Question Number 186701 by Mingma last updated on 08/Feb/23 Commented by aba last updated on 08/Feb/23 $$\frac{\mathrm{4}}{\mathrm{5}} \\ $$ Commented by Mingma last updated on…
Question Number 55625 by gunawan last updated on 28/Feb/19 Commented by kaivan.ahmadi last updated on 28/Feb/19 $${the}\:{image}\:{is}\:{not}\:{clear} \\ $$ Commented by gunawan last updated on…
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Question Number 186690 by mathlove last updated on 08/Feb/23 Answered by a.lgnaoui last updated on 08/Feb/23 $$\mathrm{x}×\mathrm{2}^{\mathrm{x}^{\mathrm{2}} } =\mathrm{4}\:\:\:\:\left(\mathrm{x}=\mathrm{a}^{\mathrm{2}} \right) \\ $$$$\mathrm{x}^{\mathrm{2}} ×\mathrm{2}^{\mathrm{x}^{\mathrm{2}} } =\mathrm{4x}…
Question Number 55613 by ajfour last updated on 27/Feb/19 Commented by ajfour last updated on 27/Feb/19 $${red}\:{curve}\:{is}\:\:\:{y}={x}^{\mathrm{3}} +{px}+{q} \\ $$$${blue}\:{line}\:{is}\:{its}\:{tangent}\:{at}\:{its} \\ $$$${largest}\:{root}. \\ $$$${After}\:{rotation}\:{of}\:{the}\:{curve} \\…
Question Number 186682 by pete last updated on 08/Feb/23 $$\mathrm{Prove}\:\mathrm{the}\:\mathrm{following}\:\mathrm{set}\:\mathrm{identities} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{A}\cup\left(\mathrm{B}\cup\mathrm{C}\right)=\left(\mathrm{A}\cup\mathrm{B}\right)\cup\mathrm{C} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{A}\cup\varnothing=\mathrm{A} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{A}\cap\left(\mathrm{B}\cup\mathrm{C}\right)=\left(\mathrm{A}\cap\mathrm{B}\right)\cup\left(\mathrm{A}\cap\mathrm{C}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 121136 by zakirullah last updated on 05/Nov/20 Commented by Ar Brandon last updated on 05/Nov/20 In this form, a relation R is represented by the set of all ordered pairs belonging to R. For example, R = {(1, a), (2, b), (3, a), (4, c)} is a relation from the set {1, 2, 3, 4} to the set {a, b, c}. Answered by Ar Brandon last updated on…
Question Number 121127 by Study last updated on 05/Nov/20 $$\sqrt{\mathrm{3}+\mathrm{2}{i}}=? \\ $$ Answered by MJS_new last updated on 05/Nov/20 $$\mathrm{3}+\mathrm{2i}=\sqrt{\mathrm{13}}\mathrm{e}^{\mathrm{i}\:\mathrm{arctan}\:\frac{\mathrm{2}}{\mathrm{3}}} \\ $$$$\sqrt{\mathrm{3}+\mathrm{2i}}=\mathrm{13}^{\mathrm{1}/\mathrm{4}} \mathrm{e}^{\mathrm{i}\:\frac{\mathrm{arctan}\:\frac{\mathrm{2}}{\mathrm{3}}}{\mathrm{2}}} \\ $$$$\mathrm{or}…
Question Number 186657 by Mingma last updated on 08/Feb/23 Answered by Rasheed.Sindhi last updated on 08/Feb/23 $$\:\bullet\:\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{T}_{{k}} \:\:: \\ $$$$\begin{array}{|c|c|c|c|c|c|c|c|}{{T}_{{n}+\mathrm{1}} −{T}_{{n}} }&\hline{{a}_{{n}} }\\{\cancel{{T}_{\mathrm{2}}…