Question Number 32047 by rahul 19 last updated on 18/Mar/18 Commented by rahul 19 last updated on 20/Mar/18 $${pls}\:{help}…. \\ $$ Terms of Service Privacy…
Question Number 32049 by rahul 19 last updated on 18/Mar/18 $$\boldsymbol{{I}}{f}\:\mid\boldsymbol{{z}}−\mathrm{6}−\mathrm{8}\boldsymbol{{i}}\mid\leqslant\mathrm{4}\:{then}\:\boldsymbol{{M}}{inimum}\:{value} \\ $$$${of}\:\mid\boldsymbol{{z}}\mid\:{is}\: \\ $$$$\left.{A}\right)\:\mathrm{4}\: \\ $$$$\left.{B}\right)\:\mathrm{5} \\ $$$$\left.{C}\right)\:\mathrm{6} \\ $$$$\left.{D}\right)\:\mathrm{8}. \\ $$ Answered by…
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Question Number 97564 by Power last updated on 08/Jun/20 Answered by Rio Michael last updated on 09/Jun/20 $$\mathrm{Ones}\:\mathrm{our}\:\mathrm{teacher}\:\mathrm{put}\:\mathrm{this}\:\mathrm{on}\:\mathrm{the}\:\mathrm{board},\:\mathrm{we}\:\mathrm{puzzeled}\:\mathrm{even} \\ $$$$\mathrm{the}\:\mathrm{geniuses}\:\mathrm{of}\:\mathrm{our}\:\mathrm{class}\:\mathrm{tried}\:\mathrm{it}\:\mathrm{out}\:\mathrm{but}\:\mathrm{it}\:\mathrm{turned}\:\mathrm{out} \\ $$$$\mathrm{even}\:\mathrm{the}\:\mathrm{teacher}\:\mathrm{couldn}'\mathrm{t}\:\mathrm{find}\:\mathrm{a}\:\mathrm{particular}\:\mathrm{summation}\:\mathrm{formula} \\ $$$$\mathrm{which}\:\mathrm{described}\:\mathrm{this}\:\mathrm{series}\:\mathrm{even}\:\mathrm{to}\:\mathrm{an}\:\mathrm{approximate}.\:\mathrm{Some}\: \\…
Question Number 163100 by HongKing last updated on 03/Jan/22 Answered by mr W last updated on 04/Jan/22 Commented by mr W last updated on 04/Jan/22…
Question Number 163099 by HongKing last updated on 03/Jan/22 $$\mathrm{1}.\:\mathrm{u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:=\:\boldsymbol{\mathrm{x}}\:+\:\boldsymbol{\mathrm{y}} \\ $$$$\mathrm{2}.\:\boldsymbol{\mathrm{u}}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:=\:\boldsymbol{\mathrm{x}}\:-\:\boldsymbol{\mathrm{y}} \\ $$ Answered by mr W last updated on 04/Jan/22 $$\left.\mathrm{1}\right)…
Question Number 163098 by amin96 last updated on 03/Jan/22 Answered by Rasheed.Sindhi last updated on 03/Jan/22 $${f}\left({x}+{y}\right)={f}\left({x}\right)×{f}\left({y}\right)\:,\:{f}^{\:'} \left(\mathrm{0}\right)=\mathrm{2} \\ $$$${f}\:'\left({x}\right)=? \\ $$$$\: \\ $$$${f}\left({x}+{y}\right)={f}\left({x}\right)×{f}\left({y}\right) \\…
Question Number 163082 by HongKing last updated on 03/Jan/22 $$\mathrm{1}.\:\mathrm{u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:-\:\mathrm{2u}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{3u}_{\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{y}}} \:-\:\mathrm{u}_{\boldsymbol{\mathrm{x}}} \:=\:\mathrm{0} \\ $$$$\mathrm{2}.\:\mathrm{xu}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{x}}} \:+\:\mathrm{2xu}_{\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{3u}_{\boldsymbol{\mathrm{y}}\:\boldsymbol{\mathrm{y}}} \:+\:\mathrm{u}_{\boldsymbol{\mathrm{y}}} \:=\:\mathrm{0} \\ $$ Commented by mahdipoor…
Question Number 32002 by rahul 19 last updated on 18/Mar/18 $${If}\:\:\boldsymbol{{z}}^{\mathrm{3}} =\bar {\boldsymbol{{z}}}\:{prove}\: \\ $$$${then}\:\mid\boldsymbol{{z}}\mid=\mathrm{1}. \\ $$ Answered by Tinkutara last updated on 18/Mar/18 $${z}^{\mathrm{3}}…
Question Number 163075 by tounghoungko last updated on 03/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{2}} −\mathrm{1}}\:=\:{x}+\sqrt{\frac{\mathrm{6}}{{x}}} \\ $$ Answered by Rasheed.Sindhi last updated on 03/Jan/22 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\mathrm{3}} +\mathrm{1}}{{x}^{\mathrm{2}} −\mathrm{1}}\:=\:{x}+\sqrt{\frac{\mathrm{6}}{{x}}} \\…