Question Number 19250 by Tinkutara last updated on 07/Aug/17 $$\mathrm{Why}\:\mathrm{arg}\left({z}\right)\:+\:\mathrm{arg}\left(\bar {{z}}\right)\:=\:\mathrm{2}{k}\pi,\:{k}\:\in\:{Z}? \\ $$$$\mathrm{Shouldn}'\mathrm{t}\:\mathrm{it}\:\mathrm{be}\:\boldsymbol{\mathrm{always}}\:\mathrm{0}? \\ $$ Commented by ajfour last updated on 07/Aug/17 $$\mathrm{yes},\:\mathrm{so}\:\mathrm{do}\:\mathrm{i}\:\mathrm{think}. \\ $$$$\mathrm{but}\:\mathrm{if}\:{z}=−\mathrm{1}\:?!…
Question Number 150326 by mathdanisur last updated on 11/Aug/21 $$\mathrm{Find}\:\:\boldsymbol{\mathrm{ax}}^{\mathrm{5}} +\boldsymbol{\mathrm{by}}^{\mathrm{5}} \:\:\mathrm{if}\:\mathrm{the}\:\mathrm{real}\:\mathrm{numbers} \\ $$$$\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}},\boldsymbol{\mathrm{x}}\:\:\mathrm{and}\:\:\boldsymbol{\mathrm{y}}\:\:\mathrm{satisf}\:\mathrm{the}\:\mathrm{equations}: \\ $$$$\mathrm{ax}\:+\:\mathrm{by}\:=\:\mathrm{3} \\ $$$$\mathrm{ax}^{\mathrm{2}} \:+\:\mathrm{by}^{\mathrm{2}} \:=\:\mathrm{7} \\ $$$$\mathrm{ax}^{\mathrm{3}} \:+\:\mathrm{by}^{\mathrm{3}} \:=\:\mathrm{16} \\…
Question Number 84785 by john santu last updated on 16/Mar/20 $$\mathrm{at}\:\mathrm{what}\:\mathrm{time}\:\mathrm{is}\:\mathrm{the}\:\mathrm{short}\:\mathrm{clock}\: \\ $$$$\mathrm{and}\:\mathrm{long}\:\mathrm{hour}\:\mathrm{hand}\:\mathrm{form}\:\mathrm{an}\: \\ $$$$\mathrm{angle}\:\mathrm{of}\:\mathrm{180}\:\mathrm{degrees}? \\ $$ Commented by mr W last updated on 16/Mar/20…
Question Number 19247 by 99 last updated on 07/Aug/17 Commented by NEC last updated on 08/Aug/17 $${please}\:{type}\:{it}\:{so}\:{we}\:{can}\:{see}\:{it} \\ $$$${clearly}. \\ $$$$ \\ $$ Commented by…
Question Number 84782 by mr W last updated on 16/Mar/20 $${Find}\:{the}\:{last}\:{three}\:{digits}\:{of}\:\mathrm{2019}^{\mathrm{2019}} . \\ $$ Commented by jagoll last updated on 16/Mar/20 $$\mathrm{19}^{\mathrm{2019}} \:=\:\left(\mathrm{18}+\mathrm{1}\right)^{\mathrm{2019}} \\ $$$$=\:\underset{\mathrm{i}=\mathrm{1}}…
Question Number 19245 by Tinkutara last updated on 07/Aug/17 $$\mathrm{Let}\:{f}\left({x}\right)\:\mathrm{be}\:\mathrm{a}\:\mathrm{quadratic}\:\mathrm{polynomial} \\ $$$$\mathrm{with}\:\mathrm{integer}\:\mathrm{coefficients}\:\mathrm{such}\:\mathrm{that}\:{f}\left(\mathrm{0}\right) \\ $$$$\mathrm{and}\:{f}\left(\mathrm{1}\right)\:\mathrm{are}\:\mathrm{odd}\:\mathrm{integers}.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\mathrm{the}\:\mathrm{equation}\:{f}\left({x}\right)\:=\:\mathrm{0}\:\mathrm{does}\:\mathrm{not}\:\mathrm{have}\:\mathrm{an} \\ $$$$\mathrm{integer}\:\mathrm{solution}. \\ $$ Commented by RasheedSindhi last updated…
Question Number 84783 by Power last updated on 16/Mar/20 Commented by Power last updated on 16/Mar/20 $$\mathrm{k}=\mathrm{3} \\ $$ Commented by Tony Lin last updated…
Question Number 19236 by chernoaguero@gmail.com last updated on 07/Aug/17 Answered by ,25>( last updated on 07/Aug/17 $${x}\:=\:\mathrm{2}\:\mathrm{since}\:\mathrm{2}^{\mathrm{2}} \:+\:\mathrm{3}^{\mathrm{2}} \:=\:\mathrm{13}. \\ $$ Commented by chernoaguero@gmail.com last…
Question Number 84770 by jagoll last updated on 16/Mar/20 $$\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{30}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{x}}+\frac{\mathrm{1}}{\mathrm{y}}\:=\:\mathrm{2}\: \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{x}\:\&\:\mathrm{y}\:? \\ $$ Commented by Tony Lin last updated on…
Question Number 150296 by mathdanisur last updated on 10/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com