Question Number 168461 by mathlove last updated on 11/Apr/22 $${y}=\left(\mathrm{sin}\:{x}+\mathrm{cos}\:{x}\right)^{\mathrm{2}} −\mathrm{1} \\ $$$${Minemum}\:{praice}\:{of}\left[\frac{\mathrm{3}\pi}{\mathrm{2}},\frac{\mathrm{7}\pi}{\mathrm{2}}\right] \\ $$ Commented by mr W last updated on 11/Apr/22 $${y}=\mathrm{sin}\:\mathrm{2}{x} \\…
Question Number 168436 by mathlove last updated on 10/Apr/22 $${y}=\left(\mathrm{sin}\:{x}+\mathrm{cos}\:{x}\right)^{\mathrm{2}} −\mathrm{1} \\ $$$${is}\:{any}\:{point}\:{minmum}\:{praice} \\ $$$${the}\:\left[\frac{\mathrm{3}\pi}{\mathrm{2}},\frac{\mathrm{7}\pi}{\mathrm{2}}\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168438 by mathlove last updated on 10/Apr/22 $${y}={sin}\frac{\mathrm{2}{x}}{\mathrm{3}}\:\:\:{function}\:{any} \\ $$$${point}\:{minemum}\:{praice} \\ $$$${the}\:\left[\pi,\mathrm{3}\pi\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168435 by mathlove last updated on 10/Apr/22 $${x}^{{x}+{y}} ={x} \\ $$$${y}^{{x}+{y}} ={xy}^{\mathrm{3}\:\:\:\:\:\:\:\:\:\overset{\left({x},{y}\right)=\left(?,?\right)} {\:}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168434 by mathlove last updated on 10/Apr/22 $$\mathrm{2}^{{x}} ×\mathrm{3}^{\frac{\mathrm{4}}{{x}}} =\mathrm{48} \\ $$$${x}=? \\ $$ Answered by nurtani last updated on 10/Apr/22 $$\mathrm{2}^{{x}} ×\mathrm{3}^{\frac{\mathrm{4}}{{x}}}…
Question Number 168424 by mathlove last updated on 10/Apr/22 $${f}\left(\mathrm{4}\right)=\mathrm{5}\:\:\:\:\:\:\:\:\:{f}\left(\mathrm{5}\right)=\mathrm{7} \\ $$$${g}\left(\mathrm{5}\right)=\mathrm{3}\:\:\:\:\:\:\:\:\:{g}\left(\mathrm{7}\right)=\mathrm{4} \\ $$$${f}\left({g}\left(\mathrm{5}\right)\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168411 by safojontoshtemirov last updated on 10/Apr/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 168402 by BagusSetyoWibowo last updated on 10/Apr/22 $$\mathrm{2}{x}^{\mathrm{3}} +\mathrm{9}{x}^{\mathrm{2}} +\mathrm{13}{x}+\mathrm{6}=\mathrm{0} \\ $$$${Solve}\:{the}\:{x},\:\left({Use}\:{Cubic}\:{Formula}!\right) \\ $$$${x}_{\mathrm{1}} =? \\ $$$${x}_{\mathrm{2}} =? \\ $$$${x}_{\mathrm{3}} =? \\ $$…
Question Number 37324 by behi83417@gmail.com last updated on 11/Jun/18 Commented by math khazana by abdo last updated on 12/Jun/18 $$\left.{b}\right)\:\frac{\sqrt{\mathrm{1}+{x}}}{\mathrm{1}+\sqrt{{x}}}={x}\:\Rightarrow\:\sqrt{\mathrm{1}+{x}}\:={x}\left(\mathrm{1}+\sqrt{{x}}\right)\:{with}\:{x}\geqslant\mathrm{0}{if}\:{x}\:{real} \\ $$$$\mathrm{1}+{x}\:={x}^{\mathrm{2}} \left(\mathrm{1}+\mathrm{2}\sqrt{{x}}\:+{x}\right)\:\Rightarrow\mathrm{1}+{x}={x}^{\mathrm{3}\:} +{x}^{\mathrm{2}} \:+\mathrm{2}{x}^{\mathrm{2}}…
Question Number 168335 by vbr last updated on 08/Apr/22 $$\frac{{x}}{\mathrm{2}}+\mathrm{4}\sqrt{{x}\:}+\mathrm{6}+\mathrm{3}+\mathrm{1}={x} \\ $$ Answered by Rasheed.Sindhi last updated on 08/Apr/22 $$\frac{{x}}{\mathrm{2}}+\mathrm{4}\sqrt{{x}\:}+\mathrm{10}={x} \\ $$$${x}+\mathrm{8}\sqrt{{x}}\:+\mathrm{20}=\mathrm{2}{x} \\ $$$$\mathrm{8}\sqrt{{x}}\:+\mathrm{20}={x} \\…