Question Number 42030 by Akashuac last updated on 17/Aug/18 $$\mathrm{x}+\frac{\mathrm{1}}{\mathrm{x}}=\mathrm{5}\:\:\:\:\mathrm{x}^{\mathrm{5}} +\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{5}} }=? \\ $$ Commented by maxmathsup by imad last updated on 17/Aug/18 $${x}+\frac{\mathrm{1}}{{x}}=\mathrm{5}\:\Rightarrow\left({x}+\frac{\mathrm{1}}{{x}}\right)^{\mathrm{5}} \:=\mathrm{5}^{\mathrm{5}}…
Question Number 42009 by 737954 last updated on 16/Aug/18 $$\mathrm{if}\:\left(\mathrm{a}+\mathrm{b}\omega+\mathrm{c}\omega^{\mathrm{2}} \right)+\left(\mathrm{a}\omega+\mathrm{b}\omega^{\mathrm{2}} +\mathrm{c}\right)^{\mathrm{2}} +\left(\mathrm{a}\omega^{\mathrm{2}} +\mathrm{b}+\mathrm{c}\omega\right)^{\mathrm{2}} =\mathrm{0} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}\:\mathrm{a}=\mathrm{c}\:\:\mathrm{or}\:\:\:\mathrm{a}+\mathrm{c}=\mathrm{2b} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 173082 by Shrinava last updated on 06/Jul/22 Answered by mr W last updated on 06/Jul/22 Commented by mr W last updated on 06/Jul/22…
Question Number 173072 by Shrinava last updated on 06/Jul/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{complex}\:\mathrm{numbers}: \\ $$$$\begin{cases}{\frac{\mid\mathrm{x}\mid^{\mathrm{2}} }{\mathrm{3}}\:\:+\:\:\frac{\mid\mathrm{y}\mid^{\mathrm{2}} }{\mathrm{5}}\:\:=\:\:\frac{\mid\mathrm{x}\:+\:\mathrm{y}\mid^{\mathrm{2}} }{\mathrm{8}}}\\{\mathrm{10x}\:\:+\:\:\mathrm{y}\:\:=\:\:\mathrm{7}\:\:+\:\:\mathrm{14}\boldsymbol{\mathrm{i}}}\end{cases} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173078 by AgniMath last updated on 06/Jul/22 Answered by som(math1967) last updated on 07/Jul/22 $$\boldsymbol{{let}}\:\boldsymbol{{b}}−\boldsymbol{{c}}=\boldsymbol{{x}}\:,\left(\boldsymbol{{a}}−\boldsymbol{{b}}\right)=\boldsymbol{{y}},\boldsymbol{{c}}−\boldsymbol{{a}}=\boldsymbol{{z}} \\ $$$$\therefore\:\boldsymbol{{x}}+\boldsymbol{{y}}+\boldsymbol{{z}}=\mathrm{0} \\ $$$$\left(\boldsymbol{{x}}+\boldsymbol{{y}}\right)^{\mathrm{2}} =\left(−\boldsymbol{{z}}\right)^{\mathrm{2}} \\ $$$$\:\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{y}}^{\mathrm{2}}…
Question Number 173064 by Shrinava last updated on 06/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 173058 by Shrinava last updated on 06/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 41985 by Penguin last updated on 16/Aug/18 $$\mathrm{Prove}\:{e}^{{x}} \geqslant{x}+\mathrm{1}\:\forall{x}\in\mathbb{R}\:\mathrm{in}\:\mathrm{as}\:\mathrm{many}\:\mathrm{ways} \\ $$$$\mathrm{as}\:\mathrm{you}\:\mathrm{can}\:\mathrm{show} \\ $$ Commented by maxmathsup by imad last updated on 16/Aug/18 $${let}\:{f}\left({x}\right)\:={e}^{{x}}…
Question Number 41984 by Tawa1 last updated on 16/Aug/18 $$\mathrm{solve}\:\mathrm{simultaneously}:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}\sqrt{\mathrm{k}}\:\:+\:\mathrm{h}\:=\:\mathrm{9}\:\:\:…….\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{k}\:+\:\mathrm{2}\sqrt{\mathrm{h}}\:\:=\:\mathrm{3}\:\:…….\:\left(\mathrm{ii}\right) \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18 $${x}+\mathrm{2}\sqrt{{y}}\:−\mathrm{9}=\mathrm{0} \\ $$$$\mathrm{2}\sqrt{{x}}\:+{y}−\mathrm{3}=\mathrm{0} \\…
Question Number 173049 by Shrinava last updated on 05/Jul/22 Answered by MJS_new last updated on 06/Jul/22 $$\mathrm{let}\:{x}\leqslant{y}\leqslant{z}\leqslant{t}\:\Rightarrow\:{x}={y}=\mathrm{0}\wedge{z}={t}=\mathrm{723} \\ $$ Answered by dragan91 last updated on…