Question Number 46245 by rpseelam last updated on 23/Oct/18 $$\frac{\mathrm{1}}{\mathrm{1}.\mathrm{3}.\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{3}.\mathrm{5}.\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{5}.\mathrm{7}.\mathrm{9}}+…..{nth}\:{term} \\ $$ Commented by maxmathsup by imad last updated on 23/Oct/18 $${let}\:{S}_{{n}} =\sum_{{k}=\mathrm{0}} ^{{n}} \:\:\frac{\mathrm{1}}{\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{2}{k}+\mathrm{3}\right)\left(\mathrm{2}{k}+\mathrm{5}\right)}\:\:\:{let}\:{find}\:\:{S}_{{n}}…
Question Number 177307 by a.lgnaoui last updated on 03/Oct/22 $${Resoudre}\:{l}\:{equation}\: \\ $$$$\frac{{a}}{\mathrm{cos}\:^{\mathrm{3}} {x}}+\frac{{b}}{\mathrm{cos}\:{x}}=\frac{{c}}{\mathrm{sin}\:{x}}\:\:\:\: \\ $$$${a},{b},{c}\:{reels}\:\:\:\:{x}#\left\{{k}\frac{\pi}{\mathrm{2}}\:\:{k}\in\mathbb{Z}\right\} \\ $$ Answered by Frix last updated on 04/Oct/22 $${t}=\mathrm{tan}\:{x}\:\Leftrightarrow\:{x}=\mathrm{tan}^{−\mathrm{1}}…
Question Number 177306 by a.lgnaoui last updated on 03/Oct/22 $${Resoudre}\:{l}\:{equaation} \\ $$$$\:\:{a}\mathrm{cos}\:{x}+{b}\mathrm{sin}\:{x}={c} \\ $$$$\left({a},{b},{c}\right)\in\mathbb{R}^{\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by Ar Brandon last updated on…
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Question Number 111724 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{How}\:\mathrm{many}\:\mathrm{real}\:\mathrm{numbers}\:\mathrm{x}\:\mathrm{satisfy}\:\mathrm{the} \\ $$$$\mathrm{equation}\:\mathrm{3}^{\mathrm{2x}+\mathrm{2}} −\mathrm{3}^{\mathrm{x}+\mathrm{3}} −\mathrm{3}^{\mathrm{x}} +\mathrm{3}=\mathrm{0}\:? \\ $$ Commented by mohammad17 last updated on…
Question Number 46186 by Saorey last updated on 22/Oct/18 $$\mathrm{please}\:\mathrm{help}\:\mathrm{me}! \\ $$$$\mathrm{S}=\mathrm{1}^{\mathrm{2}} \mathrm{q}^{\mathrm{1}} +\mathrm{2}^{\mathrm{2}} \mathrm{q}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} \mathrm{q}^{\mathrm{3}} +…+\mathrm{n}^{\mathrm{2}} \mathrm{q}^{\mathrm{n}} =? \\ $$ Commented by maxmathsup…
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Question Number 46139 by pieroo last updated on 21/Oct/18 $$\mathrm{A}\:\mathrm{park}\:\mathrm{has}\:\mathrm{the}\:\mathrm{shape}\:\mathrm{of}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{hexagon} \\ $$$$\mathrm{of}\:\mathrm{sides}\:\mathrm{2km}\:\mathrm{each}.\:\mathrm{A}\:\mathrm{boy}\:\mathrm{walks}\:\mathrm{a}\:\mathrm{distance} \\ $$$$\mathrm{of}\:\mathrm{5km}\:\mathrm{along}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the}\:\mathrm{park}.\: \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{direct}\:\mathrm{distance}\:\mathrm{between}\: \\ $$$$\mathrm{the}\:\mathrm{start}\:\mathrm{point}\:\mathrm{and}\:\mathrm{the}\:\mathrm{end}\:\mathrm{point}? \\ $$ Commented by malwaan last updated…
Question Number 177193 by peter frank last updated on 02/Oct/22 $$\int\:\:\:\frac{\mathrm{x}^{\mathrm{2021}} }{\mathrm{x}^{\mathrm{2022}} +\mathrm{x}^{\mathrm{4043}} }\mathrm{dx} \\ $$ Answered by cortano1 last updated on 02/Oct/22 $$\frac{\mathrm{1}}{\mathrm{x}\left(\mathrm{x}^{\mathrm{2021}} +\mathrm{1}\right)}\:=\frac{\mathrm{1}}{\mathrm{x}}\:−\frac{\mathrm{x}^{\mathrm{2020}}…
Question Number 46110 by Tawa1 last updated on 21/Oct/18 Commented by math khazana by abdo last updated on 22/Oct/18 $$\Delta=\mathrm{1}−\mathrm{4}=−\mathrm{3}=\left({i}\sqrt{\mathrm{3}}\right)^{\mathrm{2}} \Rightarrow\alpha=\frac{\mathrm{1}+{i}\sqrt{\mathrm{3}}}{\mathrm{2}}\:{and}\:\beta=\frac{\mathrm{1}−{i}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\Rightarrow\alpha={e}^{{i}\frac{\pi}{\mathrm{3}}} \:{and}\:\beta\:={e}^{−{i}\frac{\pi}{\mathrm{3}}} \:\Rightarrow\alpha^{\mathrm{101}}…