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Question Number 55070 by gunawan last updated on 17/Feb/19 $$\mathrm{Factorised}\:\mathrm{the}\:\mathrm{polynom}\:{z}^{\mathrm{4}} +\mathrm{1}\: \\ $$$$\mathrm{be}\:\mathrm{polynom}\:\mathrm{with}\:\mathrm{lower}\:\mathrm{degree}, \\ $$$$\mathrm{but}\:\mathrm{have}\:\mathrm{real}\:\mathrm{coefficient} \\ $$ Commented by mr W last updated on 17/Feb/19…
Question Number 55069 by gunawan last updated on 17/Feb/19 $$\mathrm{Known}\:\mathrm{analytic}\:\mathrm{function} \\ $$$${f}\left({z}\right)=\frac{\mathrm{2}\left({z}−\mathrm{2}\right)}{{z}\left({z}−\mathrm{4}\right)} \\ $$$$\mathrm{and}\:\mathrm{written}\:\mathrm{as}\:{f}\left({z}\right)=\underset{{n}=\mathrm{0}} {\overset{\propto} {\Sigma}}\:{a}_{{n}} \left({z}−\mathrm{1}\right)^{{n}} \\ $$$$\mathrm{The}\:\mathrm{value}\:\mathrm{of}\:{a}_{\mathrm{100}} \:\mathrm{is}… \\ $$ Commented by maxmathsup…
Question Number 55066 by gunawan last updated on 17/Feb/19 $$\mathrm{Find}\:\mathrm{radius}\:\mathrm{convergence}\:\mathrm{for}\:\mathrm{series} \\ $$$$\mathrm{1}−{z}^{\mathrm{2}} +{z}^{\mathrm{4}} −{z}^{\mathrm{6}} +… \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 120601 by Don08q last updated on 01/Nov/20 $$\:\mathrm{Find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:\mathrm{values}\:\mathrm{of}\:{x}\:\mathrm{for}\: \\ $$$$\:\mathrm{which}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of}\:\mathrm{the}\:\mathrm{binomial} \\ $$$$\:\left(\mathrm{2}\:−\:\mathrm{3}{x}\right)^{−\mathrm{4}} \:\mathrm{is}\:\mathrm{valid}.\: \\ $$$$\:{I}\:{need}\:{help}\:{with}\:{explanation}\:{please} \\ $$ Answered by Ar Brandon last updated…
Question Number 186124 by Rupesh123 last updated on 01/Feb/23 Commented by MJS_new last updated on 01/Feb/23 $$\mathrm{3}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} =\mathrm{25}\:\Rightarrow\:\mathrm{I}\:\mathrm{guess}\:{y}\in\left\{\mathrm{3},\:\mathrm{4}\right\} \\ $$$$\mathrm{with}\:{y}=\mathrm{4}\:\Rightarrow\:{x}=\frac{\mathrm{215}}{\mathrm{106}}\pm\frac{\mathrm{27}\sqrt{\mathrm{17}}}{\mathrm{106}}\mathrm{i} \\ $$$$\Rightarrow\:{y}=\mathrm{3} \\ $$…
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Question Number 55039 by behi83417@gmail.com last updated on 16/Feb/19 $$\alpha\:{and}\:\beta,{are}\:\mathrm{2}\:{roots}\:{of}\:{eq}: \\ $$$$\:\:\:\:{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0}\:{with}\:{conditions}: \\ $$$$\:\:\:\:\begin{cases}{\alpha^{\mathrm{2}} =\beta+{b}}\\{\beta^{\mathrm{2}} =\alpha+{a}}\end{cases} \\ $$$${find}:\:\:\boldsymbol{{c}}\:{in}\:{terms}\:{of}:\:\boldsymbol{{a}}\:\:{and}\:\:\boldsymbol{{b}}. \\ $$ Commented by mr W…
Question Number 186105 by HeferH last updated on 01/Feb/23 $$\:{a}^{\mathrm{2}} \:+\:\mathrm{1}\:\:=\:{a} \\ $$$$\:{a}^{\mathrm{12}} \:+\:{a}^{\mathrm{6}} \:+\:\mathrm{1}\:=\:?\: \\ $$ Answered by Rasheed.Sindhi last updated on 01/Feb/23 $${a}^{\mathrm{2}}…