Question Number 174532 by Shrinava last updated on 03/Aug/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 108984 by bemath last updated on 20/Aug/20 $$\:\:\:\underset{\approx} {\mathcal{B}}{e}\underset{\approx} {\mathcal{M}}{at}\underset{\approx} {{h}} \\ $$$$\left(\mathrm{1}\right)\underset{{n}\:=\:\mathrm{1}} {\overset{\mathrm{100}} {\sum}}\left[\:\frac{\mathrm{2}}{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{1}}\:\right]\:? \\ $$$$\left(\mathrm{2}\right)\:\frac{\mathrm{2}}{\mathrm{4}.\mathrm{9}}\:+\:\frac{\mathrm{2}}{\mathrm{9}.\mathrm{14}}\:+\:\frac{\mathrm{2}}{\mathrm{14}.\mathrm{19}}\:+\:…\:+\:\frac{\mathrm{2}}{\mathrm{49}.\mathrm{54}}\:? \\ $$$$\left(\mathrm{3}\right)\:{Given}\:{a}\:{quadratic}\:{equation} \\ $$$${x}^{\mathrm{2}} \left(\underset{{i}\:=\:\mathrm{1}}…
Question Number 43449 by ajfour last updated on 10/Sep/18 Answered by MJS last updated on 10/Sep/18 $${y}={ax}^{\mathrm{3}} +{bx}^{\mathrm{2}} +{cx}+{d} \\ $$$${y}'=\mathrm{3}{ax}^{\mathrm{2}} +\mathrm{2}{bx}+{c} \\ $$$${P}=\begin{pmatrix}{−\mathrm{1}}\\{\mathrm{2}}\end{pmatrix}\:\:{Q}=\begin{pmatrix}{\mathrm{3}}\\{−\mathrm{1}}\end{pmatrix} \\…
Question Number 174512 by ahdal last updated on 03/Aug/22 $${how}\:{many}\:{integer}\:{a},{b}\in{z}^{+} \\ $$$${a}^{\mathrm{5}} −{b}^{\mathrm{5}} =\mathrm{10}\left({b}+\mathrm{1}\right)^{\mathrm{2}} −\mathrm{9} \\ $$$$ \\ $$ Answered by MJS_new last updated on…
Question Number 108967 by bobhans last updated on 20/Aug/20 $$\:\:\overset{\bigstar} {{b}}\overset{\bigstar} {{o}}\overset{\bigstar} {{b}}\overset{\sim} {{h}}\overset{\sim} {{a}}\overset{\sim} {{n}}\overset{\sim} {{s}} \\ $$$$\mathrm{1}+\frac{\mathrm{4}}{\mathrm{11}}+\frac{\mathrm{9}}{\mathrm{121}}+\frac{\mathrm{16}}{\mathrm{1331}}+\frac{\mathrm{25}}{\mathrm{14641}}+… \\ $$ Answered by john santu…
Question Number 43416 by peter frank last updated on 10/Sep/18 Commented by peter frank last updated on 15/Sep/18 $${help} \\ $$ Terms of Service Privacy…
Question Number 174487 by mnjuly1970 last updated on 02/Aug/22 Answered by dragan91 last updated on 02/Aug/22 $$ \\ $$$$\mathrm{x}^{\mathrm{2}} −\mathrm{25x}=\mathrm{x}+\mathrm{5}\sqrt{\mathrm{x}} \\ $$$$\mathrm{x}\left(\mathrm{x}−\mathrm{25}\right)=\sqrt{\mathrm{x}}\left(\sqrt{\mathrm{x}}+\mathrm{5}\right) \\ $$$$\mathrm{x}\left(\sqrt{\mathrm{x}}−\mathrm{5}\right)\left(\sqrt{\mathrm{x}}+\mathrm{5}\right)=\sqrt{\mathrm{x}}\left(\sqrt{\mathrm{x}}+\mathrm{5}\right) \\…
Question Number 174479 by Michaelfaraday last updated on 02/Aug/22 Commented by mr W last updated on 03/Aug/22 $${see}\:{Q}\mathrm{147791} \\ $$ Terms of Service Privacy Policy…
Question Number 174464 by Shrinava last updated on 01/Aug/22 $$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC} \\ $$$$\mathrm{R}\in\left(\mathrm{AB}\right)\:,\:\mathrm{P}\in\left(\mathrm{BC}\right)\:,\:\mathrm{Q}\in\left(\mathrm{CA}\right) \\ $$$$\mathrm{AR}=\mathrm{3}\:,\:\mathrm{RB}=\mathrm{1}\:,\:\mathrm{BP}=\mathrm{6}\:,\:\mathrm{PC}=\mathrm{2}\:,\:\mathrm{CQ}=\mathrm{5}\:,\:\mathrm{QA}=\mathrm{4} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{PQ}\:+\:\mathrm{QR}\:+\:\mathrm{RP}\:>\:\frac{\mathrm{21}}{\mathrm{2}} \\ $$ Terms of Service Privacy Policy…
Question Number 43391 by gunawan last updated on 10/Sep/18 $${x}^{\mathrm{2}} +{x}={y}^{\mathrm{4}} +{y}^{\mathrm{3}} +{y}^{\mathrm{2}} +{y} \\ $$$${x}^{\mathrm{4}} +\left({x}+\mathrm{1}\right)^{\mathrm{4}} ={y}^{\mathrm{2}} +\left({y}+\mathrm{1}\right)^{\mathrm{2}} \\ $$$$\mathrm{find}\:{x}\:\mathrm{and}\:{y}\:\:\mathrm{of}\:\mathrm{is}\ldots \\ $$$$ \\ $$…