Question Number 104294 by Anindita last updated on 20/Jul/20 $$\mathrm{1}.\:\:\frac{\mathrm{1}\frac{\mathrm{1}}{\mathrm{2}}+\mathrm{2}\frac{\mathrm{6}}{\mathrm{7}}}{\mathrm{2}\frac{\mathrm{2}}{\mathrm{3}}−\mathrm{3}\frac{\mathrm{4}}{\mathrm{5}}}=? \\ $$$$\mathrm{2}.\:\:\mathrm{4}×\Pi×\Pi=? \\ $$$$\mathrm{3}.\:\:\boldsymbol{\mathrm{Transfer}}\:\boldsymbol{\mathrm{into}}\:\boldsymbol{\mathrm{fractions}}: \\ $$$$\:\:\:\:\:\:\mathrm{5}.\overset{.} {\mathrm{8}}\overset{.} {\mathrm{9}},\:\mathrm{9}.\overset{.} {\mathrm{6}},\:\mathrm{78}.\mathrm{5}\overset{.} {\mathrm{7}}\overset{.} {\mathrm{8}} \\ $$ Answered by…
Question Number 104297 by Anindita last updated on 20/Jul/20 $$\frac{\mathrm{3}{a}^{\mathrm{2}} {b}^{\mathrm{3}} {c}}{\mathrm{5}{b}^{\mathrm{4}} {c}}+\frac{\mathrm{6}{xy}^{\mathrm{3}} {z}^{\mathrm{16}} }{\mathrm{10}{x}^{\mathrm{2}} {y}^{\mathrm{2}} {z}^{\mathrm{10}} }\:=\:? \\ $$$$\boldsymbol{\mathrm{Can}}\:\boldsymbol{\mathrm{you}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}? \\ $$ Answered by bemath…
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Question Number 104278 by Anindita last updated on 20/Jul/20 $${x}−\left(−\left(−{x}+\left(−{x}+{x}\right)\right)\right)=\:? \\ $$ Answered by bramlex last updated on 20/Jul/20 $${x}−\left(−\left(−{x}+\mathrm{0}\right)\right)={x}−\left(−\left(−{x}\right)\right) \\ $$$$={x}−\left({x}\right)=\mathrm{0} \\ $$ Terms…
Question Number 104270 by Study last updated on 20/Jul/20 $${sgn}\left(\mid{x}\mid\right)=? \\ $$ Answered by mr W last updated on 20/Jul/20 $${sgn}\left(\mid{x}\mid\right)=\mathrm{0},\:{if}\:{x}=\mathrm{0} \\ $$$${sgn}\left(\mid{x}\mid\right)=\mathrm{1},\:{if}\:{x}\neq\mathrm{0} \\ $$…
Question Number 104260 by Anindita last updated on 20/Jul/20 $$\mathrm{You}\:\mathrm{bought}\:\mathrm{3g}\:\mathrm{rice},\:\mathrm{5g}\:\mathrm{flour}\:\mathrm{in}\:\mathrm{a} \\ $$$$\mathrm{market}.\:\mathrm{At}\:\mathrm{first}\:\mathrm{you}\:\mathrm{had}\:\mathrm{500}\:\mathrm{rupees}. \\ $$$$\mathrm{Now}\:\mathrm{you}\:\mathrm{have}\:\mathrm{300}\:\mathrm{rupees}.\:\mathrm{How}\:\mathrm{much} \\ $$$$\mathrm{rupees}\:\mathrm{you}\:\mathrm{wasted}?\:\mathrm{Suppose}\:\mathrm{you} \\ $$$$\mathrm{distribute}\:\mathrm{the}\:\mathrm{300}\:\mathrm{rupees}\:\mathrm{among} \\ $$$$\mathrm{your}\:\mathrm{4}\:\mathrm{sons}.\:\mathrm{Now}\:\mathrm{how}\:\mathrm{much}\:\mathrm{rupees} \\ $$$$\mathrm{does}\:\mathrm{your}\:\mathrm{one}\:\mathrm{son}\:\mathrm{get}? \\ $$ Commented…
Question Number 104251 by Anindita last updated on 20/Jul/20 $$\mathrm{If}\:{x}=\mathrm{8}\:\mathrm{and}\:{y}=\mathrm{5}\:\mathrm{then}\:\mathrm{what}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{answer}\:\mathrm{of}\:\:\frac{{x}+{y}+\mathrm{6}}{{x}^{\mathrm{2}} −{y}^{\mathrm{3}} }\:? \\ $$ Answered by mathmax by abdo last updated on 20/Jul/20…
Question Number 104253 by Anindita last updated on 20/Jul/20 $$\mathrm{When}\:{a}\ast{b}=\:\frac{{a}+{b}}{{a}−{b}}\:\mathrm{then}\:\mathrm{what}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{answer}\:\mathrm{of}\:\mathrm{2}\ast\mathrm{3}×\mathrm{9}\ast\mathrm{10}\:? \\ $$ Commented by som(math1967) last updated on 20/Jul/20 $$\frac{\mathrm{2}+\mathrm{3}}{\mathrm{2}−\mathrm{3}}×\frac{\mathrm{9}+\mathrm{10}}{\mathrm{9}−\mathrm{10}}=\frac{\mathrm{5}}{−\mathrm{1}}×\frac{\mathrm{19}}{−\mathrm{1}}=\mathrm{95} \\ $$ Answered…
Question Number 104246 by Anindita last updated on 20/Jul/20 $$\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}\right)\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}\right)\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}}\right)….\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{99}}\right)\:=? \\ $$ Answered by mathmax by abdo last updated on 20/Jul/20 $$\mathrm{let}\:\mathrm{A}_{\mathrm{n}} =\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{3}}\right)\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{4}}\right)….\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{n}}\right)\:\Rightarrow\mathrm{A}_{\mathrm{n}} =\frac{\mathrm{2}}{\mathrm{3}}×\frac{\mathrm{3}}{\mathrm{4}}×\frac{\mathrm{4}}{\mathrm{5}}×…\frac{\mathrm{n}−\mathrm{2}}{\mathrm{n}−\mathrm{1}}×\frac{\mathrm{n}−\mathrm{1}}{\mathrm{n}} \\…
Question Number 104243 by M±th+et+s last updated on 20/Jul/20 $${prove}\:{that} \\ $$$$\pi=\mathrm{2}×\frac{\mathrm{2}}{\:\sqrt{\mathrm{2}}}×\frac{\mathrm{2}}{\:\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}}×\frac{\mathrm{2}}{\:\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}}}}}×….. \\ $$ Answered by OlafThorendsen last updated on 20/Jul/20 $$\mathrm{sin}{x}\:=\:\mathrm{2sin}\frac{{x}}{\mathrm{2}}\mathrm{cos}\frac{{x}}{\mathrm{2}} \\ $$$$\mathrm{sin}{x}\:=\:\mathrm{2}^{\mathrm{2}} \mathrm{sin}\frac{{x}}{\mathrm{4}}\mathrm{cos}\frac{{x}}{\mathrm{4}}\mathrm{cos}\frac{{x}}{\mathrm{2}}…