Question Number 168698 by mathlove last updated on 16/Apr/22 $$\mathrm{3}{f}\left({x}\right)+\mathrm{2}{f}\left(\frac{{x}+\mathrm{59}}{{x}−\mathrm{1}}\right)=\mathrm{10}{x}+\mathrm{30}\:{for}\:{all} \\ $$$${rael}\:\:{x}\cancel{=}\mathrm{1}\:{faind}\:{volue}\:{of} \\ $$$${f}\left(\mathrm{7}\right)=? \\ $$$$ \\ $$ Answered by Rasheed.Sindhi last updated on 16/Apr/22…
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Question Number 103151 by I want to learn more last updated on 13/Jul/20 $$. \\ $$ Commented by I want to learn more last updated…
Question Number 168672 by mathlove last updated on 15/Apr/22 $$\mathrm{2}^{{x}} ={y}^{\mathrm{2}} +\mathrm{7}\:\:\:\:\:\:\:\:\:{x},{y}\in{N} \\ $$$${x}=?\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{y}=? \\ $$ Commented by safojontoshtemirov last updated on 15/Apr/22 $${x}=\mathrm{3}\:\:\:{y}=\mathrm{1}\:\:\:\:{x}=\mathrm{7}\:\:\:\:{y}=\mathrm{11} \\…
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Question Number 37568 by math khazana by abdo last updated on 15/Jun/18 $${let}\:\alpha\:{and}\:\beta\:{the}\:{roots}\:{of}\:{the}\:{equation} \\ $$$${x}^{\mathrm{2}} \:−\mathrm{2}{mx}\:−\mathrm{1}\:=\mathrm{0}\:\:{find}\:{interms}\:{of}\:{the}\:{real}\:{m} \\ $$$${A}\:=\:\alpha^{\mathrm{2}} \:+\beta^{\mathrm{2}} \\ $$$${B}\:=\alpha^{\mathrm{3}} \:+\beta^{\mathrm{3}} \\ $$$${c}\:=\alpha^{\mathrm{4}} \:+\beta^{\mathrm{4}}…
Question Number 168642 by Shrinava last updated on 15/Apr/22 $$\mathrm{Let}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{be}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with} \\ $$$$\angle\mathrm{ABC}=\mathrm{60}°\:\:\mathrm{and}\:\:\angle\mathrm{ACB}=\mathrm{50}°. \\ $$$$\mathrm{IABI}=\mathrm{a}^{\mathrm{2}} −\mathrm{2}\:,\:\mathrm{IBCI}=\mathrm{a}\:\:\mathrm{in}\:\mathrm{this} \\ $$$$\mathrm{instance}\:,\:\mathrm{prove}\:\mathrm{that}\:\:\mathrm{IACI}=\sqrt{\mathrm{3}}. \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 103093 by mr W last updated on 12/Jul/20 $${solve}\:{for}\:{x},{y}\in\mathbb{N} \\ $$$$\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}=\frac{\mathrm{3}}{\mathrm{202}} \\ $$ Answered by 1549442205 last updated on 13/Jul/20 $$\mathrm{We}\:\mathrm{have}\:\frac{\mathrm{1}}{\mathrm{x}}+\frac{\mathrm{1}}{\mathrm{y}}=\frac{\mathrm{3}}{\mathrm{202}}\Leftrightarrow\frac{\mathrm{x}+\mathrm{y}}{\mathrm{xy}}=\frac{\mathrm{3}}{\mathrm{202}} \\ $$$$\Leftrightarrow\mathrm{3xy}=\mathrm{202}\left(\mathrm{x}+\mathrm{y}\right)\Leftrightarrow\mathrm{9xy}=\mathrm{3}.\mathrm{202}\left(\mathrm{x}+\mathrm{y}\right)…
Question Number 168606 by Shrinava last updated on 14/Apr/22 Commented by mr W last updated on 14/Apr/22 $$\left[{ABC}\right]={area}\:{of}\:\Delta{ABC}? \\ $$$${is}\:{I}_{{a}} \:{opposite}\:{to}\:{A}? \\ $$ Commented by…