/19 Commented by MJS last updated on 04/Mar/19 $$\mathrm{b}=\mathrm{0}\:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\ $$$${b}={a}^{\mathrm{3}} \:\Rightarrow\:\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }{{ab}+\mathrm{1}}={a}^{\mathrm{2}} \\…
Question Number 186867 by Mingma last updated on 11/Feb/23 Answered by aba last updated on 11/Feb/23 $${x}=−\mathrm{5} \\ $$$$\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\right)^{−\mathrm{4}} =\left(\frac{\mathrm{5}}{\mathrm{4}}\right)^{\mathrm{4}} =\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{4}} \\ $$ Commented by…
Question Number 186864 by mathlove last updated on 11/Feb/23 $${if}\:\:{AB},{BA}\:{and}\:{BB}\:\:{three}\:\:{tow}\:{digits}\:{natural} \\ $$$${numbers}\:{if}\:\:\frac{\left({AB}+{BA}\right)}{{BB}}=\mathrm{4} \\ $$$${then}\:{find}\:{the}\:{maximum}\:{volue}\:{of} \\ $$$$\left({A}+{B}\right)=? \\ $$ Answered by mr W last updated on…