Question Number 172820 by Mikenice last updated on 01/Jul/22 Answered by CElcedricjunior last updated on 02/Jul/22 $$\frac{\left(\boldsymbol{\mathrm{x}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}}\right)^{\boldsymbol{\mathrm{m}}} \left(\boldsymbol{\mathrm{x}}−\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}}\right)^{\boldsymbol{\mathrm{n}}} }{\left(\boldsymbol{\mathrm{y}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}\right)^{\boldsymbol{\mathrm{m}}} \left(\boldsymbol{\mathrm{y}}−\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}\right)^{\boldsymbol{\mathrm{n}}} }=\left(\frac{\boldsymbol{\mathrm{x}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}}}{\boldsymbol{\mathrm{y}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}}\right)^{\boldsymbol{\mathrm{m}}} ×\left(\frac{\boldsymbol{\mathrm{x}}−\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}}}{\boldsymbol{\mathrm{y}}−\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}}\right)^{\boldsymbol{\mathrm{n}}} \\ $$$$=\left[\left(\frac{\boldsymbol{\mathrm{xy}}+\mathrm{1}}{\boldsymbol{\mathrm{y}}}\right)×\left(\frac{\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{xy}}+\mathrm{1}}\right)\right]^{\boldsymbol{\mathrm{n}}} ×\left[\left(\frac{\boldsymbol{\mathrm{xy}}−\mathrm{1}}{\boldsymbol{\mathrm{y}}}\right)×\left(\frac{\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{xy}}−\mathrm{1}}\right)\right]^{\boldsymbol{\mathrm{m}}}…
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Question Number 107262 by udaythool last updated on 09/Aug/20 $$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{requirement}\:\mathrm{of}\:\mathrm{last} \\ $$$$\mathrm{axioms}\:\mathrm{i}.\mathrm{e}.\:\mathrm{1}{v}={v}\:\forall\:{v}\in{V}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{definition}\:\mathrm{of}\:\mathrm{vector}\:\mathrm{space}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 172802 by mnjuly1970 last updated on 01/Jul/22 $$ \\ $$$$\:\:\:\: \\ $$$$\:\mathrm{Q}:\:\:\:\:\mathrm{how}\:\mathrm{many}\:\mathrm{natural}\:\mathrm{numbers}\:\mathrm{less}\:\mathrm{than} \\ $$$$\:\:\:\:\:\:\mathrm{6000}\:\:,\:\mathrm{exist}\:\mathrm{such}\:\mathrm{as}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of} \\ $$$$\:\:\:\:\:\:\:\:\mathrm{their}\:\mathrm{digits}\:\:\mathrm{equal}\:\mathrm{to}\:\:\:\mathrm{8}\:? \\ $$$$\:\mathrm{choices}:\:\:\:\:\mathrm{155}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{165}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{164}\:\:\:\:\:\:\:\:\:\:\mathrm{158} \\ $$$$\:\:\:\:\:\:\: \\ $$$$ \\…
Question Number 172798 by mnjuly1970 last updated on 01/Jul/22 $$ \\ $$$$\:\:\:\:\:\mathrm{a}^{\:\mathrm{2}} −\mathrm{1}\:\overset{\mathrm{10}} {\equiv}\:\mathrm{14a}\:+\mathrm{6} \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{a}^{\:\mathrm{2}} \:+\mathrm{a}\:\overset{\mathrm{10}} {\equiv}\:?\:\:\:\: \\ $$$$\:\:\mathrm{choices}:\:\:\:\:\:\mathrm{2}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{7}\:\:\:\:\:\:\:\:\:\:\:\mathrm{8} \\ $$$$\: \\…
Question Number 41720 by Tawa1 last updated on 11/Aug/18 $$\mathrm{Difference}\:\mathrm{of}\:\mathrm{last}\:\mathrm{two}\:\mathrm{digits}\:\mathrm{of}\:\:\:\:\mathrm{2019}^{\mathrm{2019}^{\mathrm{2019}} } \:\:\:\mathrm{is}\:\:? \\ $$ Commented by MJS last updated on 12/Aug/18 $$=\mathrm{2019}×\mathrm{2019}×\mathrm{2019}×… \\ $$$$\mathrm{so}\:\mathrm{we}\:\mathrm{first}\:\mathrm{need}\:\mathrm{to}\:\mathrm{know}\:\mathrm{the}\:\mathrm{sequence}\:\mathrm{of}\:\mathrm{the} \\…
Question Number 172787 by mnjuly1970 last updated on 01/Jul/22 $$ \\ $$$$\:\:\:\mathrm{In}\:\:\mathrm{A}\overset{\Delta} {\mathrm{B}C}\:\:,\:\mathrm{prove}\:\:\mathrm{that}\: \\ $$$$\:{sin}\left(\frac{\mathrm{A}}{\mathrm{2}}\right).{sin}\left(\frac{\mathrm{B}}{\mathrm{2}}\right).{sin}\left(\frac{\mathrm{C}}{\mathrm{2}}\right)\:\leqslant\:\frac{\mathrm{1}}{\mathrm{8}} \\ $$$$\:\:\:−−−−−−−− \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 41710 by Tawa1 last updated on 11/Aug/18 $$\mathrm{Factorize}:\:\:\mathrm{60x}^{\mathrm{3}} \mathrm{y}\:+\:\mathrm{115x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}} \:−\:\mathrm{120xy}^{\mathrm{3}} \\ $$ Answered by alex041103 last updated on 11/Aug/18 $$\mathrm{60x}^{\mathrm{3}} \mathrm{y}\:+\:\mathrm{115x}^{\mathrm{2}} \mathrm{y}^{\mathrm{2}}…
Question Number 107242 by mnjuly1970 last updated on 09/Aug/20 $$\:\:\:\:\:…{question}… \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:{prove}\:{that}: \\ $$$$\:{if}\:\:{a},{b},{c}\in\mathbb{R}^{+} \:{then}: \\ $$$$\:\:\:\:\:\clubsuit\:\:\:\sqrt{{a}}\:+\sqrt{{b}}+\sqrt{{c}}>\:\sqrt{{a}+{b}+{c}}\:\clubsuit\: \\ $$$$\:\:\:\:\:\:\:….{sincerly}\:{yours}… \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:…\:\mathscr{M}.\mathscr{N}… \\ $$$$\:\: \\ $$…
Question Number 172775 by Shrinava last updated on 01/Jul/22 Answered by mahdipoor last updated on 02/Jul/22 $${get}\:{side}\:{of}\:{square}\:=\:{a} \\ $$$${and}\:{cotB}+{cotC}={b} \\ $$$$, \\ $$$${BQ}={MQ}.{cotB}={a}.{cotB} \\ $$$${PC}={NP}.{cotC}={a}.{cotC}…