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Category: Algebra

54-x-1-3-54-x-1-3-18-1-3-x-

Question Number 95920 by bobhans last updated on 28/May/20 $$\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}+\sqrt{\mathrm{x}}}\:+\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}−\sqrt{\mathrm{x}}}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{18}}\: \\ $$$$\mathrm{x}\:=\:?\: \\ $$ Answered by i jagooll last updated on 28/May/20 $$\mathrm{let}\:\mathrm{a}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}+\sqrt{\mathrm{x}}}\:,\:\mathrm{b}\:=\:\sqrt[{\mathrm{3}\:\:}]{\mathrm{54}−\sqrt{\mathrm{x}}}\: \\ $$$$\mathrm{a}+\mathrm{b}\:=\:\frac{\mathrm{a}^{\mathrm{3}}…

if-x-y-z-gt-0-such-that-x-y-z-3-and-0-then-prove-that-x-y-3-y-2-y-z-3-z-2-z-x-3-x-2-3-1-

Question Number 161433 by HongKing last updated on 17/Dec/21 $$\mathrm{if}\:\:\mathrm{x};\mathrm{y};\mathrm{z}>\mathrm{0}\:\:\mathrm{such}\:\mathrm{that}\:\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{3} \\ $$$$\mathrm{and}\:\:\boldsymbol{\lambda}\geqslant\mathrm{0}\:\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\frac{\mathrm{x}}{\mathrm{y}^{\mathrm{3}} +\lambda\mathrm{y}^{\mathrm{2}} }\:+\:\frac{\mathrm{y}}{\mathrm{z}^{\mathrm{3}} +\lambda\mathrm{z}^{\mathrm{2}} }\:+\:\frac{\mathrm{z}}{\mathrm{x}^{\mathrm{3}} +\lambda\mathrm{x}^{\mathrm{2}} }\:\geqslant\:\frac{\mathrm{3}}{\lambda+\mathrm{1}} \\ $$ Terms of Service…

3x-7-2-2-x-3-3-x-2-x-3-find-the-solution-

Question Number 95843 by john santu last updated on 28/May/20 $$\frac{\left(\sqrt{\mathrm{3x}−\mathrm{7}}\right)^{\mathrm{2}} −\mathrm{2}}{\mathrm{x}−\mathrm{3}}\:\leqslant\:\frac{\mathrm{3}−\left(\sqrt{\mathrm{x}}\right)^{\mathrm{2}} }{\mathrm{x}−\mathrm{3}}\: \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\: \\ $$ Answered by john santu last updated on 28/May/20…

similar-question-reposted-if-a-3-b-b-3-c-c-3-a-with-a-b-c-and-a-b-c-R-find-abc-2-

Question Number 161366 by mr W last updated on 17/Dec/21 $$\left[{similar}\:{question}\:{reposted}\right] \\ $$$${if}\:{a}+\frac{\mathrm{3}}{{b}}={b}+\frac{\mathrm{3}}{{c}}={c}+\frac{\mathrm{3}}{{a}}\:{with}\:{a}\neq{b}\neq{c} \\ $$$${and}\:{a},{b},{c}\:\in\:\mathbb{R}.\:{find}\:\left({abc}\right)^{\mathrm{2}} =? \\ $$ Answered by 1549442205PVT last updated on 18/Dec/21…