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Question Number 42195 by math khazana by abdo last updated on 20/Aug/18 $${let}\:{p}\left({x}\right)={x}^{\mathrm{10}} −\mathrm{1} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{roots}\:{of}\:{p}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{factorize}\:{i}\:{nside}\:\:{C}\left[{x}\right]\:{p}\left({x}\left\{\right.\right. \\ $$$$\left.\mathrm{3}\right)\:{factorize}\:{inside}\:{R}\left[{x}\right]\:{p}\left({x}\right)\:. \\ $$ Answered by maxmathsup…
Question Number 173254 by mr W last updated on 09/Jul/22 $${solve}\:{for}\:{x},{y},{z}\:\in{R} \\ $$$${x}+{y}+{z}=\sqrt{\mathrm{3}} \\ $$$${xy}+{yz}+{zx}=\mathrm{1} \\ $$ Commented by AgniMath last updated on 09/Jul/22 $$\mathrm{almost}\:\mathrm{similar}\:\mathrm{to}\:\mathrm{my}\:\mathrm{recent}\:\mathrm{question}…
Question Number 173250 by Shrinava last updated on 08/Jul/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\int_{\mathrm{0}} ^{\:\boldsymbol{\mathrm{x}}} \:\frac{\mathrm{t}^{\mathrm{2}} }{\left(\mathrm{t}\:\centerdot\:\mathrm{sinh}\:\mathrm{t}\:−\:\mathrm{cosh}\:\mathrm{t}\right)^{\mathrm{2}} }\:\mathrm{dt}\:=\:\mathrm{0} \\ $$ Answered by Ar Brandon last updated on…
Question Number 42176 by Lakshman Kumar last updated on 19/Aug/18 $$\mathrm{81}\sqrt{} \\ $$ Commented by MrW3 last updated on 20/Aug/18 $$\sqrt{\mathrm{81}}=+\mathrm{9}\:\neq\:−\mathrm{9} \\ $$ Terms of…
Question Number 173240 by mnjuly1970 last updated on 08/Jul/22 Commented by a.lgnaoui last updated on 09/Jul/22 Commented by a.lgnaoui last updated on 09/Jul/22 $${m}+{n}=\frac{{i}}{\mathrm{2}}−\mathrm{1}\:\:\:{and}\:\:\:\:−\:\frac{{i}}{\mathrm{2}}−{i} \\…
Question Number 173242 by AgniMath last updated on 08/Jul/22 Commented by som(math1967) last updated on 09/Jul/22 $$\mathrm{2}\:\:\:\:\:\:\:\:\:\:\boldsymbol{{a}},\boldsymbol{{b}},\boldsymbol{{c}}\in\boldsymbol{{R}} \\ $$ Answered by AgniMath last updated on…
Question Number 173228 by mathlove last updated on 08/Jul/22 Answered by Frix last updated on 08/Jul/22 $$\mathrm{let}\:\mathrm{sin}\:\frac{\pi}{\mathrm{11}}\:={s}\:\wedge\:\mathrm{cos}\:\frac{\pi}{\mathrm{11}}\:={c} \\ $$$$\left(\mathrm{1}\right)\:\Rightarrow\:{y}={s}^{\mathrm{2}} {x}−\frac{{s}^{\mathrm{4}} }{\mathrm{4}} \\ $$$$\left(\mathrm{2}\right)\:\Rightarrow\:{y}=\frac{{x}}{{c}^{\mathrm{2}} }+\frac{{c}^{\mathrm{2}} }{\mathrm{4}}…
Question Number 173224 by cortano1 last updated on 08/Jul/22 Answered by Frix last updated on 08/Jul/22 $${x}=\mathrm{6} \\ $$ Commented by Michaelfaraday last updated on…