Question Number 173997 by mnjuly1970 last updated on 22/Jul/22 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:{If}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\sqrt[{\mathrm{3}}]{{x}}\:−\:\mathrm{3}\:=\:\sqrt[{\mathrm{3}}]{{x}−\mathrm{36}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:{then}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\:\mathrm{2}} −\mathrm{1}}{{x}}\:=\:?\: \\ $$$$\:\:\:\:\:\:\: \\ $$ Answered by…
Question Number 173992 by dragan91 last updated on 22/Jul/22 Commented by mr W last updated on 22/Jul/22 $${no}\:{answer}\:{seems}\:{to}\:{be}\:{correct}.\:{i}\:{got} \\ $$$$\mathrm{5456}. \\ $$ Answered by mr…
Question Number 173984 by Shrinava last updated on 22/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 42910 by veerendravyas1974@gmail.com last updated on 04/Sep/18 $${whatshouldbesubtructedfrom}\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right){toget}\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right)? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 04/Sep/18 $$\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right)−{x}=\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right) \\ $$$${x}=\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right)−\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right) \\ $$$${x}=\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}+\mathrm{3}{a}−\mathrm{7}{b}−\mathrm{16} \\…
Question Number 173981 by AgniMath last updated on 22/Jul/22 Answered by Frix last updated on 22/Jul/22 $${a}\geqslant\mathrm{0}\wedge{b}\geqslant\mathrm{0}\:\Rightarrow\:\mathrm{we}\:\mathrm{can}\:\mathrm{square} \\ $$$$\frac{\left({a}+{b}\right)^{\mathrm{2}} }{\mathrm{4}}\geqslant{ab} \\ $$$$\left({a}+{b}\right)^{\mathrm{2}} \geqslant\mathrm{4}{ab} \\ $$$${a}^{\mathrm{2}}…
Question Number 173978 by dragan91 last updated on 22/Jul/22 $$\mathrm{Solve}\:\mathrm{system}\:\mathrm{of}\:\mathrm{equations}: \\ $$$$\mathrm{x}+\frac{\mathrm{3x}−\mathrm{y}}{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} }=\mathrm{3} \\ $$$$\mathrm{y}−\frac{\mathrm{x}+\mathrm{3y}}{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} }=\mathrm{0} \\ $$$$ \\ $$ Answered by Frix…
Question Number 42906 by Cheyboy last updated on 04/Sep/18 $${x}^{{x}} +{y}^{{y}} =\mathrm{31} \\ $$$${x}+{y}\:=\:\mathrm{5} \\ $$$${Find}\:{x}\:{and}\:{y} \\ $$ Answered by Joel578 last updated on 04/Sep/18…
Question Number 108430 by Rasikh last updated on 16/Aug/20 Answered by Sarah85 last updated on 17/Aug/20 $$\mathrm{42}!\:\mathrm{has}\:\mathrm{got}\:\mathrm{more}\:\mathrm{2s}\:\mathrm{than}\:\mathrm{3s},\:\mathrm{so}\:\mathrm{we}\:\mathrm{have}\:\mathrm{to} \\ $$$$\mathrm{count}\:\mathrm{the}\:\mathrm{3s} \\ $$$$\mathrm{3},\:\mathrm{6},\:\mathrm{12},\:\mathrm{15},\:\mathrm{21},\:\mathrm{24},\:\mathrm{30},\:\mathrm{33},\:\mathrm{39},\:\mathrm{42}\:/\:\mathrm{10}\:\mathrm{3s} \\ $$$$\mathrm{9},\:\mathrm{18},\:\mathrm{36}\:/\:\mathrm{6}\:\mathrm{3s} \\ $$$$\mathrm{27}\:/\:\mathrm{3}\:\mathrm{3s}…
Question Number 173970 by mnjuly1970 last updated on 22/Jul/22 Commented by Tawa11 last updated on 22/Jul/22 $$\mathrm{Great}\:\mathrm{sir} \\ $$ Commented by infinityaction last updated on…
Question Number 173956 by Shrinava last updated on 21/Jul/22 Commented by dragan91 last updated on 22/Jul/22 $$ \\ $$$$\sqrt{\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{2}} }+\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{3}} }=\mathrm{x}+\mathrm{y} \\ $$$$\mathrm{x}^{\mathrm{3}}…