Question Number 175374 by MikeH last updated on 28/Aug/22 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\underset{{i}\:=\:\mathrm{1}} {\overset{{n}} {\sum}}\frac{{i}+{j}}{{i}^{\mathrm{2}} +{j}^{\mathrm{2}} }−\left(\frac{\pi}{\mathrm{2}}+\:\mathrm{ln}\:\mathrm{2}\right){n}\:+\:\mathrm{ln}\:{n}\right)\:=\:? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 175333 by mnjuly1970 last updated on 27/Aug/22 $$ \\ $$$$\:\:\:{solve}\:\left({x}\:\in\:\mathbb{R}\:\right). \\ $$$$ \\ $$$$\:\:\lfloor\:\frac{\:\mathrm{2}^{\:{x}} \:+\mathrm{1}}{\mathrm{3}}\:\rfloor\:+\:\lfloor\:\mathrm{4}^{\:\frac{{x}}{\mathrm{2}}} \:\rfloor\:=\:\mathrm{4} \\ $$$$\:\:\:\:−−−−−−\: \\ $$ Answered by mr…
Question Number 109754 by joki last updated on 25/Aug/20 $$\mathrm{1}.{specify}\:{value}\:{absolute}\:{x}\:{if}\:? \\ $$$$ \\ $$$${b}.\mid\mathrm{2}{x}+\mathrm{3}\mid+{x}−\mathrm{3}=\mathrm{0} \\ $$$$ \\ $$ Answered by Her_Majesty last updated on 25/Aug/20…
Question Number 175284 by zzzrot last updated on 26/Aug/22 Answered by MJS_new last updated on 26/Aug/22 $$\frac{\mathrm{92}{x}+\mathrm{89}{y}}{{x}+{y}}=\mathrm{91} \\ $$$$\mathrm{92}{x}+\mathrm{89}{y}=\mathrm{91}{x}+\mathrm{91}{y} \\ $$$${x}=\mathrm{2}{y} \\ $$$$\frac{{x}}{{y}}=\mathrm{2} \\ $$…
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Question Number 44200 by Tawa1 last updated on 23/Sep/18 Commented by MJS last updated on 23/Sep/18 $${A} \\ $$$${term}\mathrm{1}×{term}\mathrm{2}=\mathrm{0}\:\Leftrightarrow\:{term}\mathrm{1}=\mathrm{0}\:\vee\:{term}\mathrm{2}=\mathrm{0} \\ $$$$\mathrm{e}^{{x}} −\mathrm{e}^{\pi} =\mathrm{0}\:\Rightarrow\:{x}=\pi \\ $$$$\mathrm{e}^{{x}}…
Question Number 109721 by Algoritm last updated on 25/Aug/20 Answered by 1549442205PVT last updated on 25/Aug/20 $$\mathrm{We}\:\mathrm{need}\:\mathrm{have}\:\mathrm{the}\:\mathrm{condition}\:\mathrm{that} \\ $$$$\mathrm{6}−\mathrm{x}>\mathrm{0}\:\mathrm{for}\:\mathrm{logarithm}\:\mathrm{is}\:\mathrm{meaning}.\mathrm{Then} \\ $$$$\mathrm{log}_{\mathrm{3}} \left(\mathrm{6}−\mathrm{x}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{6}}=\mathrm{x} \\ $$$$\Leftrightarrow\mathrm{log}_{\mathrm{3}}…
Question Number 175250 by Shrinava last updated on 24/Aug/22 $$\mathrm{If}\:\mathrm{in}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{and}\:\:\mathrm{A}\:=\:\frac{\mathrm{2}\pi}{\mathrm{3}}\:\:\mathrm{then}: \\ $$$$\left(\sqrt{\frac{\mathrm{1}}{\mathrm{sinB}}}\right)^{\mathrm{3}} +\:\left(\sqrt{\frac{\mathrm{1}}{\mathrm{sinC}}}\right)^{\mathrm{3}} \geqslant\:\mathrm{4}\:\sqrt{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 109699 by bemath last updated on 25/Aug/20 $$\:\:\:\:\:{x}\left({x}−\mathrm{1}\right)^{\mathrm{2}} \:\geqslant\:\mathrm{12}\left({x}−\mathrm{1}\right) \\ $$ Answered by bemath last updated on 25/Aug/20 $$\Leftrightarrow\:\left({x}−\mathrm{1}\right)\left({x}\left({x}−\mathrm{1}\right)−\mathrm{12}\right)\geqslant\mathrm{0} \\ $$$$\Leftrightarrow\left({x}−\mathrm{1}\right)\left({x}−\mathrm{4}\right)\left({x}+\mathrm{3}\right)\geqslant\mathrm{0} \\ $$$$\Leftrightarrow\:−\mathrm{3}\leqslant{x}\leqslant\mathrm{1}\:\cup\:{x}\geqslant\mathrm{4}…
Question Number 175230 by infinityaction last updated on 24/Aug/22 Answered by Ar Brandon last updated on 24/Aug/22 $${S}=\underset{{n}=\mathrm{3}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\overset{{n}} {\:}{C}_{\mathrm{3}} }=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{n}!×\mathrm{3}!}{\left({n}+\mathrm{3}\right)!} \\…