Question Number 109029 by nimnim last updated on 20/Aug/20 $${Find}\:{the}\:{value}\left({s}\right)\:{of}\:{a},{b}\:{and}\:{c}\:\:{if}: \\ $$$$\left({x}+{a}\right)\left({x}+\mathrm{2020}\right)+\mathrm{1}=\left({x}+{b}\right)\left({x}+{c}\right) \\ $$$${where}\:{a},{b}\:{and}\:{c}\:{are}\:{natural}\:{numbers}. \\ $$ Answered by floor(10²Eta[1]) last updated on 21/Aug/20 $$\mathrm{x}^{\mathrm{2}} +\left(\mathrm{2020}+\mathrm{a}\right)\mathrm{x}+\mathrm{2020a}+\mathrm{1}=\mathrm{x}^{\mathrm{2}}…
Question Number 43488 by peter frank last updated on 11/Sep/18 $${if}\:{the}\:{root}\:{of}\:\:{x}^{\mathrm{3}} +{px}_{} ^{\mathrm{2}} +{qx}+\mathrm{30}=\mathrm{0}\:{are} \\ $$$${in}\:{the}\:{ratio}\:\mathrm{2}:\mathrm{3}:\mathrm{5}{find}\:{the}\:{value}\:{of}\:{p}\:{and}\:{q} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 11/Sep/18…
Question Number 43486 by ajfour last updated on 11/Sep/18 Commented by ajfour last updated on 11/Sep/18 $${Find}\:{the}\:{equation}\:{to}\:{the}\:{above} \\ $$$${curve}. \\ $$ Answered by MJS last…
Question Number 174552 by Tawa11 last updated on 03/Aug/22 Commented by Rasheed.Sindhi last updated on 04/Aug/22 $$\mathrm{n}=\mathrm{12}\:;\:\mathrm{Please}\:\mathrm{confirm}\:\mathrm{the}\:\mathrm{answer}. \\ $$ Commented by Tawa11 last updated on…
Question Number 43471 by Cheyboy last updated on 11/Sep/18 Answered by tanmay.chaudhury50@gmail.com last updated on 11/Sep/18 $${one}\:{is}\:{x}\:{another}\:{is}\:\mathrm{2}−{x} \\ $$$${y}={x}^{\mathrm{3}} +\left(\mathrm{2}−{x}\right)^{\mathrm{2}} \\ $$$$\frac{{dy}}{{dx}}=\mathrm{3}{x}^{\mathrm{2}} +\mathrm{2}\left(\mathrm{2}−{x}\right)\left(−\mathrm{1}\right)=\mathrm{3}{x}^{\mathrm{2}} −\mathrm{4}+\mathrm{2}{x} \\…
Question Number 109005 by Study last updated on 20/Aug/20 $${i}^{{i}} =? \\ $$ Answered by floor(10²Eta[1]) last updated on 20/Aug/20 $$\mathrm{i}=\mathrm{e}^{\frac{\mathrm{i}\pi}{\mathrm{2}}} \Rightarrow\mathrm{i}^{\mathrm{i}} =\left(\mathrm{e}^{\frac{\mathrm{i}\pi}{\mathrm{2}}} \right)^{\mathrm{i}} =\mathrm{e}^{\frac{−\pi}{\mathrm{2}}}…
Question Number 109004 by Don08q last updated on 20/Aug/20 $$\overset{} {\:}\:\:{Solve}\:\:\:\:\mid\mathrm{3}{x}+\mathrm{5}\mid\:=\:\mid\mathrm{4}{x}−\mathrm{3}\mid \\ $$$$\:\:\:{where}\:{x}\:\in\:\mathbb{R} \\ $$$$ \\ $$ Answered by bemath last updated on 20/Aug/20 $$\Rightarrow\:\left(\mathrm{3}{x}+\mathrm{5}+\mathrm{4}{x}−\mathrm{3}\right)\left(\mathrm{3}{x}+\mathrm{5}−\mathrm{4}{x}+\mathrm{3}\right)=\mathrm{0}…
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Question Number 174538 by infinityaction last updated on 03/Aug/22 $$\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{and} \\ $$$$\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:“\mathrm{x}''\:\mathrm{if} \\ $$$$\mathrm{x}+\mathrm{y}+\mathrm{z}\:=\:\mathrm{6},\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} \:=\:\mathrm{18}, \\ $$$$\mathrm{for}\:\mathrm{real}\:\mathrm{values}\:\mathrm{of}\:“\mathrm{x},\mathrm{y}\:\mathrm{and}\:\mathrm{z}'' \\ $$ Commented by JDamian last…
Question Number 174533 by mnjuly1970 last updated on 03/Aug/22 Answered by behi834171 last updated on 03/Aug/22 $$\boldsymbol{{x}}^{\mathrm{2}} =\mathrm{2}\boldsymbol{{x}}+\mathrm{1}\Rightarrow\boldsymbol{{x}}^{\mathrm{2}} −\mathrm{2}\boldsymbol{{x}}−\mathrm{1}=\mathrm{0}\Rightarrow\begin{cases}{\boldsymbol{\alpha}+\boldsymbol{\beta}=\mathrm{2}}\\{\boldsymbol{\alpha}.\boldsymbol{\beta}=−\mathrm{1}}\end{cases} \\ $$$$\boldsymbol{{x}}^{\mathrm{3}} =\mathrm{2}\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{x}}=\mathrm{5}\boldsymbol{{x}}+\mathrm{2} \\ $$$$\boldsymbol{{x}}^{\mathrm{4}}…