Question Number 106272 by Muhsang S L last updated on 04/Aug/20 $$\sqrt{\mathrm{1}\:+\:\sqrt{\mathrm{5}\:+\sqrt{\mathrm{11}\:+\:\sqrt{\mathrm{19}\:+\:\sqrt{\mathrm{29}\:+\:\sqrt{\ldots}}}}}}\:=\:? \\ $$ Commented by Her_Majesty last updated on 04/Aug/20 $$\mathrm{2} \\ $$ Answered…
Question Number 171809 by Mikenice last updated on 23/Jun/22 $${solve}\:{for}\:{x}\:{and}\:{y}: \\ $$$${x}^{\mathrm{3}} +\mathrm{12}{xy}^{\mathrm{2}} =\mathrm{679} \\ $$$$\mathrm{9}{x}^{\mathrm{2}} {y}+\mathrm{12}{y}^{\mathrm{3}} =\mathrm{978}. \\ $$ Terms of Service Privacy Policy…
Question Number 171810 by Shrinava last updated on 21/Jun/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\mathrm{x}^{\mathrm{32}} \:\:+\:\:\mathrm{x}^{\mathrm{16}} \:\:+\:\:\mathrm{y}^{\mathrm{2}} \:\:=\:\:\mathrm{2}\sqrt{\mathrm{2}}\:\:\mathrm{x}^{\mathrm{12}} \:\mathrm{y} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 171800 by mnjuly1970 last updated on 21/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 106259 by qwerty111 last updated on 03/Aug/20 Commented by qwerty111 last updated on 03/Aug/20 $$\sqrt{{xy}}\:=\:? \\ $$ Answered by john santu last updated…
Question Number 171773 by Mikenice last updated on 20/Jun/22 $${make}\:{T}\:{the}\:{subject}\:{of}\:{the}\:{formula}\:{if} \\ $$$${s}={ut}+\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\ $$ Answered by thfchristopher last updated on 21/Jun/22 $${T}?\:\mathrm{O}{r}\:{t}? \\ $$$${s}={ut}+\frac{\mathrm{1}}{\mathrm{2}}{at}^{\mathrm{2}} \\…
Question Number 171772 by Mikenice last updated on 20/Jun/22 $${solve}: \\ $$$${x}^{{x}} =\mathrm{27}{x}^{\mathrm{2}} .\:{find}\:{x} \\ $$ Commented by mr W last updated on 21/Jun/22 $${you}\:{can}\:{only}\:{approximate}.…
Question Number 106239 by chichi last updated on 03/Aug/20 $$ \\ $$$$\mathrm{A}\:\mathrm{rope}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10cm}\:\mathrm{is}\:\mathrm{used}\:\mathrm{to}\:\mathrm{form}\:\mathrm{as} \\ $$$$\mathrm{ector}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{radius}\:\mathrm{35cm}\:\mathrm{What}\:\mathrm{ish} \\ $$$$\mathrm{te}\:\mathrm{size}\:\mathrm{of}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sector} \\ $$ Answered by prakash jain last updated on…
Question Number 171771 by Mikenice last updated on 20/Jun/22 $${solve}: \\ $$$$\mathrm{2}^{{x}} =\mathrm{4}{x}.\:{find}\:{x} \\ $$ Answered by mathocean1 last updated on 20/Jun/22 $${S}_{\mathbb{R}} =\left\{\mathrm{4}\right\} \\…
Question Number 106233 by malwaan last updated on 03/Aug/20 $$\left({x}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({x}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{yz} \\ $$$$\left({y}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({y}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{xz} \\ $$$$\left({z}^{\mathrm{2}} \:+\:\mathrm{1}\right)\left({z}\:−\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{2017}{xy} \\ $$$${x}\:\geqslant\:\mathrm{1}\:;\:{y}\:\geqslant\:\mathrm{1}\:;\:{z}\:\geqslant\:\mathrm{1} \\ $$$${prove}\:{that}\:\:\:{x}\:=\:{y}\:=\:{z}\:= \\…