Question Number 106730 by I want to learn more last updated on 06/Aug/20 Answered by Dwaipayan Shikari last updated on 06/Aug/20 $$\underset{{n}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{n}^{\mathrm{2}} \left({n}+\mathrm{1}\right)^{\mathrm{2}}…
Question Number 172267 by Mikenice last updated on 25/Jun/22 Answered by mr W last updated on 25/Jun/22 $$\left({a}\right) \\ $$$${T}={mg}\:\mathrm{sin}\:\theta \\ $$$$\left({b}\right) \\ $$$${N}={mg}\:\mathrm{cos}\:\theta \\…
Question Number 172264 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\mathrm{log}_{\mathrm{2}} \left(\mathrm{log}_{\mathrm{8}} {x}\right)=\mathrm{log}_{\mathrm{8}} \left(\mathrm{log}_{\mathrm{2}} {x}\right)\:\:\:\: \\ $$$$\mathrm{log}_{\mathrm{2}} \left(\frac{\mathrm{log}_{\mathrm{2}} {x}\:}{\mathrm{log}_{\mathrm{2}}…
Question Number 172261 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)^{\mathrm{2016}} \left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)\left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)\right\}^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:\right)^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} \right\}^{\mathrm{2016}} \\…
Question Number 106727 by Algoritm last updated on 06/Aug/20 Answered by Her_Majesty last updated on 06/Aug/20 $${x}=\mathrm{1}\wedge{y}=\mathrm{0}\:\Rightarrow\:{min}\:\left({x}+{y}\right)\:=\mathrm{1} \\ $$ Commented by Her_Majesty last updated on…
Question Number 172259 by mr W last updated on 25/Jun/22 $${solve} \\ $$$${x}^{{x}} =\mathrm{3}^{\frac{\mathrm{1}}{{x}}} \\ $$ Answered by mr W last updated on 25/Jun/22 $${x}\mathrm{ln}\:{x}=\frac{\mathrm{ln}\:\mathrm{3}}{{x}}…
Question Number 172262 by Mikenice last updated on 25/Jun/22 Answered by Rasheed.Sindhi last updated on 25/Jun/22 $$\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}}\:=\sqrt{{n}}\:>\mathrm{0} \\ $$$$\left(\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}}\:\right)^{\mathrm{3}} =\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\ $$$$\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}\sqrt[{\mathrm{3}}]{\mathrm{3}…}}\:=\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\ $$$$\mathrm{3}\sqrt{{n}}=\left(\sqrt{{n}}\:\right)^{\mathrm{3}} \\…
Question Number 172244 by mr W last updated on 24/Jun/22 $${solve}\: \\ $$$$\mathrm{2}^{{x}^{\mathrm{2}} } −\mathrm{40}{x}=\mathrm{0} \\ $$$$ \\ $$$$\left[{Q}#\mathrm{172086}\:{reposted}\right] \\ $$ Commented by mr W…
Question Number 41167 by Cheyboy last updated on 02/Aug/18 $${The}\:{LCM}\:{and}\:{the}\:{GCF}\:{of}\:{three} \\ $$$${intergers}\:{are}\:\mathrm{180}\:{and}\:\mathrm{3}\:{respectively}. \\ $$$${Two}\:{numbers}\:{are}\:\mathrm{45}\:{and}\:\mathrm{60}. \\ $$$${What}\:{is}\:{the}\:{third}\:{number} \\ $$ Answered by MJS last updated on 02/Aug/18…
Question Number 41160 by behi83417@gmail.com last updated on 02/Aug/18 Commented by behi83417@gmail.com last updated on 02/Aug/18 $${solve}\:{for}\:{x}\neq{y}\neq{z}. \\ $$ Commented by MJS last updated on…