Question Number 209598 by peter frank last updated on 16/Jul/24 Answered by Frix last updated on 16/Jul/24 $${a}:{b}=\mathrm{3}:\mathrm{5} \\ $$$${b}:{c}=\mathrm{2}:\mathrm{4}=\mathrm{5}:\mathrm{10} \\ $$$${a}:{b}:{c}=\mathrm{3}:\mathrm{5}:\mathrm{10} \\ $$ Answered…
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Question Number 209602 by peter frank last updated on 16/Jul/24 Answered by som(math1967) last updated on 16/Jul/24 $$\:{let}\:{number}={x} \\ $$$$\:\frac{\mathrm{120}{x}}{\mathrm{100}}\:−\frac{\mathrm{85}{x}}{\mathrm{100}}=\mathrm{14} \\ $$$$\:\frac{\mathrm{35}{x}}{\mathrm{100}}=\mathrm{14} \\ $$$$\Rightarrow{x}=\frac{\mathrm{14}×\mathrm{100}}{\mathrm{35}}=\mathrm{40} \\…
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Question Number 209453 by peter frank last updated on 10/Jul/24 Commented by peter frank last updated on 10/Jul/24 $$\mathrm{help}\:\mathrm{B} \\ $$ Answered by mr W…
Question Number 209452 by peter frank last updated on 10/Jul/24 Answered by Ghisom last updated on 10/Jul/24 $$\mathrm{12}\:\mathrm{units} \\ $$$$−\mathrm{4}\:\mathrm{units}\:\left(\mathrm{12}/\mathrm{3}\right)\:\mathrm{for}\:\mathrm{sugar}\:=\:\mathrm{8}\:\mathrm{units} \\ $$$$−\mathrm{2}\:\mathrm{units}\:\left(\mathrm{8}/\mathrm{4}\right)\:\mathrm{for}\:\mathrm{soap}\:=\:\mathrm{6}\:\mathrm{units} \\ $$$$\mathrm{6}\:\mathrm{units}\:=\:\mathrm{6000} \\…
Question Number 209342 by essaad last updated on 07/Jul/24 Answered by Berbere last updated on 07/Jul/24 $${U}_{{n}+\mathrm{1}} ={f}\left({U}_{{n}} \right) \\ $$$${x}\overset{{f}} {\rightarrow}\frac{{x}}{\mathrm{2}}+\frac{{x}^{\mathrm{2}} }{\mathrm{4}};{f}\:{increase} \\ $$$${f}\left(\left[\mathrm{0},\mathrm{1}\right]\right)=\left[\mathrm{0},\frac{\mathrm{3}}{\mathrm{4}}\right]\subset\left[\mathrm{0},\mathrm{1}\right]…
Question Number 209166 by Tawa11 last updated on 02/Jul/24 Answered by mr W last updated on 02/Jul/24 $$\left({a}\right) \\ $$$${p}=\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{3}} =\mathrm{0}.\mathrm{42} \\ $$$$\left({b}\right) \\ $$$${p}={C}_{\mathrm{2}}…
Question Number 209128 by Spillover last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 $${The}\:{length}\:{of}\:{the}\:{diagonal}\:{of}\:{the}\:{square}=\mathrm{2}{r} \\ $$$$\Rightarrow{s}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow\mathrm{2}{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow{s}^{\mathrm{2}} =\mathrm{2}{r}^{\mathrm{2}}…
Question Number 209167 by lmcp1203 last updated on 02/Jul/24 $${please}\:{convert}\:\:\mathrm{2531}_{\left(\mathrm{5000}\right)\:} {to}\:\:{base}\:\mathrm{5002}.\:\:{thanks}.\:\: \\ $$ Answered by mr W last updated on 03/Jul/24 $$\mathrm{2531}_{\left(\mathrm{5000}\right)} =\mathrm{2}×\mathrm{5000}^{\mathrm{3}} +\mathrm{5}×\mathrm{5000}^{\mathrm{2}} +\mathrm{3}×\mathrm{5000}+\mathrm{1}…