Question Number 181625 by Shrinava last updated on 27/Nov/22 $$\mathrm{K}-\mathrm{Lemoine}'\mathrm{s}\:,\:\mathrm{I}-\mathrm{incenter}\:\mathrm{in}\:\bigtriangleup\mathrm{ABC}. \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{KA}^{\mathrm{4}} +\mathrm{KB}^{\mathrm{4}} +\mathrm{KC}^{\mathrm{4}} \:\geqslant\:\mathrm{IA}^{\mathrm{4}} +\mathrm{IB}^{\mathrm{4}} +\mathrm{IC}^{\mathrm{4}} \\ $$ Terms of Service Privacy…
Question Number 116091 by I want to learn more last updated on 30/Sep/20 $$\mathrm{Is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{formular}\:\mathrm{to}\:\mathrm{tell}\:\mathrm{how}\:\mathrm{many}\:\mathrm{times}\:\mathrm{a}\:\mathrm{digit}\:\mathrm{occur}\:\mathrm{in}\:\mathrm{an}\:\mathrm{interval}. \\ $$$$ \\ $$$$\mathrm{e}.\mathrm{g}.\:\:\mathrm{How}\:\mathrm{many}\:\mathrm{times}\:\mathrm{digits}\:\:\mathrm{2}\:\:\mathrm{occur}\:\mathrm{between}\:\:\mathrm{1}\:−\:\mathrm{100} \\ $$ Answered by 1549442205PVT last updated…
Question Number 181627 by Shrinava last updated on 27/Nov/22 $$\mathrm{Point}\:\:\mathrm{E}\:\:\mathrm{is}\:\mathrm{marked}\:\mathrm{on}\:\mathrm{side}\:\:\mathrm{AD}\:\:\mathrm{in} \\ $$$$\mathrm{rhombus}\:\:\mathrm{ABCD}.\:\mathrm{If}\:\:\mathrm{AC}\:=\:\mathrm{6}\:\sqrt{\mathrm{10}}\:\:\mathrm{and} \\ $$$$\mathrm{BD}\:=\:\mathrm{2}\:\sqrt{\mathrm{10}}\:.\:\mathrm{How}\:\mathrm{many}\:\mathrm{different} \\ $$$$\mathrm{integer}\:\mathrm{values}\:\mathrm{can}\:\mathrm{a}\:\mathrm{piece}\:\mathrm{of}\:\:\mathrm{BE}\:\:\mathrm{take}? \\ $$ Commented by Shrinava last updated on 28/Nov/22…
Question Number 181593 by mnjuly1970 last updated on 27/Nov/22 $$ \\ $$$$\:\:\:\:\:\:\:\mathrm{I}\:\mathrm{f}\:,\:\:\:\:{a}^{\:\mathrm{2}} \:+\mathrm{5}\:{b}^{\:\mathrm{2}} \:+\:\mathrm{4}{c}^{\:\mathrm{2}} =\:\mathrm{4}{b}\:\left({a}\:+{c}\:\right) \\ $$$$\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\mathrm{then}\:,\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:: \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{E}\:=\:\frac{\:\left(\:{b}+\:{c}\:−{a}\:\right)^{\:\mathrm{3}} }{\:{abc}}\:=\:?\:\:\:\:\left(\:{abc}\:\neq\:\mathrm{0}\:\right)\:\:\:\:\:\:\: \\…
Question Number 181595 by mathlove last updated on 27/Nov/22 Answered by madhabnandi last updated on 27/Nov/22 $$\mathrm{65}°+\mathrm{25}°+\mathrm{30}°=\mathrm{120}° \\ $$ Answered by Agnibhoo98 last updated on…
Question Number 116059 by Study last updated on 30/Sep/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{n}!}{\mathrm{3}^{{n}+\mathrm{1}} } \\ $$ Answered by MWSuSon last updated on 30/Sep/20 $$\mathrm{Do}\:\mathrm{you}\:\mathrm{want}\:\mathrm{to}\:\mathrm{test}\:\mathrm{for}\:\mathrm{convergence}? \\ $$…
Question Number 116057 by Study last updated on 30/Sep/20 $$\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\frac{\mathrm{3}}{\mathrm{3}{n}+\mathrm{1}}=? \\ $$ Answered by mindispower last updated on 30/Sep/20 $$\underset{{n}\geqslant\mathrm{0}} {\sum}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{3}{n}+\mathrm{1}\right)}? \\…
Question Number 116056 by Study last updated on 30/Sep/20 $$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{5}^{{n}} }{{n}!}=? \\ $$ Answered by Dwaipayan Shikari last updated on 30/Sep/20 $$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty}…
Question Number 181590 by pete last updated on 27/Nov/22 $$\mathrm{Mr}.\:\mathrm{Jibril}\:\mathrm{is}\:\mathrm{four}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old}\:\mathrm{as}\:\mathrm{his}\:\mathrm{son}. \\ $$$$\mathrm{Four}\:\mathrm{years}\:\mathrm{ago},\:\mathrm{he}\:\mathrm{was}\:\mathrm{seven}\:\mathrm{times}\:\mathrm{as}\:\mathrm{old} \\ $$$$\mathrm{as}\:\mathrm{his}\:\mathrm{son}.\:\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{years}\:\mathrm{will}\:\mathrm{Mr} \\ $$$$\mathrm{Jibril}'\mathrm{s}\:\mathrm{age}\:\mathrm{be}\:\mathrm{twice}\:\mathrm{his}\:\mathrm{son}'\mathrm{s}\:\mathrm{age}? \\ $$ Answered by Acem last updated on 27/Nov/22…
Question Number 50511 by behi83417@gmail.com last updated on 17/Dec/18 $${refer}\:{to}\:{question}\:#\mathrm{50278} \\ $$$$\sqrt{{a}+\sqrt{{a}−{x}}}+\sqrt{{a}−\sqrt{{a}+{x}}}=\mathrm{2}{x} \\ $$ Answered by behi83417@gmail.com last updated on 17/Dec/18 Commented by behi83417@gmail.com last…