Question Number 143832 by mathdanisur last updated on 18/Jun/21 $${x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \:=\:\left(\frac{\mathrm{56}}{\mathrm{13}}\right)^{\mathrm{2}} \:{and}\:\:{x}\:+\:\frac{\mathrm{5}{y}}{\mathrm{12}}\:=\:\frac{\mathrm{56}}{\mathrm{12}} \\ $$$${find}\:\:{x}+{y}=? \\ $$ Answered by MJS_new last updated on 18/Jun/21 $${x}^{\mathrm{2}}…
Solve-simultaneously-2x-y-z-8-equation-i-x-2-y-2-2z-2-14-equation-ii-3x-3-4y-3-z-3-195-equation-iii-
Question Number 12763 by tawa last updated on 30/Apr/17 $$\mathrm{Solve}\:\mathrm{simultaneously} \\ $$$$\mathrm{2x}\:+\:\mathrm{y}\:−\:\mathrm{z}\:=\:\mathrm{8}\:\:\:\:\:\:\:\:………..\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{2z}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:\:\:\:……….\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{3x}^{\mathrm{3}} \:+\:\mathrm{4y}^{\mathrm{3}} \:+\:\mathrm{z}^{\mathrm{3}} \:=\:\mathrm{195}\:\:\:\:\:\:\:\:\:………..\:\mathrm{equation}\:\left(\mathrm{iii}\right) \\ $$ Terms…
Question Number 143822 by ajfour last updated on 18/Jun/21 $$\:{x}^{\mathrm{4}} +{ax}^{\mathrm{2}} +{bx}+{c}=\mathrm{0} \\ $$$${let}\:\:{x}=\frac{{t}}{{s}} \\ $$$$\Rightarrow\:{t}^{\mathrm{4}} +{as}^{\mathrm{2}} {t}^{\mathrm{2}} +{bs}^{\mathrm{3}} {t}+{cs}^{\mathrm{4}} =\mathrm{0} \\ $$$${let}\:{t}={p}+{h}\:\:\Rightarrow \\ $$$${p}^{\mathrm{4}}…
Question Number 143814 by mathdanisur last updated on 18/Jun/21 $$\forall{a};{b};{c}\in\mathbb{R}\:,\:{find}\:{all}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:,\:{such}\:{that} \\ $$$${f}\left({a}\right){f}\left({bc}\right)+\mathrm{9}\leqslant{f}\left({ab}\right)+\mathrm{5}{f}\left({ac}\right) \\ $$ Answered by Olaf_Thorendsen last updated on 18/Jun/21 $${f}\left({a}\right){f}\left({bc}\right)+\mathrm{9}\:\leqslant\:{f}\left({ab}\right)+\mathrm{5}{f}\left({ac}\right) \\ $$$$ \\…
Question Number 143769 by bemath last updated on 18/Jun/21 Answered by TheHoneyCat last updated on 18/Jun/21 $$\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{6}}+\frac{\mathrm{1}}{\mathrm{12}}+\frac{\mathrm{1}}{\mathrm{20}}+\frac{\mathrm{1}}{\mathrm{9900}}=\frac{\mathrm{7921}}{\mathrm{990}}\approx\mathrm{0}.\mathrm{8001010101} \\ $$$$ \\ $$$$\mathrm{IF}\:''+…+'',\:\mathrm{in}\:\mathrm{your}\:\mathrm{question},\:\mathrm{is}\:\mathrm{a}\:\mathrm{finite}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{real}\:\mathrm{numbers}:\:\left(\mathrm{1}\right) \\ $$$$\frac{\mathrm{9}}{\mathrm{100}}=\mathrm{0}.\mathrm{09}<\mathrm{0}.\mathrm{8}\:\Rightarrow\:\left(\mathrm{A}\right)\:\mathrm{is}\:\mathrm{false} \\ $$$$\frac{\mathrm{19}}{\mathrm{100}}=\mathrm{0}.\mathrm{19}<\mathrm{0}.\mathrm{8}\:\Rightarrow\:\left(\mathrm{C}\right)\:\mathrm{is}\:\mathrm{false}…
Question Number 143774 by TheHoneyCat last updated on 18/Jun/21 $$\mathrm{Is}\:\mathrm{this}\:\mathrm{statement}\:{true}\:\mathrm{or}\:\mathrm{not}? \\ $$$$\exists\:\mathrm{A}\in\mathscr{M}_{\mathrm{3}} \left(\mathbb{R}\right)\:\mid\:\mathrm{tr}\left(\mathrm{A}\right)=\mathrm{0}\:\mathrm{and}\:\mathrm{A}^{\mathrm{2}} +^{{t}} \mathrm{A}=\mathrm{I}_{\mathrm{3}} \\ $$ Commented by TheHoneyCat last updated on 18/Jun/21 Oh, I actually found the answer. �� sorry. Should I send it?…
Question Number 12698 by frank ntulah last updated on 29/Apr/17 $$\mathrm{Given}\:\:\:\mathrm{A}^{\left(−\mathrm{1}\right)} =\begin{bmatrix}{\mathrm{0}.\mathrm{5}\:\:\:\:\:\:\mathrm{3}}\\{\mathrm{4}\:\:\:\:\:\:\:\:\:\:\mathrm{2}}\end{bmatrix} \\ $$$$\mathrm{find}\:\left(\mathrm{A}^{\mathrm{2}} \right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 78233 by jagoll last updated on 15/Jan/20 $${given}\:\mathrm{5}{x}+\mathrm{22}{y}=\mathrm{18} \\ $$$${find}\:{for}\:{x},{y}\:{integer} \\ $$ Commented by mr W last updated on 15/Jan/20 $${x}=−\mathrm{22}{k}+\mathrm{8} \\ $$$${y}=\mathrm{5}{k}−\mathrm{1}…
Question Number 12682 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 28/Apr/17 Answered by mrW1 last updated on 29/Apr/17 $${let}\:{u}={x}+{y} \\ $$$${let}\:{v}={xy} \\ $$$$ \\ $$$$\left({x}+{y}\right)^{\mathrm{2}} ={x}^{\mathrm{2}} +{y}^{\mathrm{2}}…
Question Number 12684 by tawa last updated on 29/Apr/17 Answered by mrW1 last updated on 29/Apr/17 $${p}=\sqrt{{x}} \\ $$$${q}=\sqrt{{y}} \\ $$$${u}={p}+{q} \\ $$$${v}={pq} \\ $$$$…