Question Number 98844 by I want to learn more last updated on 16/Jun/20 $$\mathrm{Please}\:\mathrm{explain}:\:\:\:\:\:\:\underset{\mathrm{1}\:\leqslant\:\boldsymbol{\mathrm{i}}\:<\:\boldsymbol{\mathrm{j}}\:\leqslant\:\boldsymbol{\mathrm{n}}} {\sum}\boldsymbol{\mathrm{ij}}\:\:\:\:=\:\:\:\underset{\boldsymbol{\mathrm{j}}\:\:=\:\:\mathrm{2}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\frac{\boldsymbol{\mathrm{j}}\left(\boldsymbol{\mathrm{j}}\:−\:\mathrm{1}\right)\boldsymbol{\mathrm{j}}}{\mathrm{2}} \\ $$$$\boldsymbol{\mathrm{I}}\:\mathrm{want}\:\mathrm{to}\:\mathrm{know}\:\mathrm{how}\:\mathrm{L}.\mathrm{H}.\mathrm{S}\:\:=\:\:\mathrm{R}.\mathrm{H}.\mathrm{S} \\ $$ Answered by mr W…
Question Number 33307 by abdo imad last updated on 14/Apr/18 $${let}\:{z}={x}+{iy}\:\:{with}\:{x}\neq\mathrm{0}\:{prove}?{that} \\ $$$$\mid\:\frac{{e}^{{z}} \:−\mathrm{1}}{{z}}\:\mid\leqslant\mid\:\frac{{e}^{{x}} \:−\mathrm{1}}{{x}}\:\mid \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 164372 by mathlove last updated on 16/Jan/22 Commented by mathlove last updated on 16/Jan/22 $${Domain}\:{f}\left({x}\right)=? \\ $$ Answered by mahdipoor last updated on…
Question Number 98818 by Algoritm last updated on 16/Jun/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 164341 by ajfour last updated on 16/Jan/22 $$\:\:{x}^{\mathrm{4}} ={x}^{\mathrm{2}} +{cx} \\ $$$$\left({x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} ={cx}+\frac{\mathrm{1}}{\mathrm{4}} \\ $$$${let}\:\:\:\:{x}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{2}}={t}\:\:\:\Rightarrow \\ $$$$\left({t}^{\mathrm{2}} −\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{2}} ={c}^{\mathrm{2}} \left({t}+\frac{\mathrm{1}}{\mathrm{2}}\right) \\…
Question Number 98796 by Lekhraj last updated on 16/Jun/20 Answered by MJS last updated on 16/Jun/20 $$−\frac{\mathrm{267}}{\mathrm{2}} \\ $$ Commented by Lekhraj last updated on…
Question Number 164331 by HongKing last updated on 16/Jan/22 Commented by mr W last updated on 16/Jan/22 $${see}\:{Q}\mathrm{163656} \\ $$$$\frac{{BC}}{{AD}}=\frac{{PB}^{\mathrm{2}} −{PC}^{\mathrm{2}} }{{PA}^{\mathrm{2}} −{PD}^{\mathrm{2}} }=\mathrm{1}\: \\…
Question Number 164312 by mathlove last updated on 16/Jan/22 Commented by mr W last updated on 16/Jan/22 $${one}\:{must}\:{see}:\:{x}=\mathrm{1},\:{y}=\mathrm{0} \\ $$ Commented by mathlove last updated…
Question Number 164315 by ajfour last updated on 16/Jan/22 Commented by ajfour last updated on 16/Jan/22 $${If}\:{the}\:{blue}\:{area}\:{is}\:\:\:{c}\:\:\:{units},\:{find}\:{p}. \\ $$ Commented by cortano1 last updated on…
Question Number 33240 by Tinkutara last updated on 13/Apr/18 Commented by rahul 19 last updated on 13/Apr/18 $$\left(\mathrm{2}\right)\:\left(−\mathrm{4},\mathrm{2}\right). \\ $$ Commented by Tinkutara last updated…