Question Number 19171 by gourav~ last updated on 06/Aug/17 $${log}_{\sqrt{\mathrm{2}}} \:\sqrt{\mathrm{2}\sqrt{\mathrm{2}\sqrt{\mathrm{2}\sqrt{\mathrm{2}\:\:\:\:}}}} \\ $$ Commented by gourav~ last updated on 06/Aug/17 $${find}\:{value} \\ $$ Answered by…
Question Number 150231 by Lekhraj last updated on 10/Aug/21 Answered by Ar Brandon last updated on 10/Aug/21 $${f}\left({x}\right)=\frac{\mathrm{1}}{\mathrm{3}^{{x}} +\sqrt{\mathrm{3}}} \\ $$$$\Rightarrow{f}\left(\mathrm{1}−{x}\right)=\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{1}−{x}} +\sqrt{\mathrm{3}}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{3}^{{x}} }{\mathrm{3}+\mathrm{3}^{{x}}…
Question Number 19135 by gourav~ last updated on 05/Aug/17 $${solve}\:{for}\:{x}: \\ $$$$\mathrm{2}^{\mid{x}+\mathrm{2}\mid} −\mid\mathrm{2}^{{x}+\mathrm{1}} −\mathrm{1}\mid=\mathrm{2}^{{x}+\mathrm{1}} +\mathrm{1} \\ $$ Answered by ajfour last updated on 05/Aug/17 $$\mathrm{x}+\mathrm{2}\geqslant\mathrm{0}\:\:\Rightarrow\:\:\mathrm{x}\geqslant−\mathrm{2}…
Question Number 19123 by 433 last updated on 05/Aug/17 $$\begin{cases}{\mathrm{xf}\left(\mathrm{x}\right)−\mathrm{g}\left(\mathrm{x}\right)+\mathrm{h}\left(\mathrm{x}\right)=\mathrm{2x}+\mathrm{1}}\\{\mathrm{f}\left(\mathrm{x}\right)−\left(\mathrm{2x}−\mathrm{2}\right)\mathrm{g}\left(\mathrm{x}\right)−\mathrm{3h}\left(\mathrm{x}\right)=\mathrm{x}}\\{\mathrm{ln}\:\left(\mathrm{x}\right)\mathrm{f}\left(\mathrm{x}\right)−\left(\mathrm{x}−\mathrm{3}\right)\mathrm{h}\left(\mathrm{x}\right)=\mathrm{1}}\end{cases} \\ $$$$\mathrm{Find}\:\mathrm{f}\left(\mathrm{x}\right),\mathrm{g}\left(\mathrm{x}\right),\mathrm{h}\left(\mathrm{x}\right) \\ $$ Answered by ajfour last updated on 05/Aug/17 $$\mathrm{x}\left(\mathrm{2x}−\mathrm{2}\right)\mathrm{f}−\left(\mathrm{2x}−\mathrm{2}\right)\mathrm{g}+\left(\mathrm{2x}−\mathrm{2}\right)\mathrm{h}=\left(\mathrm{2x}−\mathrm{2}\right)\left(\mathrm{2x}+\mathrm{1}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{f}−\left(\mathrm{2x}−\mathrm{2}\right)\mathrm{g}−\mathrm{3h}=\mathrm{x} \\…
Question Number 150199 by mathdanisur last updated on 10/Aug/21 Commented by Rasheed.Sindhi last updated on 10/Aug/21 $$\mathrm{Is}\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\pi?\:\mathrm{Are}\:\mathrm{x},\mathrm{y}\:\&\:\mathrm{z}\:\mathrm{the}\:\mathrm{angles} \\ $$$$\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}? \\ $$ Terms of Service Privacy…
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Question Number 150189 by mathdanisur last updated on 10/Aug/21 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}: \\ $$$$\left(\mathrm{x}\:-\:\mathrm{3}\right)\:\sqrt{\mathrm{x}^{\mathrm{2}} \:-\:\mathrm{x}\:−\:\mathrm{2}}\:=\:\mathrm{0} \\ $$ Commented by Skabetix last updated on 10/Aug/21 $${x}=\mathrm{3}\:{or}\:{x}=\mathrm{2}\:{or}\:{x}=−\mathrm{1} \\ $$…
Question Number 150191 by mathdanisur last updated on 10/Aug/21 $$\begin{cases}{\mathrm{x}\:-\:\sqrt{\mathrm{y}}\:=\:\mathrm{7}}\\{\mathrm{y}\:+\:\sqrt{\mathrm{x}}\:=\:\mathrm{7}}\end{cases}\:\:\:\Rightarrow\:\:\mathrm{xy}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 10/Aug/21 $$\begin{cases}{\mathrm{x}\:-\:\underset{\mathrm{v}} {\underbrace{\sqrt{\mathrm{y}}}}\:=\:\mathrm{7}}\\{\mathrm{y}\:+\:\underset{\mathrm{u}} {\underbrace{\sqrt{\mathrm{x}}}}\:=\:\mathrm{7}}\end{cases}\:\:\:\Rightarrow\:\:\mathrm{xy}\:=\:? \\ $$$$\mathrm{u}^{\mathrm{2}} −\mathrm{v}=\mathrm{7}\:\wedge\:\mathrm{v}^{\mathrm{2}}…
Question Number 150187 by mathdanisur last updated on 10/Aug/21 $$\mathrm{If}\:\:\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{2x}^{\mathrm{2}} \:+\:\mathrm{5}\:\:\Rightarrow\:\:\mathrm{f}^{\:−\mathrm{1}} \left(\mathrm{2}\right)\:=\:? \\ $$ Commented by amin96 last updated on 10/Aug/21 $$\mathrm{2}{x}^{\mathrm{2}} +\mathrm{5}=\mathrm{2}\:\:\Rightarrow\:\:\:{x}=\pm\frac{\mathrm{3}{i}}{\:\sqrt{\mathrm{2}}}\:\:\: \\ $$$${f}\left(\pm\frac{\mathrm{3}{i}}{\:\sqrt{\mathrm{2}}}\right)=\mathrm{2}\:\:\:\:\Rightarrow\:\:{f}^{−\mathrm{1}}…
Question Number 150181 by liberty last updated on 10/Aug/21 $$\:\left(\mathrm{x}−\mathrm{6}\right)^{\mathrm{3}} +\left(\mathrm{x}−\mathrm{5}\right)^{\mathrm{3}} +\left(\mathrm{x}−\mathrm{4}\right)^{\mathrm{3}} =\mathrm{3}\left(\mathrm{x}−\mathrm{6}\right)\left(\mathrm{x}−\mathrm{5}\right)\left(\mathrm{x}−\mathrm{4}\right) \\ $$$$\mathrm{x}=? \\ $$ Answered by Rasheed.Sindhi last updated on 13/Aug/21 $$\:\left(\mathrm{x}−\mathrm{6}\right)^{\mathrm{3}}…