Question Number 218366 by Mingma last updated on 08/Apr/25 Commented by Mingma last updated on 08/Apr/25 Find the dimensions Commented by zetamaths last updated on 08/Apr/25 $${the}\:{dimension}\:{is}\:\mathrm{2}\:\:\Leftrightarrow{dim}\left({W}\right)=\mathrm{2}\:{because}…
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Question Number 218328 by hardmath last updated on 06/Apr/25 Answered by vnm last updated on 08/Apr/25 $$ \\ $$$$\mathrm{Let}\:\mathrm{us}\:\mathrm{introduce}\:\mathrm{a}\:\mathrm{coordinate} \\ $$$$\mathrm{system}\:\mathrm{in}\:\mathrm{which}\:\mathrm{the}\:\mathrm{OX}\:\mathrm{axis}\:\mathrm{is} \\ $$$$\mathrm{co}−\mathrm{directed}\:\mathrm{with}\:\mathrm{the}\:\mathrm{vector}\:\mathrm{AC} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{origin}\:\mathrm{is}\:\mathrm{in}\:\mathrm{the}\:\mathrm{middle}\:…
Question Number 218280 by vahid last updated on 04/Apr/25 Answered by Frix last updated on 05/Apr/25 $$\mathrm{i}^{\mathrm{4}{n}} =\mathrm{1} \\ $$$$\mathrm{i}^{\mathrm{4}{n}+\mathrm{1}} =\mathrm{i} \\ $$$$\mathrm{i}^{\mathrm{4}{n}+\mathrm{2}} =−\mathrm{1} \\…
Question Number 218262 by hardmath last updated on 03/Apr/25 Commented by hardmath last updated on 03/Apr/25 $$\mathrm{ABCD}\:-\:\mathrm{Rectangular} \\ $$$$\mathrm{AK}\:\bot\:\mathrm{BM} \\ $$$$\mathrm{S}_{\bigtriangleup\boldsymbol{\mathrm{AKB}}} \:=\:\mathrm{S}_{\bigtriangleup\boldsymbol{\mathrm{BMC}}} \:=\:\mathrm{S}_{\boldsymbol{\mathrm{AKMD}}} \\ $$$$\mathrm{DM}\:=\:\boldsymbol{\mathrm{a}}…
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Question Number 218202 by Rojarani last updated on 01/Apr/25 Commented by Frix last updated on 01/Apr/25 $$\mathrm{I}\:\mathrm{think}\:\mathrm{it}'\mathrm{s}\:\mathrm{9}−\mathrm{4}\sqrt{\mathrm{5}} \\ $$ Commented by Rojarani last updated on…
Question Number 218195 by david2409 last updated on 01/Apr/25 $${P}=\frac{\Sigma{Fz}}{{Npil}} \\ $$ Answered by MrGaster last updated on 02/Apr/25 $$\left(\mathrm{1}\right):\Sigma{Fz}=\int_{\partial\Sigma} {FzdS} \\ $$$${Npil}=\int_{\partial\Sigma} {dS} \\…
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