Question Number 171360 by Shrinava last updated on 13/Jun/22 $$\mathrm{Solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\mathrm{log}_{\mathrm{9}} \:\mathrm{x}\:\:\centerdot\:\:\mathrm{log}_{\mathrm{2}} \:\left(\mathrm{7}\:−\:\mathrm{x}\right)\:=\:\mathrm{1} \\ $$ Answered by MJS_new last updated on 13/Jun/22 $$\frac{\mathrm{ln}\:{x}}{\mathrm{2ln}\:\mathrm{3}}×\frac{\mathrm{ln}\:\left(\mathrm{7}−{x}\right)}{\mathrm{ln}\:\mathrm{2}}=\mathrm{1} \\…
Question Number 105822 by bemath last updated on 01/Aug/20 $$\mathcal{G}{iven}\:{f}\left({x}+\frac{\mathrm{1}}{\mathrm{2}{x}}\right)\:=\:{x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{4}{x}^{\mathrm{2}} }+\mathrm{3}{x}+\frac{\mathrm{3}}{\mathrm{2}{x}} \\ $$$${find}\:{f}\left(\mathrm{2}\right)\: \\ $$ Answered by bobhans last updated on 01/Aug/20 $$\Rightarrow{x}^{\mathrm{2}} +\frac{\mathrm{1}}{\mathrm{4}{x}^{\mathrm{2}}…
Question Number 171346 by Mr.D.N. last updated on 13/Jun/22 $$\:\:\mathrm{solve}: \\ $$$$\:\:\:\frac{\mathrm{m}+\left(\mathrm{mn}^{\mathrm{2}} \right)^{\mathrm{1}/\mathrm{3}} +\left(\mathrm{m}^{\mathrm{2}} \mathrm{n}\right)^{\mathrm{1}/\mathrm{3}} }{\mathrm{m}−\mathrm{n}}\:×\:\frac{\left(\mathrm{m}^{\mathrm{1}/\mathrm{3}} −\mathrm{n}^{\mathrm{1}/\mathrm{3}} \right)}{\mathrm{m}^{\mathrm{1}/\mathrm{3}} } \\ $$ Commented by infinityaction last…
Question Number 171342 by mathlove last updated on 13/Jun/22 Commented by infinityaction last updated on 13/Jun/22 $$\mathrm{3} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 171318 by sciencestudent last updated on 12/Jun/22 $${if}\:{f}\left({x}\right)={x}^{\frac{\mathrm{13}}{\mathrm{5}}} \:{and}\:{g}\left({x}\right)=\sqrt[{\mathrm{5}}]{{x}^{\mathrm{13}} }\: \\ $$$${Which}\:{one}\:{is}\:{correct}? \\ $$$$\left.\mathrm{1}\left.\right)\:{f}\left({x}\right)={g}\left({x}\right)\:\:\:\:\mathrm{2}\right){f}\left({x}\right)\neq{g}\left({x}\right) \\ $$ Commented by mr W last updated on…
Question Number 171311 by mathlove last updated on 12/Jun/22 $$\mathrm{2}^{{x}^{−{i}^{\mathrm{2}} } } +\mathrm{2}^{{x}^{\mathrm{2}} } =\mathrm{2}^{{x}^{\mathrm{3}} −{i}^{\mathrm{2}} } \\ $$$${x}=? \\ $$ Terms of Service Privacy…
Question Number 171296 by dragan91 last updated on 11/Jun/22 Commented by Rasheed.Sindhi last updated on 13/Jun/22 $${For}\:{x}>\mathrm{5}\:\:\:\:{xy}^{\mathrm{3}} +{xy}^{\mathrm{3}} +\mathrm{2022}<\mathrm{20}{x}!+\mathrm{22}{y}! \\ $$$${For}\:{y}>\mathrm{5}\:\:\:\:{xy}^{\mathrm{3}} +{xy}^{\mathrm{3}} +\mathrm{2022}<\mathrm{20}{x}!+\mathrm{22}{y}! \\ $$$${this}\:{means}\:{we}'{ve}\:{to}\:{search}\:{values}…
Question Number 171289 by mathlove last updated on 11/Jun/22 $$\left({x},{y}\right)\in{R}\:\:\:{x}^{\mathrm{2}} −{xy}−\mathrm{12}{y}^{\mathrm{2}} =\mathrm{0} \\ $$$$\frac{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{4}{y}^{\mathrm{2}} }{{xy}}=? \\ $$ Answered by mr W last updated on…
Question Number 40222 by byaw last updated on 17/Jul/18 $$\mathrm{please}\:\mathrm{help} \\ $$$$\mathrm{Kate}\:\mathrm{was}\:\mathrm{given}\:\mathrm{602}.\mathrm{00}\:\mathrm{dollas}\:\mathrm{for}\: \\ $$$$\mathrm{shopping}.\:\mathrm{She}\:\mathrm{spent}\:\frac{\mathrm{1}}{\mathrm{4}}\:\mathrm{on}\:\mathrm{chocolate} \\ $$$$\mathrm{and}\:\mathrm{later}\:\frac{\mathrm{2}}{\mathrm{3}}\:\mathrm{on}\:\mathrm{goods}.\:\mathrm{How}\:\mathrm{much} \\ $$$$\mathrm{money}\:\mathrm{was}\:\mathrm{left}? \\ $$ Answered by Joel578 last updated…
Question Number 171244 by mathlove last updated on 11/Jun/22 $$\frac{{x}}{{y}}+\frac{{y}}{{x}}=\frac{\mathrm{26}}{\mathrm{5}} \\ $$$$\frac{{x}+{y}}{{x}−{y}}=? \\ $$$$\frac{}{} \\ $$ Commented by infinityaction last updated on 11/Jun/22 $$\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}}…