Question Number 173882 by Shrinava last updated on 20/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173869 by mnjuly1970 last updated on 20/Jul/22 $$ \\ $$$$\:{If},\:\:\:\left(\:\frac{\sqrt{\mathrm{10}}\:+\sqrt{\mathrm{6}}+\mathrm{2}}{\:\sqrt{\mathrm{5}}\:−\sqrt{\mathrm{3}\:}\:+\:\sqrt{\mathrm{2}}}\:\right)^{\:\mathrm{2}} =\:{a}\:+\:\sqrt{{b}} \\ $$$$\:\:\:\:\:\:\:\:{then}.\:\:\:\:\:\:\:\:{a}\:\:,\:\:\:{b}\:=\:? \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$ Commented by infinityaction last updated on…
Question Number 173871 by mathlove last updated on 20/Jul/22 $$\mathrm{2}^{{x}} \centerdot\mathrm{3}^{{y}} =\mathrm{4} \\ $$$$\mathrm{2}^{{y}} \centerdot\mathrm{3}^{{x}} =\mathrm{6}\:\:\:\:\:\:\:{prove}\:{that}\:\:{xy}={z}\left({z}+\mathrm{1}\right) \\ $$$$\mathrm{6}^{{z}} =\mathrm{2} \\ $$ Commented by dragan91 last…
Question Number 173864 by blackmamba last updated on 20/Jul/22 $$\:\:\:\:\sqrt{{x}}\:\geqslant\:\frac{{x}^{\mathrm{4}} −\mathrm{2}{x}^{\mathrm{3}} +\mathrm{2}{x}−\mathrm{1}}{{x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} +\mathrm{2}{x}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 108316 by bemath last updated on 16/Aug/20 $$\:\:\:\:\frac{\bigtriangledown\mathcal{B}{e}\mathcal{M}{ath}\bigtriangledown}{\bigtriangleup} \\ $$$${If}\:{x}^{\mathrm{4}} +{x}^{\mathrm{2}} \:=\:\frac{\mathrm{11}}{\mathrm{5}}\:,\:{find}\:{the}\:{value}\:{of} \\ $$$$\Omega\:=\:\sqrt[{\mathrm{3}}]{\frac{{x}+\mathrm{1}}{{x}−\mathrm{1}}}\:+\:\sqrt[{\mathrm{3}}]{\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}}}\: \\ $$ Answered by bobhans last updated on 16/Aug/20…
Question Number 42776 by Tawa1 last updated on 02/Sep/18 $$\mathrm{Solve}:\:\:\:\:\:\mathrm{q}^{\mathrm{4}} \:−\:\mathrm{40q}^{\mathrm{2}} \:+\:\mathrm{q}\:+\:\mathrm{384}\:=\:\mathrm{0} \\ $$ Answered by MJS last updated on 02/Sep/18 $$\mathrm{I}\:\mathrm{found}\:\mathrm{no}\:\mathrm{useable}\:\mathrm{exact}\:\mathrm{solution} \\ $$$${q}_{\mathrm{1}} \approx−\mathrm{4}.\mathrm{95762}…
Question Number 108309 by bemath last updated on 16/Aug/20 $$\:\:\:\:\:\frac{\bigtriangleup\mathcal{B}{e}\mathcal{M}{ath}\bigtriangleup}{\therefore} \\ $$$${Given}\:\sqrt{\mathrm{5}+\sqrt{\mathrm{9}+\mathrm{2}\sqrt{\mathrm{15}}}}\:+\sqrt{\mathrm{5}−\sqrt{\mathrm{9}+\mathrm{2}\sqrt{\mathrm{15}}}}\:=\:{x} \\ $$$${find}\:{the}\:{value}\:{of}\:\left({x}−\frac{\mathrm{1}}{{x}}\right)^{\mathrm{2}} \\ $$ Answered by bobhans last updated on 16/Aug/20 $$\:\:\frac{\in{bobhans}\in}{\Bumpeq} \\…
Question Number 42765 by jbm last updated on 02/Sep/18 Commented by MJS last updated on 02/Sep/18 $$\approx\mathrm{1}.\mathrm{4331274267223}\:\left({n}=\mathrm{10},\:\mathrm{the}\:\mathrm{difference}\:\mathrm{to}\right. \\ $$$$\left.\mathrm{the}\:\mathrm{value}\:\mathrm{with}\:{n}=\mathrm{11}\:\mathrm{is}\:\mathrm{smaller}\:\mathrm{than}\:\mathrm{10}^{−\mathrm{13}} \right) \\ $$$$ \\ $$ Terms…
Question Number 173834 by mnjuly1970 last updated on 19/Jul/22 Commented by infinityaction last updated on 20/Jul/22 $$\boldsymbol{{f}}\left(\boldsymbol{{x}}\right)\boldsymbol{{g}}\left(\boldsymbol{{x}}\right)\boldsymbol{{h}}\left(\boldsymbol{{x}}\right)\:=\:\left(\boldsymbol{\mathrm{tan}}^{\mathrm{7}} \boldsymbol{{x}}+\boldsymbol{\mathrm{cot}}^{\mathrm{7}} \boldsymbol{{x}}\right)\left(\boldsymbol{\mathrm{tan}}^{\mathrm{8}} \boldsymbol{{x}}−\boldsymbol{\mathrm{cot}}^{\mathrm{8}} \boldsymbol{{x}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:×\:\:\left(\boldsymbol{\mathrm{tan}}^{\mathrm{9}} \boldsymbol{{x}}+\boldsymbol{\mathrm{cot}}^{\mathrm{9}} \boldsymbol{{x}}\right)…
Question Number 42761 by Meritguide1234 last updated on 02/Sep/18 Terms of Service Privacy Policy Contact: info@tinkutara.com